How do you display and describe a time series, and how do moving-mean and moving-median smoothing reveal the underlying trend?
Construct and interpret a time series plot, describe its features (trend, seasonality, cycles, irregular fluctuations), smooth it using moving-mean and moving-median smoothing, and fit a least-squares trend line for forecasting
A focused answer to the VCE General Mathematics Unit 3 Data analysis key-knowledge point on time series. Reading a time series plot, describing trend, seasonality and irregular variation, moving-mean and moving-median smoothing, centred smoothing, and a least-squares trend line for forecasting.
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What this dot point is asking
VCAA wants you to analyse data collected over time. You construct and read a time series plot, describe its features (trend, seasonality, cycles and irregular fluctuations), smooth out short-term noise with moving-mean and moving-median smoothing to reveal the underlying trend, and fit a least-squares trend line so you can forecast. This sits alongside regression as the other big bivariate technique in Data analysis.
Describing a time series
A time series plot joins data points in time order. You describe it using four features:
- Trend: a long-term upward or downward movement.
- Seasonality: a regular pattern that repeats over a fixed period, such as quarterly or monthly.
- Cycles: longer waves not tied to the calendar, such as economic booms and slumps.
- Irregular fluctuations: random, one-off variation with no pattern.
Moving-mean smoothing
For an odd window (3-point, 5-point), replace each interior point with the mean of itself and the points either side. The first and last points have no smoothed value because they lack neighbours.
Moving-median smoothing
A moving median takes the middle value of the window instead of the mean, which makes it resistant to outliers. For a 3-point median of you order them () and take . Moving-median smoothing can also be done graphically straight off the plot.
Centred smoothing for an even window
A 4-point or other even-numbered moving mean lands between time points, so you centre it by taking a further 2-point mean of consecutive moving means. This realigns the smoothed value with an actual time period and is the standard way to smooth quarterly data with a 4-point mean.
Fitting a trend line and forecasting
Once a trend is clear, fit a least-squares line with time as the explanatory variable, numbering the periods . The slope gives the average change per period, and substituting a future period number forecasts ahead. As with all regression, forecasting far beyond the data is extrapolation and unreliable.
Why this matters for the exams
Time series questions appear in most Data analysis exams and the SAC, usually asking you to smooth a short series by hand and describe the trend. The marks reward correct window alignment, the right choice of mean or median, and a description that uses the proper terms. Smoothing leads on to seasonal indices, where you quantify and remove the seasonal effect.
Exam-style practice questions
Practice questions written in the style of VCAA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
2023 VCAA1 marksThe number of visitors to a public library each day for 10 consecutive days was: day 1 to day 10 = 337, 317, 313, 335, 322, 335, 322, 338, 302, 349. The eight-mean smoothed number of visitors with centring for day number 6 is A. 323 B. 324 C. 325 D. 326 E. 327Show worked answer →
Smoothing with an even window of 8 needs centring, which averages two consecutive eight-means.
First eight-mean (days 2 to 9), centred at day 5.5: (317 + 313 + 335 + 322 + 335 + 322 + 338 + 302) / 8 = 2584 / 8 = 323.
Second eight-mean (days 3 to 10), centred at day 6.5: (313 + 335 + 322 + 335 + 322 + 338 + 302 + 349) / 8 = 2616 / 8 = 327.
Centred value at day 6 = (323 + 327) / 2 = 325, so the answer is C.
2025 VCAA1 marksThe number of drinks sold daily by a juice bar over a 10-day period was: day 1 to day 10 = 146, 98, 120, 176, 145, 78, 187, 106, 166, 124. The four-mean smoothed number of drinks, with centring, sold on day 8 is closest to A. 134.25 B. 140.0 C. 142.75 D. 145.75Show worked answer →
A four-mean smooth with centring at day 8 averages the two four-means centred at days 7.5 and 8.5.
Four-mean of days 6 to 9 (centred at 7.5): (78 + 187 + 106 + 166) / 4 = 537 / 4 = 134.25.
Four-mean of days 7 to 10 (centred at 8.5): (187 + 106 + 166 + 124) / 4 = 583 / 4 = 145.75.
Centred value at day 8 = (134.25 + 145.75) / 2 = 280 / 2 = 140.0, so the answer is B.