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Population genetics and allele frequencies (SACE Stage 2 Biology)

Syllabus dot point

“Explain allele frequencies and gene pools, and use the Hardy-Weinberg principle to detect change”

9 min read

Quick answer

A gene pool is all the alleles of all individuals in a population, and allele frequencies are the proportions of each allele. The Hardy-Weinberg principle uses p + q = 1 and p squared + 2pq + q squared = 1 to predict genotype frequencies in a population that is not evolving. When real frequencies differ from the predicted values, evolutionary forces such as selection, drift, gene flow or mutation are acting.

Jump to a section
  1. What this dot point is asking
  2. Gene pools and allele frequencies
  3. The Hardy-Weinberg principle
  4. Reading the equations carefully
  5. Why deviation signals evolution
  6. Exam-style questions

What this dot point is asking

You need to define gene pool and allele frequency, state the Hardy-Weinberg conditions, and use the Hardy-Weinberg equations to calculate allele and genotype frequencies. This dot point treats evolution quantitatively.

Gene pools and allele frequencies

A gene pool is the total collection of all alleles for all genes in a population. The allele frequency is the proportion of a particular allele among all the copies of that gene in the population.

Evolution can be defined at this level as a change in allele frequencies in a gene pool over generations. The mechanisms that change them are natural selection, genetic drift, gene flow and mutation. This definition is powerful because it makes evolution measurable: rather than describing whole organisms changing, we track the proportions of alleles, which lets the Hardy-Weinberg model give precise, testable predictions.

To calculate an allele frequency directly, count the copies of that allele and divide by the total number of allele copies in the population. For a gene with two alleles in a diploid population of NN individuals there are 2N2N allele copies in total. For example, if a population of 100100 individuals contains 130130 copies of allele A and 7070 copies of allele a, then the frequency of A is 130/200=0.65130 / 200 = 0.65 and the frequency of a is 70/200=0.3570 / 200 = 0.35, which together sum to 11 as required.

The Hardy-Weinberg principle

The Hardy-Weinberg principle describes a theoretical population in which allele frequencies stay constant from generation to generation - a population that is not evolving. It acts as a null model: if a real population matches it, no evolution is occurring; if it deviates, evolution is.

It uses two equations, where pp and qq are the frequencies of two alleles of a gene:

p+q=1p + q = 1

p2+2pq+q2=1p^2 + 2pq + q^2 = 1

Here p2p^2 is the frequency of the homozygous dominant genotype, 2pq2pq the heterozygous genotype, and q2q^2 the homozygous recessive genotype.

The conditions for equilibrium

Allele frequencies stay constant only if all the following hold:

  • a large population (so drift is negligible)
  • no mutation
  • no gene flow (no migration)
  • random mating
  • no natural selection

If any condition is broken, allele frequencies can change - that is, evolution can occur.

Why Hardy-Weinberg is useful

The principle gives the allele and genotype frequencies expected when nothing is changing. By comparing observed frequencies with these predictions, scientists can detect whether a population is evolving and estimate the frequency of carriers of recessive alleles.

Calculating allele frequencies

From recessive phenotype to carrier frequency

In a population, 16 percent of individuals show a recessive phenotype (genotype aa).

Step 1: q2=0.16q^2 = 0.16, so q=0.16=0.4q = \sqrt{0.16} = 0.4 (frequency of the recessive allele).

Step 2: p=1−q=1−0.4=0.6p = 1 - q = 1 - 0.4 = 0.6 (frequency of the dominant allele).

Step 3: frequency of heterozygous carriers =2pq=2×0.6×0.4=0.48= 2pq = 2 \times 0.6 \times 0.4 = 0.48, or 48 percent.

Step 4: frequency of homozygous dominant =p2=0.62=0.36= p^2 = 0.6^2 = 0.36, or 36 percent.

Check: 0.36+0.48+0.16=10.36 + 0.48 + 0.16 = 1. So 48 percent of the population are carriers, even though only 16 percent show the recessive trait.

Reading the equations carefully

The most common stumbling block is mapping the right quantity to the right symbol. Work in this order: the observed recessive phenotype gives q2q^2 (because only homozygous recessive individuals show it), so take the square root to get the recessive allele frequency qq. Then p=1−qp = 1 - q gives the dominant allele frequency. Only then can you find the genotype frequencies: p2p^2 for homozygous dominant, 2pq2pq for heterozygous carriers, and q2q^2 for homozygous recessive. A useful sanity check is that the three genotype frequencies must always add to 11, and the two allele frequencies must always add to 11. If they do not, an arithmetic slip has crept in.

Why deviation signals evolution

The real value of the Hardy-Weinberg model is as a null hypothesis. It tells you what the genotype frequencies should be if none of the evolutionary forces are acting. If a real population's observed genotype frequencies match the predicted p2:2pq:q2p^2 : 2pq : q^2 ratio, then within the limits of measurement no evolution is detected. If they differ - for example, far fewer homozygous recessives than predicted - then at least one condition is being broken, and you can reason about which force is responsible. Heavy selection against the recessive phenotype would lower qq over generations; a small population would let drift shift frequencies randomly; immigration would introduce gene flow. This is how a static equation becomes a tool for detecting and quantifying evolutionary change.

Common errors
Reading the recessive phenotype as q rather than q squared
The frequency of the recessive phenotype equals q2q^2; take the square root to get qq.
Forgetting carriers in 2pq
Heterozygotes (2pq2pq) carry the recessive allele but show the dominant phenotype.
Assuming Hardy-Weinberg means evolution is happening
It describes a non-evolving population; deviation from it is what signals evolution.
Mixing up genotype and allele frequencies
pp and qq are allele frequencies; p2p^2, 2pq2pq and q2q^2 are genotype frequencies.

Exam-style questions

Questions in the style of SACE Board exam questions on this dot point, each with a worked answer. They are written by ExamExplained unless tagged "Past paper"; the year shows the paper a question is modelled on.

SACE 2018-style1 mark
About 250 black robins live on the Chatham Islands, all descended from one female. State the term that refers to all the genetic information in the interbreeding population of black robins.
Show worked answer →

The gene pool. The gene pool is the total of all the alleles of all the genes present in all the individuals of an interbreeding population. The mark is for naming the gene pool.

SACE 2022-style4 marks
In a population in Hardy-Weinberg equilibrium, 9%9\% of individuals are homozygous recessive (aa) for a gene. (a) Calculate the frequency of the recessive allele. (b) Calculate the percentage of the population that are heterozygous carriers. (c) State one Hardy-Weinberg condition and explain how breaking it could change the allele frequencies.
Show worked answer →

Four marks: one for (a), one for (b), two for (c).

(a) Recessive allele frequency (1 mark)
q2=0.09q^2 = 0.09, so q=0.09=0.3q = \sqrt{0.09} = 0.3.
(b) Carrier percentage (1 mark)
First p=1−q=1−0.3=0.7p = 1 - q = 1 - 0.3 = 0.7. Heterozygous carriers =2pq=2×0.7×0.3=0.42= 2pq = 2 \times 0.7 \times 0.3 = 0.42, so 42%42\% of the population are carriers.
(c) A condition and its effect (2 marks)
Any one valid condition, for example "no natural selection". If selection acts (one condition broken), individuals with one genotype survive and reproduce more than others, so they pass on more of their alleles. This changes the allele frequencies in the next generation's gene pool, meaning the population is evolving and no longer in equilibrium. (Other valid conditions: large population - else genetic drift; no migration - else gene flow; no mutation; random mating.)

Markers reward the correct square-root step, the 2pq2pq calculation, and a named condition correctly linked to a change in allele frequency.

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