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QLDSpecialist MathematicsUnit 4: Further calculus, and statistical inference

Quick questions on Integration techniques: substitution and partial fractions (QCE Specialist Mathematics Unit 4)

5short Q&A pairs drawn directly from our worked dot-point answer. For full context and worked exam questions, read the parent dot-point page.

What is integration by substitution?
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Substitution reverses the chain rule. If the integrand contains a function and (a multiple of) its derivative, let uu be the inner function. With u=g(x)u = g(x) and du=g(x)dxdu = g'(x)\,dx,
What are integration by partial fractions?
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A proper rational function with a factorisable denominator can be split into simpler fractions. For distinct linear factors,
What is volumes of solids of revolution?
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Rotating the region under y=f(x)y = f(x) between x=ax = a and x=bx = b about the xx-axis produces a solid of volume
What is choosing the substitution?
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A good substitution makes the derivative of the inner function appear (up to a constant) elsewhere in the integrand. Telltale signs are a composite function with its inner derivative present, such as 6x6x alongside 3x2+13x^2 + 1, or an expression of the form g(x)g(x)\dfrac{g'(x)}{g(x)}, whose integral is lng(x)\ln|g(x)|. When the integrand is a single awkward function with no obvious inner derivative, a trigonometric substitution (for example x=asinθx = a\sin\theta to handle a2x2\sqrt{a^2 - x^2}) may be the intended route.
What is standard integrals to recognise?
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Fluent integration depends on recognising a small library of standard forms: 1xdx=lnx+C\displaystyle\int \dfrac{1}{x}\,dx = \ln|x| + C, 1a2+x2dx=1aarctanxa+C\displaystyle\int \dfrac{1}{a^2 + x^2}\,dx = \dfrac{1}{a}\arctan\dfrac{x}{a} + C, 1a2x2dx=arcsinxa+C\displaystyle\int \dfrac{1}{\sqrt{a^2 - x^2}}\,dx = \arcsin\dfrac{x}{a} + C, and ekxdx=1kekx+C\displaystyle\int e^{kx}\,dx = \dfrac{1}{k}e^{kx} + C. Many integration questions reduce, after a substitution or a partial-fraction split, to one of these forms, so the strategy is always to manipulate the integrand until it matches a standard result.

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