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SAChemistrySyllabus dot point

How is the heat released or absorbed by a reaction measured and calculated?

Calculate enthalpy changes from calorimetry data using q = mcΔT, and interpret exothermic and endothermic reactions.

How to classify reactions as exothermic or endothermic and calculate enthalpy changes from calorimetry using q = mcΔT and the molar enthalpy relationship.

Generated by Claude Opus 4.78 min answer

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  1. What this dot point is asking
  2. Exothermic and endothermic reactions
  3. The calorimetry equation
  4. Sources of error in calorimetry
  5. Why this matters for managing processes

What this dot point is asking

You must classify reactions energetically and calculate enthalpy changes from experimental calorimetry data.

Exothermic and endothermic reactions

In an exothermic reaction the products are lower in energy than the reactants; in an endothermic reaction they are higher.

The calorimetry equation

Heat transferred to or from the water is:

q=mcΔTq = mc\Delta T

where mm is the mass of water (g), cc is the specific heat capacity of water (4.18 J g1C14.18\ \text{J g}^{-1}\,{}^\circ\text{C}^{-1}), and ΔT\Delta T is the temperature change (C^\circ\text{C}).

To get the molar enthalpy change, divide qq by the moles of the limiting reactant:

ΔH=qn\Delta H = -\frac{q}{n}

The negative sign converts "heat gained by water" into "enthalpy of the reaction": if the water warmed, the reaction was exothermic (ΔH<0\Delta H < 0).

Sources of error in calorimetry

Simple calorimeters lose heat to the surroundings, so the measured temperature rise - and hence the calculated energy - is usually lower in magnitude than the true value. Incomplete combustion and heat absorbed by the container add further error.

Why this matters for managing processes

Knowing whether a process is exothermic or endothermic - and by how much - lets engineers design heating, cooling and safety systems, and (combined with Le Chatelier's principle) predict how temperature affects equilibrium yield.

Exam-style practice questions

Practice questions written in the style of SACE Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

2024 SACE Stage 23 marksA student burned biodiesel under 100.0 g of water, which was heated from 19.4 degrees C to 32.9 degrees C. Calculate the quantity of heat, in kJ, absorbed by the water in this experiment. (The specific heat capacity of water = 4.18 J g-1 degrees C-1.)
Show worked answer →

Use q = mc(delta T).

  1. delta T = 32.9 - 19.4 = 13.5 degrees C.

  2. q = m x c x delta T = 100.0 x 4.18 x 13.5.

  3. q = 5643 J = 5.64 kJ. One mark for delta T, one for correct substitution, one for converting J to kJ with an appropriate answer.

2024 SACE Stage 22 marksExplain one systematic error that results in the value calculated for the quantity of energy released by combustion of biodiesel being significantly smaller than its true value.
Show worked answer →

A systematic error consistently lowers the measured energy.

  1. A large amount of heat is lost to the surroundings (the air, the container, and the apparatus) rather than all being transferred to the water.

  2. Because the heat absorbed by the water is used to calculate the energy released, this heat loss means less than the true heat is detected, so the calculated energy released is consistently lower than the true value. One mark for identifying heat loss to surroundings (or incomplete combustion), one for explaining why this lowers the calculated value.

2024 SACE Stage 21 marksA biodiesel C17H34O2 has molar mass 270.46 g mol-1 and releases 9950 kJ mol-1. Calculate the energy released, in kJ g-1.
Show worked answer →

Divide the molar energy by the molar mass:

energy per gram = 9950 / 270.46 = 36.8 kJ g-1.

One mark for the correct calculation and answer.