Module 7: The Nature of Light

NSWPhysicsSyllabus dot point

Inquiry Question 3: What evidence supports the relativistic model of the universe?

Analyse the Michelson-Morley experiment, state Einstein's two postulates of special relativity, and apply the consequences of time dilation, length contraction and relativity of simultaneity

A focused answer to the HSC Physics Module 7 dot point on light and special relativity. The Michelson-Morley null result, Einstein's two postulates, and quantitative application of time dilation t = gamma t_0, length contraction L = L_0 / gamma and relativity of simultaneity.

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What this dot point is asking

NESA wants you to summarise the Michelson-Morley experiment, state Einstein's two postulates, and apply time dilation and length contraction quantitatively. You should also be able to describe the relativity of simultaneity qualitatively.

The answer

The aether problem and Michelson-Morley

By the late nineteenth century, light was understood as a wave. Waves needed a medium, so physicists postulated the luminiferous aether: a hypothetical, all-pervading substance through which light propagated. The aether was assumed stationary (or close to it), so the Earth must move through it at orbital speed (about 3030 km/s).

Michelson and Morley's interferometer aimed to detect this motion. A beam of monochromatic light was split into two perpendicular paths by a half-silvered mirror, reflected off mirrors at equal distance, and recombined. Any difference in transit time between the two paths would produce interference fringes. Rotating the apparatus by 9090^\circ would swap the "along-aether" and "across-aether" paths and should shift the fringes by a predictable amount (about 0.40.4 of a fringe for the 1887 setup).

The result was null: no significant fringe shift was observed in any orientation, season or location. The experiment was repeated many times with increasing precision, always null. The simplest interpretation: there is no aether.

Einstein's two postulates (1905)

Special relativity rests on just two postulates:

  1. Principle of relativity. The laws of physics are the same in all inertial (non-accelerating) reference frames. No experiment can identify an absolute rest frame.
  2. Constancy of the speed of light. The speed of light in vacuum, cc, is the same in all inertial frames, regardless of the motion of the source or the observer.

The second postulate is the radical one. It immediately removes the need for an aether and makes the Michelson-Morley null result automatic. But it forces strange consequences for space and time.

The Lorentz factor

Most relativistic formulas use:

γ=11v2/c2\gamma = \frac{1}{\sqrt{1 - v^2 / c^2}}

At everyday speeds, γ1\gamma \approx 1 and relativistic effects are negligible. At v=0.5cv = 0.5c, γ1.155\gamma \approx 1.155; at v=0.9cv = 0.9c, γ2.29\gamma \approx 2.29; at v=0.99cv = 0.99c, γ7.09\gamma \approx 7.09.

Time dilation

A clock moving with speed vv relative to an observer ticks slowly compared to a clock at rest with that observer. If the moving clock measures proper time t0t_0 (time between two events at the same place in its own frame), the time interval measured by the stationary observer is:

t=γt0t = \gamma t_0

The classic thought experiment: a light clock bounces a photon between two parallel mirrors a distance L0L_0 apart. In its rest frame the round trip is t0=2L0/ct_0 = 2 L_0 / c. In a frame where the clock moves sideways at speed vv, the photon traces a longer zig-zag path, but still travels at cc (postulate 2). Equating distances gives t=γt0t = \gamma t_0.

Time dilation has been confirmed by atomic clocks flown on aircraft (Hafele-Keating, 1971) and by the increased lifetime of fast-moving muons (covered in evidence-for-special-relativity).

Length contraction

An object moving at speed vv along its length is measured to be shorter than its proper length L0L_0 (the length in its rest frame) by:

L=L0γL = \frac{L_0}{\gamma}

Contraction is only along the direction of motion; perpendicular dimensions are unchanged. Like time dilation, it is real in the sense that any measurement in the observer's frame, made with synchronised rulers, gives the contracted value. There is no internal stress in the object; it is the geometry of spacetime that differs between frames.

Relativity of simultaneity

Two events that are simultaneous in one inertial frame are generally not simultaneous in another moving relative to the first.

Einstein's train thought experiment: lightning strikes both ends of a train simultaneously according to an observer on the embankment. The flashes reach the embankment observer at the same time. But an observer at the centre of the moving train is travelling toward the front flash and away from the back flash, so the front flash reaches them first. Because the speed of light is the same in both frames (postulate 2), the train observer must conclude the front strike happened earlier than the back strike. The two observers disagree on which events were simultaneous.

This is the deepest consequence of the postulates: there is no universal "now". Time ordering of causally connected events (cause before effect) is preserved, but ordering of spacelike-separated events depends on the frame.

Worked example: muon trip

A muon created at the top of the atmosphere (1515 km altitude) travels at 0.998c0.998c toward the ground. Its proper lifetime is 2.22.2 μ\mus.

In the Earth frame: γ=1/10.996=1/0.0632=15.8\gamma = 1 / \sqrt{1 - 0.996} = 1 / 0.0632 = 15.8.

Lifetime as measured from Earth: t=γt0=15.8×2.2×106=3.48×105t = \gamma t_0 = 15.8 \times 2.2 \times 10^{-6} = 3.48 \times 10^{-5} s.

Distance the muon can cover: d=vt=0.998×3.0×108×3.48×105=1.04×104d = v t = 0.998 \times 3.0 \times 10^8 \times 3.48 \times 10^{-5} = 1.04 \times 10^4 m =10.4= 10.4 km.

Without dilation, the muon would only travel 660660 m in 2.22.2 μ\mus and almost none would reach the surface. Time dilation explains why many do.

In the muon's frame, the atmosphere is contracted: L=15 km/15.8=0.95L = 15 \text{ km} / 15.8 = 0.95 km, so it can cover the (now-much-shorter) distance in its proper lifetime. Both frames agree on the outcome (muons reach the ground) via different mechanisms.

Common traps

Applying time dilation backwards. The moving clock measures the proper time t0t_0 (the shorter interval). The observer who sees the clock moving measures t=γt0t = \gamma t_0 (longer interval).

Applying length contraction backwards. The object at rest in some frame has the proper length L0L_0 in that frame. Any frame that sees the object moving measures a shorter length.

Confusing proper time with elapsed coordinate time. Proper time is between two events at the same place in some frame. Coordinate time depends on the synchronisation of clocks at different places.

Treating γ\gamma as something that can be smaller than 1. γ1\gamma \geq 1 always, equal to 1 only when v=0v = 0.

Saying "moving clocks run slow because of physical effects on their mechanism". Any clock (mechanical, atomic, biological) is dilated equally because it is a property of time itself, not of the clock.

In one sentence

The Michelson-Morley null result removed the aether, and Einstein's two postulates (the laws of physics are the same in all inertial frames; cc is invariant) yield time dilation t=γt0t = \gamma t_0, length contraction L=L0/γL = L_0 / \gamma and relativity of simultaneity, where γ=1/1v2/c2\gamma = 1 / \sqrt{1 - v^2/c^2}.

Past exam questions, worked

Real questions from past NESA papers on this dot point, with our answer explainer.

2023 HSC5 marksA spacecraft travels at 0.80c relative to Earth. Its proper length (measured in its own rest frame) is 50 m and a clock on board ticks off 1.0 hour during a journey segment. Calculate the length of the spacecraft and the elapsed time as measured by an Earth observer, and explain the meaning of 'proper time' and 'proper length'.
Show worked answer →

Lorentz factor at v=0.80cv = 0.80c:

γ=1/1v2/c2=1/10.64=1/0.36=1/0.6=5/31.667\gamma = 1 / \sqrt{1 - v^2/c^2} = 1 / \sqrt{1 - 0.64} = 1 / \sqrt{0.36} = 1 / 0.6 = 5/3 \approx 1.667.

Length contraction (Earth observer sees the moving ship as contracted along its direction of motion):

L=L0/γ=50/1.667=30L = L_0 / \gamma = 50 / 1.667 = 30 m.

Time dilation (Earth observer sees the moving clock running slow, so the same on-board interval corresponds to a longer Earth interval):

t=γt0=1.667×1.0=1.67t = \gamma t_0 = 1.667 \times 1.0 = 1.67 h.

Proper time t0t_0: the time interval between two events that occur at the same location in some frame, measured by a clock at rest in that frame. The on-board clock measures proper time for events happening on the spacecraft.

Proper length L0L_0: the length of an object measured in the rest frame of the object. The on-board crew measures proper length.

Markers reward correct γ\gamma, both calculations, and clear definitions linking proper time and length to the rest frame of the observed system. A common error is to apply the contraction the wrong way (Earth observer sees a shorter ship, not a longer one).

2020 HSC3 marksOutline the Michelson-Morley experiment and explain how its null result was a key piece of evidence for special relativity.
Show worked answer →

A Michelson interferometer splits a beam of monochromatic light into two perpendicular paths, reflects each off a mirror, and recombines them to form an interference pattern. Michelson and Morley (1887) aimed to detect the Earth's motion through the hypothesised "luminiferous aether", a medium thought necessary for light to propagate.

Reasoning: if the Earth moves through a stationary aether at speed vv, light travelling parallel to that motion takes a different round-trip time from light travelling perpendicular to it. Rotating the apparatus would change which path was "along the wind" and shift the interference fringes by a predictable amount.

Result: no fringe shift was observed (or only one far smaller than predicted) regardless of orientation or time of year. This null result implied no aether wind exists, which conflicted with the wave model that required a medium.

Significance for special relativity: Einstein's second postulate, that the speed of light in vacuum is the same in all inertial frames, makes the Michelson-Morley null result automatic; there is no aether and no preferred frame to detect.

Markers reward correct description of the apparatus, the expected versus observed result, and the link to Einstein's postulate.

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