Skip to main content

Cubic and quartic polynomials (VCE Maths Methods Unit 1)

Syllabus dot point

“Sketch cubic and quartic polynomials, identifying intercepts, end behaviour, turning points and points of inflection, and using factored form to read roots and multiplicities”

5 min read

Quick answer

From factored form, read each root's multiplicity: 1 crosses, 2 touches and turns, 3 crosses with a flat tangent. End behaviour comes from the leading term axnax^n (even degree: both ends agree; odd: opposite), and the yy-intercept from x=0x=0.

Jump to a section
  1. What this dot point is asking
  2. End behaviour
  3. Root multiplicities
  4. Cubics
  5. Quartics
  6. Building a polynomial from its roots
  7. Worked example
  8. Common traps
  9. In one sentence
  10. Examples in context
  11. Try this
  12. Exam-style questions

What this dot point is asking

VCAA wants you to sketch cubic and quartic polynomials from their factored or standard form, identify intercepts, end behaviour and turning/inflection points, and interpret root multiplicities geometrically.

End behaviour

The end behaviour of a polynomial is set by its leading term axnax^n:

| nn even, a>0a > 0 | Both ends +∞+\infty |
| nn even, a<0a < 0 | Both ends −∞-\infty |
| nn odd, a>0a > 0 | Left −∞-\infty, right +∞+\infty |
| nn odd, a<0a < 0 | Left +∞+\infty, right −∞-\infty |

Root multiplicities

For a factor (x−p)k(x - p)^k:

  • k=1k = 1: graph crosses the xx-axis at x=px = p.
  • k=2k = 2: graph touches the xx-axis and bounces back (turning point on the axis).
  • k=3k = 3: graph crosses with a horizontal tangent (point of inflection on the axis).

Cubics

General cubic: y=ax3+bx2+cx+dy = ax^3 + bx^2 + cx + d.

Has up to two turning points (one local max and one local min) and at least one xx-intercept (because every cubic has at least one real root).

Stationary point of inflection: a cubic of the form y=a(x−h)3+ky = a(x - h)^3 + k has one stationary point of inflection at (h,k)(h, k) and no other turning points.

Quartics

General quartic: y=ax4+bx3+cx2+dx+ey = ax^4 + bx^3 + cx^2 + dx + e.

Has up to three turning points. May have 00, 11, 22, 33 or 44 real roots.

Special form: y=a(x−h)4+ky = a(x - h)^4 + k. Single turning point at (h,k)(h, k), similar shape to a parabola but flatter at the vertex.

Building a polynomial from its roots

If a polynomial has roots r1,r2,…,rnr_1, r_2, \ldots, r_n and leading coefficient aa:

y=a(x−r1)(x−r2)⋯(x−rn)y = a(x - r_1)(x - r_2) \cdots (x - r_n)

Multiplicities are written by repeating factors: (x−p)2(x - p)^2 for a double root at pp.

Worked example

Sketch y=−(x+1)(x−2)2y = -(x + 1)(x - 2)^2.

Cubic. Leading coefficient −1-1 (expand: −x3+…-x^3 + \ldots).

Roots: x=−1x = -1 (multiplicity 11, crosses), x=2x = 2 (multiplicity 22, touches and turns).

yy-intercept: y(0)=−(1)(4)=−4y(0) = -(1)(4) = -4.

End behaviour: as x→+∞x \to +\infty, y→−∞y \to -\infty; as x→−∞x \to -\infty, y→+∞y \to +\infty (odd degree, negative lead).

Local maximum exists at x=2x = 2 (touch-and-turn at the double root from below).

Common traps

Confusing odd and even degree end behaviour
Even degree polynomials have both ends going the same direction; odd degree polynomials have opposite directions.
Treating a double root as just one root
A double root counts twice when counting roots with multiplicity and produces touch-and-turn behaviour rather than crossing.
Forgetting the sign of the leading coefficient
Negative leading coefficient flips the graph vertically.
Including more turning points than degree allows
A polynomial of degree nn has at most n−1n - 1 turning points.

In one sentence

Cubic and quartic polynomials are sketched from their factored form by reading roots (with multiplicities determining crossing vs touching), the yy-intercept by setting x=0x = 0, and end behaviour from the leading term (axnax^n for nn even gives both ends in the same direction, for nn odd in opposite directions, with the sign of aa flipping vertically).

Examples in context

Example 1. Reading a factored cubic. Sketch y=(x+2)(x−1)2y = (x + 2)(x - 1)^2. Roots: x=−2x = -2 (single, so the curve crosses) and x=1x = 1 (double, so the curve touches and turns). The yy-intercept is y=(2)(1)2=2y = (2)(1)^2 = 2. Leading term: expanding gives x3x^3 as the highest power with positive coefficient, so as x→−∞x \to -\infty, y→−∞y \to -\infty and as x→+∞x \to +\infty, y→+∞y \to +\infty.

Example 2. End behaviour of a quartic. For y=−x4+5x2−4=−(x2−1)(x2−4)=−(x−1)(x+1)(x−2)(x+2)y = -x^4 + 5x^2 - 4 = -(x^2 - 1)(x^2 - 4) = -(x - 1)(x + 1)(x - 2)(x + 2), the four roots are x=±1,±2x = \pm 1, \pm 2 (all single, all crossings). The negative leading coefficient and even degree mean both ends point down (y→−∞y \to -\infty). The yy-intercept is −4-4.

Try this

Q1. State the roots of y=(x−3)(x+1)2y = (x - 3)(x + 1)^2 and which is a turning point on the axis. [2 marks]

  • Cue. Roots x=3x = 3 (crosses) and x=−1x = -1 (double root, touches and turns).

Q2. Find the yy-intercept and end behaviour of y=2x3−xy = 2x^3 - x. [2 marks]

  • Cue. yy-intercept 00; positive odd leading term, so y→−∞y \to -\infty as x→−∞x \to -\infty and y→+∞y \to +\infty as x→+∞x \to +\infty.

Q3. A quartic has factored form y=a(x+2)(x−1)3y = a(x + 2)(x - 1)^3 and passes through (0,4)(0, 4). (a) Find aa. (b) Describe the behaviour at each root. [2+2 marks]

  • Cue. (a) 4=a(2)(−1)3=−2a4 = a(2)(-1)^3 = -2a, so a=−2a = -2. (b) At x=−2x = -2 single root (crosses); at x=1x = 1 triple root (crosses with a flattening/stationary inflection).

Exam-style questions

Questions in the style of VCAA exam questions on this dot point, each with a worked answer. They are written by ExamExplained unless tagged "Past paper"; the year shows the paper a question is modelled on.

Year 11 SAC-style4 marks
Sketch y=(x+2)(x−1)2(x−3)y = (x + 2)(x - 1)^2 (x - 3). State all intercepts, root multiplicities, and end behaviour.
Show worked answer →

Degree 44 (quartic), leading coefficient +1+1.

Roots: x=−2x = -2 (multiplicity 11, crosses), x=1x = 1 (multiplicity 22, touches and turns), x=3x = 3 (multiplicity 11, crosses).

yy-intercept: y(0)=(2)(−1)2(−3)=−6y(0) = (2)(-1)^2(-3) = -6.

End behaviour: as x→±∞x \to \pm\infty, y→+∞y \to +\infty (positive leading coefficient, even degree).

Sketch: enters from top-left, crosses at x=−2x = -2, dips below zero, touches the axis at x=1x = 1 (without crossing), descends below, crosses at x=3x = 3, rises to top-right.

Markers reward identifying multiplicity behaviour, end behaviour and the yy-intercept.

Practise this

Sources & how we know this

ExamExplained