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SAGeneral MathematicsSyllabus dot point

How do we use a straight-line equation to model and predict from a real situation?

Construct and interpret linear functions of the form y = mx + c to model practical situations, identifying the meaning of the gradient and intercept.

How to build a linear model y = mx + c from a worded situation, interpret the gradient as a rate and the intercept as a starting value, and use the model to predict.

Generated by Claude Opus 4.76 min answer

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  1. What this dot point is asking
  2. The linear model
  3. Building a model from words
  4. Interpreting the model in context
  5. Predicting and the limits of a model

What this dot point is asking

You must be able to read a practical situation, set up a linear equation that fits it, explain what the gradient and intercept mean in context, and use the model to make predictions.

The linear model

A relationship is linear when yy changes by the same amount for each unit increase in xx. The model is:

y=mx+cy = mx + c

Building a model from words

The key is to identify the two parameters from the wording:

  • A fixed starting amount, base fee, or initial value gives the intercept cc.
  • A "per unit" amount (per hour, per kilometre, per item) gives the gradient mm.

Interpreting the model in context

Examiners reward interpretation, not just numbers. For the taxi model:

  • The gradient 2.202.20 means the fare increases by $2.20 for each extra kilometre.
  • The intercept 4.504.50 means the fare is $4.50 before any distance is travelled.

Predicting and the limits of a model

Substitute a value to predict. Predicting inside the range of your data is interpolation (usually reliable); predicting outside it is extrapolation (less reliable, because the linear pattern may not continue).