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NSWMaths Standard 2Syllabus dot point

How is the 10% GST added to a price and then pulled back out of a GST-inclusive total, and why do percentage changes only behave predictably when you treat them as multipliers?

Add the 10% GST to a pre-GST price, find the GST contained in a GST-inclusive total and the pre-GST price, calculate percentage increases and decreases, and combine successive percentage changes using multipliers

The HSC Maths Standard 2 method for GST and percentage change. Add the 10% GST with x 1.1, extract the GST from an inclusive total with /11 and the pre-GST price with /1.1, do percentage increases and decreases as multipliers, and combine successive changes by multiplying, with code-checked Australian examples and a GST split-bar diagram.

Generated by Claude Opus 4.815 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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What this dot point is asking

NESA wants two closely linked skills here. The first is the Goods and Services
Tax (GST)
: a flat 10%10\% tax the Australian Government adds to most goods and
services. You must be able to add the GST to a price. Just as often, you must
work backwards from a GST-inclusive total (a price that already has the tax in
it). From that total you find either the GST it contains or the price before GST.
The second skill is percentage change: increasing or decreasing a quantity by
a percentage, and combining several such changes one after another. One idea ties
both topics together and makes them click. That idea is the multiplier: a
single number you multiply by. Every percentage change is one of these multipliers,
and that is also exactly how GST works.

This is strictly Year 11 Money Matters (MS-F1). The arithmetic is percentages you
already have; what is examined is choosing the right operation, especially the
direction of a GST calculation and what to do when changes are stacked.

The answer

Everything on this page reduces to one move: turn the percentage into a
multiplier and multiply.

  • Adding the GST. The GST is 10%10\% of the pre-GST price. To add it, find
    10%10\% and add it on, or in one step multiply the pre-GST price by 1.11.1 (which
    is 100%+10%=110%100\% + 10\% = 110\%):

GST-inclusive total=pre-GST price×1.1.\text{GST-inclusive total} = \text{pre-GST price} \times 1.1.

  • Finding the GST inside an inclusive total. Because the price was multiplied
    by 1.11.1, the GST is one eleventh of the inclusive total, so divide by 1111:

GST contained=GST-inclusive total÷11.\text{GST contained} = \text{GST-inclusive total} \div 11.

  • Finding the pre-GST price from an inclusive total. Undo the ×1.1\times 1.1 by
    dividing by 1.11.1:

pre-GST price=GST-inclusive total÷1.1.\text{pre-GST price} = \text{GST-inclusive total} \div 1.1.

  • A percentage increase or decrease of rr (written as a decimal) multiplies
    the amount by (1+r)(1 + r) for an increase or (1r)(1 - r) for a decrease:

new amount=original×(1+r)ororiginal×(1r).\text{new amount} = \text{original} \times (1 + r) \quad\text{or}\quad \text{original} \times (1 - r).

  • Successive percentage changes multiply their multipliers. Apply each change
    in turn, or just multiply the multipliers together once:

final=original×m1×m2×\text{final} = \text{original} \times m_1 \times m_2 \times \cdots

Adding the GST: multiply by 1.1

To add the 10%10\% GST you can find 10%10\% and add it on. It is faster and safer,
though, to multiply the pre-GST price by 1.11.1 in a single step. This works because
100%100\% of the price plus another 10%10\% is 110%=1.1110\% = 1.1. A plumber who quotes
$680 excluding GST adds 0.10×680=680.10 \times 680 = 68, i.e. $68.00 of GST, for a
total of 680×1.1=748680 \times 1.1 = 748, i.e. $748.00. The two routes agree because
680+68=748680 + 68 = 748. Quotes from tradespeople are very often given "plus GST", so
adding the GST is the everyday calculation.

Working backwards: the divide-by-11 method

The trap that catches the most students is going backwards from a price that
already includes GST. Suppose a receipt total is $88.00, GST included. The GST
is not 10%10\% of $88; that would give $8.80, which is too much. The
$88 is 110%110\% of the pre-GST price, so the pre-GST price is
88÷1.1=8088 \div 1.1 = 80, i.e. $80.00, and the GST is the remaining
8880=888 - 80 = 8, i.e. $8.00. The shortcut is to divide the inclusive total by
1111 directly: 88÷11=888 \div 11 = 8.

Here is why ÷11\div 11 works. The inclusive total is the pre-GST price times
1.1=11101.1 = \tfrac{11}{10}, and the GST is the pre-GST price times
0.1=1100.1 = \tfrac{1}{10}. So the GST as a fraction of the inclusive total is

1101110=111,\frac{\tfrac{1}{10}}{\tfrac{11}{10}} = \frac{1}{11},

i.e. the GST is exactly 111\tfrac{1}{11} of any GST-inclusive total, about
9.09%9.09\% of it, never 10%10\% of it. The bar below splits a GST-inclusive grocery
and homewares receipt of $132.00 into its pre-GST price and its GST.

A GST-inclusive total split into the pre-GST price and the GSTA horizontal bar representing a GST-inclusive receipt total of 132 dollars. The bar is divided into two parts: a large pre-GST part of 120 dollars, which is ten elevenths of the bar, and a small GST part of 12 dollars, which is one eleventh of the bar. The 12 dollar GST equals the 132 dollar total divided by 11, and the 120 dollar pre-GST price equals the total divided by 1.1.Pre-GST price$120.00GST$12.00GST-inclusive total $132.00GST = total ÷ 11 = $12.00pre-GST = total ÷ 1.1 = $120.00

For the $132.00 receipt, the GST is 132÷11=12132 \div 11 = 12, i.e. $12.00, and the
pre-GST price is 132÷1.1=120132 \div 1.1 = 120, i.e. $120.00. The bar shows the GST as a
single skinny eleventh sitting beside the ten parts of pre-GST price: that picture
is the whole reason the GST is the total divided by 1111, not by 1010.

Percentage change as a multiplier

A percentage increase or decrease is the same idea as adding GST, just with
a different rate. To change an amount by rr (the rate as a decimal), multiply by
(1+r)(1 + r) to increase or (1r)(1 - r) to decrease. The number you multiply by is the
multiplier. A $1450 laptop discounted by 30%30\% keeps
100%30%=70%100\% - 30\% = 70\% of its price, so the sale price is
1450×0.70=10151450 \times 0.70 = 1015, i.e. $1015.00, and the saving is the rest,
14501015=4351450 - 1015 = 435, i.e. $435.00. An hourly rate of $24.80 raised by
3.5%3.5\% becomes 24.80×1.035=25.6724.80 \times 1.035 = 25.67, i.e. $25.67. Going through the
multiplier is one calculation; finding the change and then adding or subtracting it
is two, with two chances to slip.

The multiplier also lets you find a percentage change from two prices: divide
the new by the old to get the multiplier, then read off the rate. If rent rises
from $540 to $580.50 a week, the multiplier is
580.50÷540=1.075580.50 \div 540 = 1.075, so the increase is 0.075=7.5%0.075 = 7.5\%.

Successive percentage changes: multiply the multipliers

When two or more percentage changes happen one after another, you apply each to the
result of the previous one, never to the original. The clean way is to multiply
the multipliers together. This is where students lose marks by adding
percentages, which is always wrong. You see this stacking everywhere. A shop marks
an item up then runs a sale on the new price. A price rises one year and falls the
next. A sale takes a discount and then a further discount at the register. The
diagram traces a sound system originally $480.00 through a 20%20\% discount and
then a further 10%10\% discount.

Successive percentage changes multiply their multipliersA left-to-right chain of three values. An original price of 480 dollars is multiplied by 0.80 (a 20 percent decrease) to give 384 dollars, then multiplied by 0.90 (a further 10 percent decrease) to give 345.60 dollars. The two multipliers combine as 0.80 times 0.90 equals 0.72, a single 28 percent discount applied to the original 480 dollars.original price$480.00after 20% off$384.00after a further 10% off$345.60× 0.80× 0.90combined: × 0.80 × 0.90 = × 0.72 (a single 28% discount, not 30%)

After the first discount the price is 480×0.80=384480 \times 0.80 = 384, i.e. $384.00.
The further 10%10\% comes off that figure: 384×0.90=345.60384 \times 0.90 = 345.60, i.e.
$345.60. Combining the multipliers gives 0.80×0.90=0.720.80 \times 0.90 = 0.72, so the two
discounts together are a single ×0.72\times 0.72, which keeps 72%72\% of the price and
so is a 28%28\% discount overall, not the 30%30\% you would get by adding
20%+10%20\% + 10\%. Two discounts never add, because the second one acts on an
already-reduced price.

The same logic explains why a price that goes up then down by the same percentage
does not return to where it started. Raise $200 by 10%10\% to get
200×1.1=220200 \times 1.1 = 220, i.e. $220.00, then drop it by 10%10\%:
220×0.9=198220 \times 0.9 = 198, i.e. $198.00. The combined multiplier is
1.1×0.9=0.991.1 \times 0.9 = 0.99, a net fall of 1%1\%, because the 10%10\% fall is taken
from the larger $220 and so removes more than the 10%10\% rise added.

How exam questions ask about this

Each wording points to one of the moves above. Learn the translation:

  • "A 10%10\% GST is added. Find the GST / the total price." Multiply the pre-GST
    price by 0.100.10 for the GST, or by 1.11.1 for the total.
  • "This price includes GST. How much GST is included?" Divide the inclusive
    total by 1111.
  • "This price includes GST. What was the price before GST?" Divide the
    inclusive total by 1.11.1.
  • "Increase / decrease ... by ... %." Multiply by (1+r)(1 + r) to increase or
    (1r)(1 - r) to decrease.
  • "Find the percentage increase / decrease" (given two prices). Divide the new
    amount by the old to get the multiplier, subtract 11, and convert to a percent;
    or divide the change by the original amount.
  • "... and then ..." (one change after another). Apply each change to the
    previous result, or multiply the multipliers together.
  • "What single discount has the same effect?" Multiply the multipliers, then
    the single discount is 100%100\% minus the combined multiplier as a percent.

Edge case: GST-free items and "plus GST" quotes

Two practical points sit just inside the syllabus. First, not everything carries
GST. Basic foods (plain bread, milk, fresh fruit and vegetables) and some health
and education items are GST-free, so a receipt can mix taxed and untaxed lines
and the GST is 111\tfrac{1}{11} only of the taxable part, not of the whole
total. An exam will tell you which items are taxable. Second, watch the wording of
a price. "$680 plus GST" means $680 is the pre-GST price and you add GST to
get 680×1.1=748680 \times 1.1 = 748, i.e. $748.00; "$680 including GST" means the
$680 is already the inclusive total and the GST inside it is
680÷1161.82680 \div 11 \approx 61.82, i.e. about $61.82. Reading which one a question
gives you decides whether you multiply by 1.11.1 or divide by 1111.

Exam-style practice questions

Practice questions written in the style of NESA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

2021 HSC-style3 marksAn electrician's invoice lists labour and parts of $760 before GST. A 10%10\% GST is then added. Calculate the GST, the total the customer pays, and the percentage the GST is of the final invoice, correct to two decimal places.
Show worked answer →

Find the GST. The GST is 10%10\% of the pre-GST amount, so multiply by 0.100.10. (1 mark)

0.10×760=76.0.10 \times 760 = 76.

Find the total invoice. Add the GST, or multiply the pre-GST amount by 1.11.1 in one step. (1 mark)

760×1.1=836.760 \times 1.1 = 836.

Find the GST as a percentage of the final invoice. Divide the GST by the inclusive total. (1 mark)

76836×100=9.09% (2 d.p.).\frac{76}{836} \times 100 = 9.09\% \text{ (2 d.p.)}.

State the answer. The GST is $76.00, the total invoice is $836.00, and the GST is 9.09%9.09\% of that inclusive total. Note the GST is 10%10\% of the pre-GST figure but only about 9.09%9.09\% (one eleventh) of the GST-inclusive total. Marker note: full marks require the $1.1 method or an explicit add, plus the final percentage on the inclusive base, not the pre-GST base.

2022 HSC-style3 marksA homewares store issues a receipt with a GST-inclusive total of $946. Calculate the GST contained in the receipt and the total price before GST, justifying why you divide by 1111 and not by 1010.
Show worked answer →

Find the GST contained. The inclusive total is the pre-GST price times 1.11.1, so the GST is one eleventh of that total; divide by 1111. (1 mark)

946÷11=86.946 \div 11 = 86.

Find the pre-GST price. Divide the inclusive total by 1.11.1 to undo the added GST. (1 mark)

946÷1.1=860.946 \div 1.1 = 860.

Justify the divide by 1111
The GST is 110\dfrac{1}{10} of the pre-GST price while the inclusive total is 1110\dfrac{11}{10} of it, so the GST as a fraction of the inclusive total is 1/1011/10=111\dfrac{1/10}{11/10} = \dfrac{1}{11}, not 110\dfrac{1}{10}. (1 mark)
Check
The GST should be 10%10\% of the pre-GST price: 0.10×860=860.10 \times 860 = 86, and 860+86=946860 + 86 = 946. Everything ties out.
State the answer
The receipt contains $86.00 of GST on a pre-GST price of $860.00. Dividing $946 by 1010 would wrongly give $94.60; the GST in a GST-inclusive total is always the total divided by 1111. Marker note: award the justification mark only for a clear one eleventh argument, not merely the arithmetic.
2023 HSC-style4 marksA bracket of jewellery is ticketed at $1600. The store first marks it up by 25%25\%, then a week later runs a sale taking 20%20\% off the marked-up price. Find the price after each change, find the overall percentage change from $1600, and explain the result using the combined multiplier.
Show worked answer →

Apply the markup. A 25%25\% increase multiplies by 1+0.25=1.251 + 0.25 = 1.25. (1 mark)

1600×1.25=2000.1600 \times 1.25 = 2000.

Apply the sale to the marked-up price. A 20%20\% discount multiplies by 10.20=0.801 - 0.20 = 0.80, acting on the $2000, not the original $1600. (1 mark)

2000×0.80=1600.2000 \times 0.80 = 1600.

Combine the multipliers. Over the two changes the price is multiplied by (1 mark)

1.25×0.80=1.00,1.25 \times 0.80 = 1.00,

so the overall change is 0%0\%: the price returns to $1600.

Explain. It looks like a 5%5\% gain (25%20%25\% - 20\%), but percentage changes never add. The 20%20\% cut is taken from the larger $2000, removing $400, exactly cancelling the $400 the markup added. Because 1.25×0.80=1.001.25 \times 0.80 = 1.00, the net effect is no change. (1 mark)

State the answer. The price is $2000.00 after the markup and $1600.00 after the sale, an overall change of 0%0\%. The combined multiplier 1.25×0.80=1.001.25 \times 0.80 = 1.00 shows the two changes cancel, not add to +5%+5\%. Marker note: the final mark needs the multiplier reasoning, not just the observation that the price matches.

Practice questions

Original practice questions graded from foundation to exam level, each with a full worked solution. Try them before revealing the solution.

foundation2 marksA plumber quotes $320 for a job, excluding GST. A 10%10\% GST is then added. Calculate the GST and the total price the customer pays.
Show worked solution →

Find the GST. The GST is 10%10\% of the pre-GST price, so multiply by 0.100.10.

0.10×320=32.0.10 \times 320 = 32.

Find the total price. Add the GST to the pre-GST price, or multiply the pre-GST price by 1.11.1 in one step.

320×1.1=352.320 \times 1.1 = 352.

State the answer. The GST is $32.00 and the total price is $352.00. Adding GST always multiplies the pre-GST price by 1.11.1, never by 1.101.10 of some other figure.

foundation3 marksA restaurant bill of $451 already includes the 10%10\% GST. Calculate the GST contained in the bill and the price before GST was added.
Show worked solution →

Find the GST contained in the total. Because the price was multiplied by 1.11.1, the GST is one eleventh of the inclusive total, so divide by 1111 (not by 1010).

451÷11=41.451 \div 11 = 41.

Find the pre-GST price. Divide the inclusive total by 1.11.1 to undo the GST.

451÷1.1=410.451 \div 1.1 = 410.

Check. The GST should be 10%10\% of the pre-GST price: 0.10×410=410.10 \times 410 = 41, and 410+41=451410 + 41 = 451. Everything ties out.

State the answer. The bill contains $41.00 of GST on a pre-GST price of $410.00. Dividing the $451 by 1010 would wrongly give $45.10; the GST in an inclusive total is always the total divided by 1111.

core3 marksA laptop is marked at $1260. In a sale it is discounted by 15%15\%. Calculate the discount and the sale price using a multiplier.
Show worked solution →

Write the multiplier for a decrease. A 15%15\% decrease keeps 100%15%=85%100\% - 15\% = 85\%, so the multiplier is 10.15=0.851 - 0.15 = 0.85.

Find the sale price in one step.

1260×0.85=1071.1260 \times 0.85 = 1071.

Find the discount. The discount is the amount taken off, 15%15\% of the marked price.

0.15×1260=189.0.15 \times 1260 = 189.

Check. The sale price plus the discount should rebuild the marked price: 1071+189=12601071 + 189 = 1260.

State the answer. The discount is $189.00 and the sale price is $1071.00. Multiplying by 0.850.85 jumps straight to the sale price, which is faster and less error prone than finding the discount and subtracting.

core2 marksAn employee on $86.40 an hour is given a 2.5%2.5\% pay rise. Calculate the new hourly rate, correct to the nearest cent.
Show worked solution →

Write the multiplier for an increase. A 2.5%2.5\% increase makes the rate 100%+2.5%=102.5%100\% + 2.5\% = 102.5\% of the old rate, so the multiplier is 1+0.025=1.0251 + 0.025 = 1.025.

Apply the multiplier.

86.40×1.025=88.56.86.40 \times 1.025 = 88.56.

State the answer. The new hourly rate is $88.56. (Check: the rise is 0.025×86.40=2.160.025 \times 86.40 = 2.16, and 86.40+2.16=88.5686.40 + 2.16 = 88.56.) Writing a percentage increase as the multiplier 1+r1 + r turns a two-step calculation into one.

exam4 marksA share is bought at $50.00. In one week its price rises by 20%20\%; the next week it falls by 20%20\%. Find the price after each change, and explain why the share is not back at $50.00.
Show worked solution →

Apply the first change. A 20%20\% rise multiplies by 1+0.20=1.201 + 0.20 = 1.20.

50.00×1.20=60.00.50.00 \times 1.20 = 60.00.

Apply the second change. A 20%20\% fall multiplies by 10.20=0.801 - 0.20 = 0.80, applied to the new $60.00 price, not the original.

60.00×0.80=48.00.60.00 \times 0.80 = 48.00.

Combine the multipliers. The two changes together multiply by

1.20×0.80=0.96,1.20 \times 0.80 = 0.96,

so the share ends at 50.00×0.96=48.0050.00 \times 0.96 = 48.00, a net fall of 4%4\%.

Explain. The 20%20\% fall is taken from the higher $60.00, so it removes $12.00, more than the $10.00 the rise added. A rise then an equal-percentage fall always lands below the start because the fall acts on a larger amount.

State the answer. The price is $60.00 after the rise and $48.00 after the fall, a $2.00 (or 4%4\%) loss overall, because 1.20×0.80=0.96<11.20 \times 0.80 = 0.96 < 1.

exam4 marksA landscaper buys materials for a job. The hardware receipt total is &#36;924, which already includes the 10%10\% GST. She passes the materials on at their pre-GST price plus her own 30%30\% markup, then adds GST to that. Calculate the pre-GST cost of the materials and the final GST-inclusive price she charges the client.
Show worked solution →

Find the pre-GST cost of the materials. The $924 already includes GST, so divide by 1.11.1 to strip it out.

924÷1.1=840.924 \div 1.1 = 840.

So the materials cost $840.00 before GST. (Check: the GST contained is 924÷11=84924 \div 11 = 84, and 840+84=924840 + 84 = 924.)

Apply the markup. A 30%30\% markup multiplies the pre-GST cost by 1+0.30=1.301 + 0.30 = 1.30.

840×1.30=1092.840 \times 1.30 = 1092.

Add GST to the marked-up price. Multiply by 1.11.1.

1092×1.1=1201.20.1092 \times 1.1 = 1201.20.

State the answer. The materials cost $840.00 before GST, and the client is charged $1201.20 including GST. The trap is marking up the $924 inclusive figure; the markup belongs on the $840 pre-GST cost, with GST added once at the end.

exam4 marksA clearance sale takes 30%30\% off the ticket price, then takes a further 10%10\% off at the register. A dishwasher is ticketed at &#36;2400. Find the final price, and find the single percentage discount that has the same effect. Explain why it is not 40%40\%.
Show worked solution →

Apply the first discount. A 30%30\% discount multiplies by 10.30=0.701 - 0.30 = 0.70.

2400×0.70=1680.2400 \times 0.70 = 1680.

Apply the second discount. A further 10%10\% off multiplies the new price by 10.10=0.901 - 0.10 = 0.90.

1680×0.90=1512.1680 \times 0.90 = 1512.

Combine the multipliers. The two discounts together multiply by

0.70×0.90=0.63.0.70 \times 0.90 = 0.63.

Find the single equivalent discount
Keeping 63%63\% of the price means taking off 100%63%=37%100\% - 63\% = 37\%.
Explain
The second 10%10\% comes off the already reduced $1680, not the original $2400, so it removes less than a flat 10%10\% of $2400 would. Discounts never add; you multiply the multipliers, here 0.70×0.90=0.630.70 \times 0.90 = 0.63, giving 37%37\% off rather than 40%40\%.
State the answer
The final price is $1512.00, the same as a single 37%37\% discount on $2400, not 40%40\%.

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