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TASSpecialist MathematicsUnit 4

Quick questions on Integration techniques and applications - TCE Mathematics Specialised (Tasmania)

5short Q&A pairs drawn directly from our worked dot-point answer. For full context and worked exam questions, read the parent dot-point page.

What is substitution?
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Substitution reverses the chain rule. If part of the integrand is the derivative of another part, let uu be the inner function. With u=g(x)u = g(x) and du=g(x)dxdu = g'(x)\,dx, $f(g(x))g(x)dx=f(u)du. \int f(g(x))\, g'(x)\, dx = \int f(u)\, du. Foradefiniteintegral,changethelimitstovaluesof For a definite integral, change the limits to values of u$ rather than substituting back.
What are integration by parts?
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Integration by parts reverses the product rule: $udvdxdx=uvvdudxdx. \int u\, \frac{dv}{dx}\, dx = uv - \int v\, \frac{du}{dx}\, dx. Choose Choose utobethefactorthatbecomessimplerwhendifferentiated.Ausefulpriorityforpicking to be the factor that becomes simpler when differentiated. A useful priority for picking u$ is logarithms, then inverse trigonometric functions, then algebraic, then trigonometric, then exponential.
What are partial fractions?
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A proper rational function with a factorised denominator can be split into simpler fractions. For distinct linear factors, $P(x)(xa)(xb)=Axa+Bxb, \frac{P(x)}{(x - a)(x - b)} = \frac{A}{x - a} + \frac{B}{x - b}, $ and each piece integrates to a logarithm.
What is volumes of revolution?
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When the region under y=f(x)y = f(x) between x=ax = a and x=bx = b is rotated about the xx axis, the solid formed has volume $V=πaby2dx=πab(f(x))2dx. V = \pi \int_a^b y^2 \, dx = \pi \int_a^b \big(f(x)\big)^2 \, dx. Rotationaboutthe Rotation about the yaxisgives axis gives V = \pi\int_c^d x^2 \, dy$.
What are integration using trigonometric identities?
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Powers of sin\sin and cos\cos are integrated by first reducing the power with an identity. For even powers use the double-angle forms sin2θ=1cos2θ2\sin^2\theta = \dfrac{1 - \cos 2\theta}{2} and cos2θ=1+cos2θ2\cos^2\theta = \dfrac{1 + \cos 2\theta}{2}; for odd powers peel off one factor and convert the rest with sin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1, then substitute.

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