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What is the structure of the atomic nucleus, and how does it produce energy through radioactivity and nuclear reactions?

Atomic nucleus structure (protons, neutrons), isotopes, types of radioactive decay (alpha, beta, gamma), nuclear stability, half-life, fission and fusion, and applications including nuclear power

A focused answer to the VCE Physics Unit 1 key knowledge point on nuclear physics. Atomic structure (Z, N, A), alpha, beta and gamma decay, half-life N=N0(1/2)t/T1/2N = N_0 (1/2)^{t/T_{1/2}}, nuclear stability, fission, fusion, and applications in nuclear power and medicine.

Generated by Claude Opus 4.810 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. Atomic nucleus
  3. Nuclear forces
  4. Radioactive decay
  5. Conservation laws
  6. Half-life
  7. Fission
  8. Fusion
  9. Applications
  10. Examples in context
  11. Try this

What this dot point is asking

VCAA wants you to describe the structure of the atomic nucleus, identify the three types of radioactive decay, apply the half-life formula, and explain fission and fusion with their applications.

Atomic nucleus

The nucleus contains:

  • Protons. Charge +e+e, mass 1.673×10271.673 \times 10^{-27} kg.
  • Neutrons. Charge 0, mass 1.675×10271.675 \times 10^{-27} kg.

Notation ZAX^A_Z X:

  • ZZ = atomic number (number of protons) = number of electrons in neutral atom.
  • AA = mass number = protons + neutrons.
  • N=AZN = A - Z = number of neutrons.

Isotopes. Same ZZ (same element) but different NN (and so different AA). Examples: 612^{12}_6C, 613^{13}_6C, 614^{14}_6C are all carbon, but with different neutron counts.

Approximate masses are measured in atomic mass units (amu): 1 amu = 1.661×10271.661 \times 10^{-27} kg.

Nuclear forces

Inside the nucleus, two forces compete:

Coulomb repulsion between positively charged protons (long-range).

Strong nuclear force between any pair of nucleons (very short-range, around 101510^{-15} m, but ~100 times stronger than electromagnetism at this scale).

For light nuclei, strong force dominates and stable nuclei have approximately equal protons and neutrons. For heavy nuclei, more neutrons are needed to bind the larger volume against increasing Coulomb repulsion. Above Z=83Z = 83 (bismuth), no nuclei are stable.

Radioactive decay

Unstable nuclei spontaneously emit radiation to reach more stable configurations.

Alpha decay. Emission of a helium nucleus (24^4_2He). Mass number decreases by 4; atomic number by 2.

Example: 92238U90234Th+24He^{238}_{92} \text{U} \to ^{234}_{90} \text{Th} + ^4_2 \text{He}.

Alpha particles are heavy and slow. Range: a few cm in air; stopped by paper.

Beta-minus decay. A neutron converts to a proton plus electron plus antineutrino. Atomic number increases by 1; mass number unchanged.

Example: 614C714N+10e+νˉe^{14}_6 \text{C} \to ^{14}_7 \text{N} + ^0_{-1} e + \bar{\nu}_e.

Beta particles are fast electrons. Range: a few metres in air; stopped by aluminium foil.

Beta-plus decay. A proton converts to a neutron plus positron plus neutrino. (Less common; not always required in Unit 1.)

1122Na1022Ne++10e+νe^{22}_{11} \text{Na} \to ^{22}_{10} \text{Ne} + ^0_{+1} e + \nu_e.

Gamma decay. The nucleus, in an excited state after another decay, emits a high-energy photon. Mass number and atomic number unchanged.

Gamma rays are highly penetrating; require lead or concrete shielding.

Conservation laws

In any nuclear equation:

  • Mass number is conserved.
  • Charge is conserved.
  • (Energy and momentum are also conserved, accounting for kinetic energy of products.)

Half-life

The half-life T1/2T_{1/2} is the time for half the nuclei in a sample to decay. The decay is random for any individual nucleus, but the half-life is a well-defined statistical property.

N=N0(12)t/T1/2N = N_0 \left(\frac{1}{2}\right)^{t/T_{1/2}}

where N0N_0 is initial number, NN is number after time tt.

Equivalent activity: A=A0(1/2)t/T1/2A = A_0 (1/2)^{t/T_{1/2}}.

Common half-lives:

  • Carbon-14: 5,730 years. Used for carbon dating.
  • Iodine-131: 8 days. Used in medicine.
  • Uranium-238: 4.5 billion years.
  • Polonium-214: 0.16 ms.

Fission

A heavy nucleus (typically uranium-235 or plutonium-239) splits into two roughly equal fragments, releasing energy and free neutrons.

92235U+n56141Ba+3692Kr+3n+energy^{235}_{92} \text{U} + n \to ^{141}_{56} \text{Ba} + ^{92}_{36} \text{Kr} + 3n + \text{energy}

The energy released per fission is approximately 200 MeV.

Chain reaction. The released neutrons can induce further fissions. If on average more than one neutron per fission triggers a new fission, the chain reaction is supercritical (explosive). Controlled chain reactions (one neutron per fission triggers one new fission) power nuclear reactors.

Fusion

Light nuclei (typically deuterium and tritium, 2^2H and 3^3H) fuse into a heavier nucleus (helium), releasing energy.

12H+13H24He+n+17.6 MeV^2_1 \text{H} + ^3_1 \text{H} \to ^4_2 \text{He} + n + 17.6 \text{ MeV}

Fusion powers the sun. Controlled fusion for power generation has been a long-term research goal (ITER, JET, others) but has not yet been commercialised.

Fusion produces more energy per kg of fuel than fission and has fewer long-lived radioactive products. The barrier is the temperature (around 10810^8 K) needed to overcome Coulomb repulsion.

Applications

Nuclear power
Fission reactors generate about 10 percent of world electricity. Concerns: waste storage, weapons proliferation, accident risk (Three Mile Island 1979, Chernobyl 1986, Fukushima 2011).
Nuclear medicine
Diagnostic imaging (technetium-99m, fluorine-18 in PET scans). Cancer therapy (cobalt-60, iodine-131, linear accelerators).
Industrial
Thickness measurement, smoke detectors (americium-241), industrial radiography.
Carbon dating
Carbon-14 is produced in the upper atmosphere and incorporated into living things. After death, 14^{14}C content decays with half-life 5,730 years. Used to date objects up to about 50,000 years old.

Examples in context

Example 1. ANSTO OPAL reactor neutron fluence for medical isotopes. The OPAL reactor at Lucas Heights runs at 2020 MW thermal and provides a thermal-neutron flux of about 4×10144 \times 10^{14} neutrons cm2^{-2} s1^{-1} at irradiation positions. Each fission of 235^{235}U yields approximately 200200 MeV. Power output divided by energy per fission gives 20×106/(200×1.602×1013)=6.2×101720 \times 10^6 \,/\, (200 \times 1.602 \times 10^{-13}) = 6.2 \times 10^{17} fissions s1^{-1}. The neutrons activate 98^{98}Mo to 99^{99}Mo for technetium-99m generators that supply Australian and Pacific hospitals; about 30%30\% of global 99^{99}Mo supply comes from ANSTO during regional shortages.

Example 2. Radon mitigation in Mt Stromlo observatory bedrock. Uranium-238 decay series at Mt Stromlo bedrock produces radon-222 (half-life 3.83.8 days), which can accumulate in basement instrumentation rooms. Initial activity 200200 Bq m3^{-3} decays as N=N0(1/2)t/3.8N = N_0 (1/2)^{t/3.8}. After one week (7 days), activity falls to 200×(1/2)7/3.8=200×0.277=55200 \times (1/2)^{7/3.8} = 200 \times 0.277 = 55 Bq m3^{-3}, but continuous ingrowth from soil-bound radium replenishes it. Building physics design therefore uses sub-floor ventilation to keep airborne radon below the 200200 Bq m3^{-3} ARPANSA action threshold, protecting astronomers and electronics from alpha activity.

Try this

Q1. Identify the three principal types of radioactive decay and state one penetration property of each. [3 marks]

  • Cue. Alpha: stopped by paper. Beta: stopped by thin aluminium. Gamma: needs lead or thick concrete.

Q2. A 99^{99}mTc sample (half-life 6.06.0 hours) has an initial activity of 800800 MBq. Calculate (a) the activity after 1818 hours, and (b) the time required for activity to fall below 5050 MBq. [4 marks]

  • Cue. (a) 800×(1/2)3=100800 \times (1/2)^3 = 100 MBq. (b) 50/800=1/16=(1/2)450/800 = 1/16 = (1/2)^4 so t=24t = 24 hours.

Q3. Refer to OPAL operations. (a) Outline the role of neutron capture in producing 99^{99}Mo. (b) Calculate the number of fissions per second at 2020 MW thermal power, assuming 200200 MeV per fission. (c) Explain one safety benefit of using 99^{99}mTc rather than 131^{131}I for diagnostic imaging. [2+2+2 marks]

  • Cue. (a) 98^{98}Mo + n99n \to ^{99}Mo + γ\gamma. (b) 6.2×10176.2 \times 10^{17} s1^{-1}. (c) Shorter half-life gives smaller cumulative dose; pure gamma emitter has no beta dose to surrounding tissue.

Exam-style practice questions

Practice questions written in the style of VCAA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Year 11 SAC4 marksCarbon-14 (614C^{14}_6 \text{C}) has half-life 5,7305,730 years. A sample contains 1.0×10101.0 \times 10^{10} carbon-14 atoms initially. (a) How many atoms remain after 17,19017,190 years? (b) Carbon-14 decays by beta-minus emission to nitrogen-14. Write the nuclear equation.
Show worked answer →

(a) Atoms remaining. 17,190/5,730=317,190 / 5,730 = 3 half-lives.

N=N0(1/2)3=1.0×1010×1/8=1.25×109N = N_0 (1/2)^3 = 1.0 \times 10^{10} \times 1/8 = 1.25 \times 10^9 atoms.

(b) Nuclear equation. Beta-minus decay: a neutron converts to a proton plus electron plus antineutrino.

614C714N+10e+νˉe^{14}_6 \text{C} \to ^{14}_7 \text{N} + ^0_{-1} e + \bar{\nu}_e

Conservation: mass number 14 = 14 + 0; charge 6 = 7 + (-1).

Markers reward the half-life calculation (3 half-lives gives 1/8), the equation with correct conservation of mass and charge, and the antineutrino (optional in some marking schemes).

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