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What is a perpetuity, how does the balance stay constant when the payment exactly equals the interest, and how do you find the payment or the principal?

Model a perpetuity as a special annuity in which the regular payment equals the interest earned each period so the balance never changes, and find the perpetual payment, the required principal or the interest rate

A focused answer to the VCE General Mathematics Unit 3 Recursion and financial modelling key-knowledge point on perpetuities. The condition that payment equals interest, the constant-balance recurrence, the formula linking payment, principal and rate, and finding each unknown.

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  1. What this dot point is asking
  2. The constant-balance condition
  3. The payment relationship
  4. Matching the payment frequency to the rate
  5. Perpetuity as a special annuity
  6. Cumulative payments and total payout
  7. Matching technology to the model
  8. Why this matters for the exams

What this dot point is asking

VCAA wants you to model a perpetuity: a lump sum invested so that the regular payment drawn out exactly equals the interest earned each period, leaving the balance unchanged forever. You recognise the constant-balance condition, use the relationship between payment, principal and interest rate, and solve for whichever quantity is unknown. Perpetuities fund scholarships and prizes, where a fixed amount must be paid out indefinitely without ever touching the principal.

The constant-balance condition

In a perpetuity the growth factor adds interest and the payment removes exactly that interest. The recurrence is the annuity form

Vn+1=R Vnβˆ’d,V_{n+1} = R\,V_n - d,

but with dd chosen so that the interest added, r100Vn\frac{r}{100}V_n, equals the payment dd. Then the balance returns to its starting value every period:

Vn+1=Vn+r100Vnβˆ’d=Vn.V_{n+1} = V_n + \frac{r}{100}V_n - d = V_n.

The payment relationship

Because the payment equals the interest on the principal:

d=r100Γ—P.d = \frac{r}{100}\times P.

Rearranged, the principal needed to fund a given payment is P=100 drP = \dfrac{100\,d}{r}, and the rate required is r=100 dPr = \dfrac{100\,d}{P}.

Matching the payment frequency to the rate

If the payment is made more often than yearly, use the rate per period. A perpetuity paying monthly at a nominal 6%6\% per annum uses 0.5%0.5\% per month, so d=0.005Γ—Pd = 0.005 \times P. Always match the rate's period to the payment's period.

Perpetuity as a special annuity

A perpetuity is the boundary case of a reducing-balance annuity. A general annuity follows Vn+1=R Vnβˆ’dV_{n+1} = R\,V_n - d, where the multiplier R=1+r100R = 1 + \frac{r}{100} adds interest and the payment dd draws the balance down. In a perpetuity the payment is set exactly equal to the interest earned, d=r100Vnd = \frac{r}{100}V_n, so the addition and the withdrawal cancel and the balance is fixed at the principal for every period. If the payment were even slightly smaller the balance would grow without limit; if it were slightly larger the balance would shrink and eventually run out, turning the perpetuity into an ordinary depleting annuity. Recognising this knife-edge condition is the key insight VCAA tests.

Cumulative payments and total payout

Because a perpetuity never stops, questions often ask not for a final balance but for the cumulative total of payments after nn periods. Since each payment is the constant d=r100Pd = \frac{r}{100}P, the running total after nn payments is simply n dn\,d, an arithmetic sum. To find when the cumulative payout first passes some target TT, solve n d>Tn\,d > T for the smallest whole number nn. This is exactly the structure of the 2025 multiple-choice item above: the payments form a linear (arithmetic) sequence even though the underlying account is compounding, because the balance never changes.

Matching technology to the model

On a CAS finance solver a perpetuity is entered with the present value and the future value equal in magnitude and opposite in sign (for example PV=βˆ’200 000PV = -200\,000 and FV=200 000FV = 200\,000), the payment equal to the interest, and NN set to any convenient number of periods, since the balance is the same after every one. In Exam 1 (technology-free) you will not use the solver, so rely on the direct relationship d=r100Pd = \frac{r}{100}P and its rearrangements. Always state, in words, that the balance is preserved because the payment equals the interest, as this is the reasoning mark examiners look for.

Why this matters for the exams

Perpetuity questions are short but reward the key insight that payment equals interest, so the balance is constant. They test the simple relationship d=r100Pd = \frac{r}{100}P and its rearrangements, and link to the broader annuity model where the payment instead draws the balance down. State clearly that the balance is preserved, since that is the defining feature markers look for.

Exam-style practice questions

Practice questions written in the style of VCAA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

2025 VCAA1 marksDonald invests 250000intoaperpetuityataninterestrateof5250 000 into a perpetuity at an interest rate of 5% per annum. Donald receives a payment at the end of each year. When will the sum of all annual payments to Donald first exceed 250 000? A. at the end of year 13 B. at the end of year 17 C. at the end of year 21 D. at the end of year 25
Show worked answer β†’

In a perpetuity the payment exactly equals the interest earned each period, so the balance stays at $250 000 forever.

annual payment = interest = 0.05 x 250 000 = $12 500.

The cumulative total after n years is 12 500 x n. Set this greater than 250 000: 12 500 x n > 250 000 gives n > 20.

So the total first exceeds 250000atn=21(21x12500=250 000 at n = 21 (21 x 12 500 = 262 500), which is the end of year 21, option C.

VCAA 20234 marksA university wants to fund a perpetual scholarship that pays \9000attheendofeachyear.Thefundearnsinterestat at the end of each year. The fund earns interest at 4.5\%perannum,compoundingannually.(a)Calculatetheprincipalthatmustbeinvested.(b)Ifinsteadthescholarshipispaidas per annum, compounding annually. (a) Calculate the principal that must be invested. (b) If instead the scholarship is paid as \22502250 at the end of each quarter from a fund earning a nominal 4.5%4.5\% per annum compounding quarterly, determine the principal required.
Show worked answer β†’

A perpetuity preserves its principal because each payment equals the interest earned. Use P=100 drP = \dfrac{100\,d}{r} with the rate matched to the payment period.

(a) Annual payment d=9000d = 9000, annual rate r=4.5r = 4.5. P=100Γ—90004.5=900 0004.5=$200 000P = \dfrac{100 \times 9000}{4.5} = \dfrac{900\,000}{4.5} = \$200\,000.

(b) Quarterly payment d=2250d = 2250, quarterly rate r=4.5/4=1.125%r = 4.5/4 = 1.125\%. P=100Γ—22501.125=225 0001.125=$200 000P = \dfrac{100 \times 2250}{1.125} = \dfrac{225\,000}{1.125} = \$200\,000.

Both arrangements need the same principal, $200 000\$200\,000, because the total annual payout ($9000\$9000) and the effective annual return are unchanged. Markers award two marks per part: one for matching the rate to the payment period, one for the correct principal.

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