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TASPhysicsSyllabus dot point

What produces magnetic fields and what shape do they take?

Describe magnetic fields from magnets and currents and represent them with field lines.

Magnetic poles and field lines, permanent and temporary magnets, the field around a current-carrying wire and solenoid, electromagnets, and Earth's magnetic field including the angle of dip.

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What this dot point is asking

This dot point describes where magnetic fields come from and how to represent them, the groundwork for the motor effect and induction.

Poles and field lines

Every magnet has two poles, north and south. Like poles repel and unlike poles attract. A magnetic field is represented by field lines that, by convention, point from the north pole to the south pole outside the magnet and continue from south to north inside it, forming closed loops. The lines never cross, and where they bunch together the field is stronger.

A compass needle is a small magnet that aligns with the field, so the direction a compass north points defines the field direction at that spot.

Magnetic materials

At a deeper level, magnetism comes from the motion of charges, specifically the spin and orbital motion of electrons. In most materials these effects cancel, but in ferromagnetic materials like iron, regions called domains can align to give a net field.

  • A permanent magnet keeps its alignment, producing a steady field.
  • A temporary magnet, such as soft iron, becomes magnetised only while in another field and loses it afterward.
  • An electromagnet is a coil of wire whose magnetism can be switched on and off with the current, and strengthened with an iron core.

Fields from currents

A straight current-carrying wire produces a circular magnetic field around it. The right-hand grip rule gives the direction: point your right thumb along the conventional current and your curled fingers show the field looping around the wire.

A coil or solenoid carrying current produces a field very like a bar magnet, with a north and south pole at its ends. A second right-hand rule applies: curl your fingers in the direction of the current around the loops and your thumb points to the solenoid's north pole. Adding an iron core concentrates the field, making a strong electromagnet used in motors, relays and lifting magnets.

Earth's magnetic field

Earth behaves like a giant bar magnet tilted slightly from its spin axis. A compass aligns horizontally with this field, but a needle free to rotate vertically also tilts downward; the angle below the horizontal is the angle of dip. The dip is near zero at the equator and close to vertical near the magnetic poles, which tells us the field has a vertical component that varies with latitude.

In the exam, use the right-hand grip rule for the field around a wire and the coil version for a solenoid. When describing Earth's field, mention both the horizontal compass direction and the angle of dip, which shows the field is genuinely three dimensional.

Exam-style practice questions

Practice questions written in the style of TASC exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

2023 TASC4 marksTwo parallel wires 5.00 cm apart carry currents of 5.00 A and 10.00 A. At point P, located 4.00 cm above the 5.00 A wire and 3.00 cm above the 10.00 A wire, calculate the magnetic flux density B1 due to the 5.00 A wire and B2 due to the 10.00 A wire.
Show worked answer →

The field around a long straight wire is B = mu0 I / (2 pi r), with mu0 = 4 pi x 10^-7 T m A-1.

From the 5.00 A wire at r = 0.04 m:
B1 = (4 pi x 10^-7 x 5.00) / (2 pi x 0.04) = (2 x 10^-7 x 5.00) / 0.04 = 1.0 x 10^-6 / 0.04 = 2.50 x 10^-5 T.

From the 10.00 A wire at r = 0.03 m:
B2 = (4 pi x 10^-7 x 10.00) / (2 pi x 0.03) = (2 x 10^-7 x 10.00) / 0.03 = 2.0 x 10^-6 / 0.03 = 6.67 x 10^-5 T.

The directions are tangent to circles around each wire (use the right-hand grip rule) and must be added as vectors for the total. Markers want B = mu0 I / (2 pi r) applied with the correct distance for each wire.

2022 TASC2 marksA vertical wire carrying a current of 5.00 A upwards is placed against the edge of a table. Calculate the magnetic flux density due to the current at a point P located 20 cm North of the wire.
Show worked answer →

Use the field of a long straight wire: B = mu0 I / (2 pi r).

B = (4 pi x 10^-7 x 5.00) / (2 pi x 0.20)
= (2 x 10^-7 x 5.00) / 0.20
= 1.0 x 10^-6 / 0.20
= 5.0 x 10^-6 T.

The flux density is 5.0 x 10^-6 T (5.0 microT). By the right-hand grip rule, with current upward and P to the north, the field at P points west (horizontally). Markers want the straight-wire formula and the field direction from the grip rule.

2024 TASC1 marksIn a science museum an aluminium plate is levitated over a large coil carrying 800 A of alternating current at 800 Hz. Describe what would happen if direct current (rather than alternating current) was used.
Show worked answer →

With direct current the coil produces a steady, unchanging magnetic field. A steady field does not change the magnetic flux through the aluminium plate, so no emf is induced and no eddy currents flow in the plate (Faraday's law requires a changing flux).

Without induced eddy currents there is no opposing magnetic field in the plate, so there is no repulsive force to support it. The plate would simply not levitate, and would fall or rest on the coil.

Markers want: DC gives a constant field, no changing flux, no induced eddy currents, therefore no levitating force.