Quick questions on Mass-energy equivalence E = mc^2 and nuclear binding energy: HSC Physics Module 7

Splitting the total energy gives kinetic energy as:

For atomic and nuclear calculations, the unified atomic mass unit is convenient:

For comparison, chemical-bond energies are of order eV per molecule, six orders of magnitude smaller than nuclear binding energies. That is why nuclear reactions release millions of times more energy per atom than chemical reactions.

$\Delta m = (m_p + m_n) - m_d = (1.00728 + 1.00866) - 2.01355 = 2.39 \times 10^{-3}$ u. $E_b = 2.39 \times 10^{-3} \times 931.5 = 2.23$ MeV. Per nucleon: $1.11$ MeV.

$\Delta m \approx 0.528$ u. $E_b \approx 492$ MeV. Per nucleon: $\approx 8.79$ MeV - the peak of the binding-energy curve.

When U-235 captures a neutron and fissions into Ba-141 + Kr-92 + 3 neutrons, the mass defect is approximately $0.215$ u, giving about $200$ MeV per fission event. A reactor running at $1$ GW thermal fissions about $3 \times 10^{19}$ U-235 atoms per second.