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VICPhysicsSyllabus dot point

What holds atomic nuclei together and why do some decay?

Describe the structure of atomic nuclei, the strong nuclear force, and the modes of radioactive decay (alpha, beta-minus, beta-plus, gamma), and write balanced nuclear equations

A focused answer to the VCE Physics Unit 1 dot point on nuclear structure and decay. Describes the strong nuclear force, the neutron-proton ratio for stability, and the four classical decay modes ($\alpha$, $\beta^-$, $\beta^+$, $\gamma$). Works the VCAA SAC-style balanced-equation problem.

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What this dot point is asking

VCAA wants you to describe the nucleus (protons, neutrons, the strong force, stability), identify the four classical decay modes, and write balanced nuclear equations that conserve mass number and atomic number.

The nucleus

Atomic nuclei contain protons (ZZ) and neutrons (NN), together called nucleons. The mass number A=Z+NA = Z + N. Notation: ZAX^A_Z X where XX is the chemical symbol.

The strong nuclear force binds nucleons. It is short-range (about 11 fm), attractive, and stronger than the electromagnetic repulsion between protons over very short distances.

Stability

Stable nuclei occupy a narrow "valley of stability" on a NN vs ZZ chart. For light nuclei (Z<20Z < 20), stable isotopes have Nβ‰ˆZN \approx Z. For heavier nuclei, more neutrons are needed to dilute the proton-proton repulsion: stable isotopes have N/Zβ‰ˆ1.5N/Z \approx 1.5 near uranium.

Unstable nuclei decay toward the valley of stability through one or more decay events.

Alpha decay

The nucleus emits an alpha particle (24^4_2He). Common for heavy nuclei (A>200A > 200).

ZAX→ Zβˆ’2Aβˆ’4Y+ 24He^A_Z X \to \,^{A-4}_{Z-2}Y + \,^4_2\text{He}

Alpha particles are highly ionising but have low penetration (stopped by paper).

Beta-minus decay

A neutron decays into a proton plus an electron plus an electron antineutrino. The electron is emitted as the beta particle.

ZAX→ Z+1AY+β€‰βˆ’10e+Ξ½Λ‰e^A_Z X \to \,^A_{Z+1}Y + \,^0_{-1}e + \bar{\nu}_e

Common for neutron-rich nuclei. The antineutrino carries away part of the kinetic energy, producing the continuous beta energy spectrum.

Beta-plus decay

A proton decays into a neutron plus a positron plus an electron neutrino. Common for proton-rich nuclei.

ZAX→ Zβˆ’1AY+ +10e+Ξ½e^A_Z X \to \,^A_{Z-1}Y + \,^0_{+1}e + \nu_e

The positron annihilates with an electron, producing two 0.5110.511 MeV gamma photons in opposite directions. This is the basis of PET imaging.

Gamma emission

A nucleus in an excited state drops to a lower state by emitting a gamma photon. AA and ZZ are unchanged.

ZAYβˆ—β†’β€‰ZAY+Ξ³^A_Z Y^* \to \,^A_Z Y + \gamma

Often follows alpha or beta decay (the daughter is left in an excited state).

Conservation in nuclear equations

Always conserve:

  • Mass number AA (total nucleons).
  • Atomic number ZZ (total charge).
  • Lepton number (electron + neutrino vs positron + antineutrino).

Energy, momentum and angular momentum are also conserved, but VCE Year 11 questions focus on AA and ZZ.

VCAA exam style

Year 11 SAC tasks include:

  • Identifying the decay mode from a parent and daughter pair.
  • Writing balanced equations.
  • Identifying stable vs unstable isotopes from a chart of nuclides.

Common traps

Wrong ZZ direction in beta decay. Beta-minus increases ZZ (extra proton). Beta-plus decreases ZZ.

Treating gamma emission as changing the element. Gamma keeps both AA and ZZ unchanged.

Forgetting the (anti)neutrino. For full marks, include it. The antineutrino in beta-minus accompanies the electron; the neutrino in beta-plus accompanies the positron.

In one sentence

Atomic nuclei contain protons and neutrons bound by the short-range strong force, with stability determined by the neutron-to-proton ratio; unstable nuclei decay by alpha (βˆ’4A-4 A, βˆ’2Z-2 Z), beta-minus (+1Z+1 Z, neutron β†’\to proton plus electron plus antineutrino), beta-plus (βˆ’1Z-1 Z, proton β†’\to neutron plus positron plus neutrino) or gamma (no AA/ZZ change) emission, and every decay equation must conserve mass number and atomic number.

Past exam questions, worked

Real questions from past VCAA papers on this dot point, with our answer explainer.

Year 11 SAC4 marksCarbon-14 ($^{14}_6$C) undergoes beta-minus decay. (a) Write the balanced equation. (b) Identify the daughter nucleus and explain the conservation laws applied.
Show worked answer β†’

(a) Balanced equation.

614Cβ†’714N+βˆ’10e+Ξ½Λ‰e^{14}_{6}\text{C} \to ^{14}_{7}\text{N} + ^0_{-1}e + \bar{\nu}_e

(b) Daughter and conservation.

Daughter nucleus: nitrogen-14.

Conservation: mass number AA (14=14+014 = 14 + 0) and atomic number ZZ (6=7+(βˆ’1)6 = 7 + (-1)) are both conserved. Charge is conserved (the antineutrino is neutral). Energy and momentum are conserved (shared between the beta particle and the antineutrino, explaining the continuous beta energy spectrum).

Markers reward conservation of AA and ZZ in the equation, the daughter named explicitly, and inclusion of the antineutrino.

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