Skip to main content

Back to the full dot-point answer

TASMath MethodsQuick questions

Unit 3

Quick questions on Kinematics: position, velocity and acceleration (TCE Mathematics Methods, Tasmania)

2short Q&A pairs drawn directly from our worked dot-point answer. For full context and worked exam questions, read the parent dot-point page.

What are reading the signs?
Show answer
Sign carries direction. A positive velocity means the object moves in the positive direction; a negative velocity means it moves backwards. The object is momentarily at rest when v=0v=0.
What is recovering motion from acceleration?
Show answer
A common second style of question gives the acceleration and an initial condition and asks you to integrate. For example, if a(t)=6ta(t) = 6t with v(0)=2v(0)=2, then v(t)=6tdt=3t2+Cv(t) = \int 6t\,dt = 3t^2 + C, and v(0)=2v(0)=2 gives C=2C=2, so v(t)=3t2+2v(t) = 3t^2 + 2. Integrating again with a starting position recovers x(t)x(t).

Have a question we have not covered?

This dot-point answer is short enough that we have not extracted many short questions yet. Read the full dot-point answer or ask Mo, our study assistant, in the chat for follow ups.

All Math MethodsQ&A pages