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Waves and sound: QCE Physics Unit 2 Year 11

Syllabus dot point

“Wave properties (wavelength, frequency, amplitude, period, wave speed v=fλv = f\lambda), transverse vs longitudinal waves, sound waves, the wave behaviours (reflection, refraction, diffraction, interference, polarisation), the Doppler effect, and the electromagnetic spectrum”

10 min read

Quick answer

Waves transfer energy without net matter movement; properties are wavelength, frequency, period, amplitude, and wave speed v=fλv = f\lambda; transverse waves (light) oscillate perpendicular to propagation, longitudinal waves (sound) oscillate parallel; wave behaviours (reflection, refraction, diffraction, interference, polarisation), the Doppler effect, and the electromagnetic spectrum (radio to gamma, all at cc in vacuum) are the universal wave phenomena.

Jump to a section
  1. What this dot point is asking
  2. Wave properties
  3. Transverse vs longitudinal
  4. Sound waves
  5. Wave behaviours
  6. Doppler effect
  7. Electromagnetic spectrum
  8. Examples in context
  9. Try this
  10. Exam-style questions

What this dot point is asking

QCAA wants Year 11 students to describe wave properties, distinguish wave types, apply v=fλv = f\lambda, and identify wave behaviours.

Wave properties

Wavelength λ\lambda (m): distance between successive crests / troughs.

Frequency ff (Hz = 1/s): waves per second.

Period T=1/fT = 1/f (s): time for one wavelength to pass.

Amplitude: maximum displacement from equilibrium. Determines energy.

Wave speed v=fλv = f\lambda.

Transverse vs longitudinal

Transverse. Oscillation perpendicular to propagation direction. Examples: light, water surface, transverse waves on a string.

Longitudinal. Oscillation parallel to propagation. Compressions and rarefactions. Examples: sound, P waves in earthquakes.

Only transverse waves can be polarised.

Sound waves

Longitudinal mechanical wave. Speed in air at 20 degrees C: ∼343\sim 343 m/s. Speed depends on medium (faster in solids than liquids than gases). Requires a medium; cannot travel through vacuum.

Audible range: 20 Hz to 20 kHz (human, declines with age). Below 20 Hz: infrasound. Above 20 kHz: ultrasound.

Intensity in W/m2^2. Loudness in decibels (logarithmic).

Wave behaviours

Reflection
Wave bounces off boundary. Angle of incidence = angle of reflection.
Refraction
Wave changes direction at boundary between media (different speeds).
Diffraction
Wave bends around obstacles or through openings. Greater when wavelength comparable to opening.
Interference
Two waves superpose: constructive (in phase) and destructive (out of phase).
Polarisation
Only transverse waves. Light passing through polariser: I=I0cos⁡2θI = I_0 \cos^2 \theta (Malus's law).

Doppler effect

Apparent frequency change when source and observer move relative to each other.

If source moves toward observer, perceived frequency increases. If away, decreases.

fobserved=fsource(v/(v−vs))f_{\text{observed}} = f_{\text{source}} (v / (v - v_s)) for source moving toward observer at speed vsv_s, with wave speed vv.

Applications: radar speed measurement, medical ultrasound, astronomy (red/blueshift).

Electromagnetic spectrum

All EM waves: transverse, travel at c=3×108c = 3 \times 10^8 m/s in vacuum. Differ in wavelength / frequency.

Region Wavelength
Radio >1> 1 m
Microwave 1 m to 1 mm
Infrared 1 mm to 700 nm
Visible 700 to 400 nm
UV 400 to 10 nm
X-ray 10 nm to 10 pm
Gamma <10< 10 pm

Photon energy E=hfE = hf. Higher frequency = higher energy.

Common errors
Confusing wave types
Light is transverse; sound is longitudinal.
Forgetting medium for sound
Sound requires a medium; cannot travel through vacuum.
Mixing vv and cc
Light in vacuum: cc. Light in medium: c/nc/n where nn is refractive index.
Doppler direction
Approaching: higher frequency. Receding: lower.

Examples in context

Example 1. A Brisbane River ferry sounds a 200 Hz200 \text{ Hz} horn at 30 m s−130 \text{ m s}^{-1} approaching South Bank. A listener on the pontoon hears f′=f×v/(v−vs)=200×340/(340−30)=219 Hzf' = f \times v/(v - v_s) = 200 \times 340/(340-30) = 219 \text{ Hz} - the Doppler effect from the QCAA Unit 2 dot point on sound. The wavelength ahead of the ferry compresses to λ′=(v−vs)/f=1.55 m\lambda' = (v - v_s)/f = 1.55 \text{ m} from the rest-frame 1.70 m1.70 \text{ m}.

Example 2. ANSTO Mt Cotton dishes track 2.2 GHz2.2 \text{ GHz} telemetry from a 7 km s−17 \text{ km s}^{-1} orbital satellite using radial-velocity Doppler. The shift Δf/f≈v/c=2.3×10−5\Delta f / f \approx v/c = 2.3 \times 10^{-5} gives Δf≈51 kHz\Delta f \approx 51 \text{ kHz} - tens of thousands of times the audible Doppler, measurable in real time and used to derive orbital parameters. QCAA EA Unit 2 thematic items hook on this electromagnetic-vs-acoustic parallel.

Try this

Q1. State the electromagnetic spectrum in order of increasing frequency. [2 marks]

  • Cue. Radio, microwave, infrared, visible, ultraviolet, X-ray, gamma.

Q2. A source emits 440 Hz440 \text{ Hz} and moves toward an observer at 20 m s−120 \text{ m s}^{-1} (vsound=340 m s−1v_{sound} = 340 \text{ m s}^{-1}). Calculate the observed frequency. [3 marks]

  • Cue. f′=f×v/(v−vs)=440×340/320=467.5 Hzf' = f \times v/(v - v_s) = 440 \times 340/320 = 467.5 \text{ Hz}.

Q3. A Brisbane River ferry horn at 200 Hz200 \text{ Hz} approaches a stationary listener at 30 m s−130 \text{ m s}^{-1} (vsound=340 m s−1v_{sound} = 340 \text{ m s}^{-1}). (a) Calculate the observed frequency. (b) Calculate the wavelength in front of the moving ferry. (c) Compare with the Doppler-shift of ANSTO satellite radio at 2.2 GHz,v=7 km s−12.2 \text{ GHz}, v = 7 \text{ km s}^{-1}. [3+2+3 marks; ISMG: Knowledge and conceptual understanding, Analysis and interpretation]

  • Cue. (a) 219 Hz219 \text{ Hz}; (b) 1.55 m1.55 \text{ m}; (c) Δf/f≈v/c=2.3×10−5\Delta f/f \approx v/c = 2.3 \times 10^{-5}, Δf≈51 kHz\Delta f \approx 51 \text{ kHz}.

Exam-style questions

Questions in the style of QCAA exam questions on this dot point, each with a worked answer. They are written by ExamExplained unless tagged "Past paper"; the year shows the paper a question is modelled on.

Year 11 SAC-style4 marks
A wave has frequency 440440 Hz and wavelength 0.780.78 m. (a) Find the wave speed. (b) Identify the medium and wave type (sound in air has v≈343v \approx 343 m/s).
Show worked answer →

(a) v=fλ=440×0.78=343v = f\lambda = 440 \times 0.78 = 343 m/s.

(b) This matches the speed of sound in air at 2020 degrees C. The wave is a sound wave in air. Sound is a longitudinal mechanical wave.

Markers reward correct v=fλv = f\lambda application and identification.

Practise this

Sources & how we know this

ExamExplained