Skip to main content
NSWMaths Standard 2Syllabus dot point

Which statistical chart best displays a set of data, and how do you construct and read column, sector, line and Pareto charts correctly?

Display categorical and numerical data using a range of statistical graphs, including column graphs, sector graphs, line graphs, divided bar graphs and Pareto charts, and interpret the displays

A focused answer to the HSC Maths Standard 2 dot point on statistical graphs. Column and bar graphs, sector (pie) graphs with each angle computed as a fraction of 360 degrees, line graphs, divided bar graphs, and the Pareto chart with bars sorted descending and a cumulative percentage line for the 80/20 read, with worked Australian examples.

Generated by Claude Opus 4.814 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

Have a quick question? Jump to the Q&A page

What this dot point is asking

NESA wants you to display a set of data with the right kind of statistical graph, and to read information back out of one. You need four everyday chart types - the column (or bar) graph, the sector (pie) graph, the line graph and the divided bar graph - plus one chart that trips students up, the Pareto chart. The skill being marked is twofold: choosing the chart that suits the data (parts of a whole, change over time, or comparing categories), and constructing or reading it accurately. The arithmetic is light. Marks are won and lost on two things: computing a sector angle as a fraction of 360360^{\circ} correctly, and building the Pareto chart's cumulative-percentage line in the right order. Get those two right and this dot point is reliable marks.

The answer

Different data calls for a different chart. A column graph compares the sizes of separate categories with equal-width bars (heights show frequency). A sector graph and a divided bar graph both split one total into parts of a whole. A line graph shows a single quantity changing over time, with the points joined so a trend is visible. The Pareto chart is a column graph with its bars sorted from tallest to shortest, plus a line tracking the running (cumulative) percentage, used to find the few categories that make up most of the total. The one calculation that runs through this whole topic is turning a fraction of the data into a piece of a chart.

Column and bar graphs

A column graph (vertical bars) or bar graph (horizontal bars) compares separate categories. Every bar has the same width and a gap between bars, because the categories are distinct, not a continuous scale. The bar's height (or length) shows the frequency, read against an axis that should start at zero so the heights are not misleading. Use a column or bar graph when the question gives you counts for several named categories (sports played, drinks sold, votes per party) and asks you to compare them.

Sector (pie) graphs: computing the angles

A sector graph is a circle divided into wedges, one per category, where each wedge's angle is the category's share of the full 360360^{\circ} turn. To construct one, find each angle with the rule

angle=frequencytotal×360,\text{angle} = \frac{\text{frequency}}{\text{total}} \times 360^{\circ},

then draw the wedges with a protractor from largest to smallest. The diagram below shows the method for how 6060 students travel to school.

Sector graph of how sixty students travel to schoolA circle split into five wedges sized by how sixty students travel: car twenty students is one hundred and twenty degrees, bus fifteen is ninety degrees, walk twelve is seventy-two degrees, train nine is fifty-four degrees and bicycle four is twenty-four degrees. The car wedge is annotated with the calculation twenty over sixty times three hundred and sixty equals one hundred and twenty degrees.Sector angle = (frequency ÷ total) × 360°Car120°Bus90°Walk72°Train54°Bike24°Car sector20 ÷ 60 × 360°= 0.333... × 360°= 120°

For these data the five angles are 120120^{\circ} (car), 9090^{\circ} (bus), 7272^{\circ} (walk), 5454^{\circ} (train) and 2424^{\circ} (bicycle), and as a check they total 120+90+72+54+24=360120 + 90 + 72 + 54 + 24 = 360^{\circ}. A sector graph is the right choice when the question gives the parts of a single whole and asks for each part's share, but it is poor for comparing two separate data sets or for showing change over time.

Divided bar graphs

A divided bar graph carries the same "parts of a whole" idea as a sector graph, but along a single bar instead of around a circle. Each category's segment length is its fraction of the bar's total length:

segment length=frequencytotal×(bar length).\text{segment length} = \frac{\text{frequency}}{\text{total}} \times \text{(bar length)}.

So if the 6060 students above were shown on a divided bar 300300 mm long, the car segment would be 2060×300=100\tfrac{20}{60} \times 300 = 100 mm, the bus segment 1560×300=75\tfrac{15}{60} \times 300 = 75 mm, and so on. The segments must fill the bar exactly, just as the sector angles must fill the circle.

Line graphs

A line graph plots points for a quantity measured over time and joins them with straight segments, so the rises, falls and overall trend stand out. Time goes on the horizontal axis. To read a value, find the time on the horizontal axis, go up to the line, then across to the vertical axis. To find a change between two times, read both values and subtract. Use a line graph for time-series data such as monthly rainfall, yearly recycling tonnage or daily temperature; do not use it for separate categories (that is a column graph's job).

Pareto charts: bars sorted, plus a cumulative line

A Pareto chart combines a column graph and a line graph to answer one question: which few categories cause most of the total? You build it in a fixed order:

  1. Sort the categories by frequency, largest first.
  2. Draw the bars in that order against the left (frequency) axis.
  3. Work out the cumulative percentage after each bar - a running total of frequency, divided by the grand total, times 100100 - and plot it against a right-hand axis running 00 to 100%100\%.
  4. Join the cumulative points with a line; it always ends at 100%100\%.

The cumulative line lets you apply the 80/20 principle (the Pareto principle): often about 80%80\% of the effect comes from about 20%20\% of the causes. You read off how many of the leading categories you must add before the cumulative line reaches (say) 80%80\% - those are the "vital few" worth acting on. The build below uses a month of customer complaints, total 200200.

Pareto chart of two hundred customer complaints by causeFive bars sorted largest to smallest: late delivery ninety, wrong item fifty-four, damaged thirty, billing error sixteen, other ten. A cumulative percentage line rises through forty-five, seventy-two, eighty-seven, ninety-five and one hundred percent, read on the right axis, with the eighty percent level marked by a dashed line that the cumulative line crosses at the third bar.frequencycumulative %0204060801000408010080% level905430161045%72%87%95%Late del.WrongDamagedBillingOtherTop 2 of 5 causes = 72% of complaints; cumulative line crosses 80% at the 3rd bar.

The cumulative line for these complaints reads 45%45\%, 72%72\%, 87%87\%, 95%95\%, 100%100\%. It crosses the 80%80\% level at the third bar, so the top three causes (late delivery, wrong item, damaged goods) account for 87%87\% of all complaints. The first two alone are 72%72\%. That is the 80/20 read: a handful of causes drives almost everything, so a manager should fix those first.

How exam questions ask about statistical charts

The wording tells you which chart and which calculation:

  • "Find the angle of the ... sector" or "construct a sector graph" means use frequencytotal×360\dfrac{\text{frequency}}{\text{total}} \times 360^{\circ} for each category, and check the angles total 360360^{\circ}.
  • "What length is the ... segment" on a divided bar means the same fraction times the bar's length, not 360360^{\circ}.
  • "Read off ... from the line graph" means trace up from the time axis to the line and across; "find the change / increase / decrease" means read two values and subtract; "percentage increase" means change over the original times 100100.
  • "Construct a Pareto chart" or "complete the cumulative percentage column" means sort largest first, keep a running total, and convert each to a percentage of the grand total.
  • "How many causes account for 80%80\% ..." or "use the 80/20 principle" means read the cumulative line (not the individual bars) and count the leading categories up to 80%80\%.
  • "Which graph is most appropriate ..." means match the data to the chart: parts of a whole (sector or divided bar), change over time (line), comparing categories (column).

Exam-style practice questions

Practice questions written in the style of NESA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

2022 HSC-style4 marksA sports club surveys its 9090 members on their main sport: 4545 play netball, 3030 play soccer and 1515 play cricket. (a) Find the angle of each sector for a sector graph. (b) Confirm the angles add to 360360^{\circ}.
Show worked answer →

Each angle is frequency over total, times 360360^{\circ}, with total 9090.

Netball: 4590×360=180\tfrac{45}{90} \times 360 = 180^{\circ}. Soccer: 3090×360=120\tfrac{30}{90} \times 360 = 120^{\circ}. Cricket: 1590×360=60\tfrac{15}{90} \times 360 = 60^{\circ}.

Check: 180+120+60=360180 + 120 + 60 = 360^{\circ}.

Markers award one mark for the correct method (fraction times 360360), marks for the three correct angles, and a mark for the closing check that they total a full turn. A common error is dividing by 360360 instead of multiplying, or forgetting to total to 360360^{\circ}.

2023 HSC-style5 marksA help desk logs 400400 support tickets by category: password 180180, login 100100, payment 6060, app crash 4040, other 2020. (a) Find the cumulative percentage after each category for a Pareto chart. (b) State how many categories account for at least 80%80\% of tickets. (c) Explain what the 80/20 read tells the manager.
Show worked answer →

Sorted descending already. Cumulative percentages of the total 400400:

Password 180400×100=45%\tfrac{180}{400} \times 100 = 45\%; + login 280400×100=70%\tfrac{280}{400} \times 100 = 70\%; + payment 340400×100=85%\tfrac{340}{400} \times 100 = 85\%; + app crash 380400×100=95%\tfrac{380}{400} \times 100 = 95\%; + other 100%100\%.

The cumulative line first reaches at least 80%80\% at the third category (payment, 85%85\%), so the top 33 categories account for at least 80%80\% of tickets.

The 80/20 read tells the manager that a small number of categories (here 33 of 55) cause most of the tickets, so focusing effort on password, login and payment issues will resolve the great majority of the workload.

Markers award marks for correct cumulative percentages, the correct count of categories reaching 80%80\%, and a sensible interpretation naming the "vital few" causes. Watch for using individual rather than cumulative percentages in part (b).

Practice questions

Original practice questions graded from foundation to exam level, each with a full worked solution. Try them before revealing the solution.

foundation2 marksA survey of 4040 people records their favourite sport. Soccer was chosen by 1414 people. For a sector (pie) graph, find the angle of the soccer sector, correct to the nearest degree.
Show worked solution →

Write the sector angle as a fraction of the whole turn. The soccer sector is the fraction of the 360360^{\circ} turn equal to the fraction of people who chose soccer:

angle=frequencytotal×360=1440×360\text{angle} = \frac{\text{frequency}}{\text{total}} \times 360^{\circ} = \frac{14}{40} \times 360^{\circ}

Evaluate.

1440×360=14×9=126\frac{14}{40} \times 360 = 14 \times 9 = 126

so the soccer sector has an angle of 126126^{\circ}. (Sanity check: 1414 out of 4040 is a bit more than a third, and 126126^{\circ} is a bit more than 120120^{\circ}, which is a third of a turn, so the size is right.)

foundation2 marksA line graph shows a shop's monthly rainfall takings. The line passes through (Feb,95)(\text{Feb}, 95) and (Apr,110)(\text{Apr}, 110), where the values are in millimetres. (a) Read the rainfall in April. (b) Find the change in rainfall from February to April.
Show worked solution →

Part (a) read the value off the line. Find April on the horizontal axis, go up to the line, then across to the vertical axis. The point is (Apr,110)(\text{Apr}, 110), so April had 110110 mm of rain.

Part (b) subtract the two readings. The change from February to April is the later value minus the earlier value:

11095=15110 - 95 = 15

so the rainfall rose by 1515 mm from February to April. (Because the answer is positive, the line went up between those months, which matches reading a rise on the graph.)

core3 marksA household's weekly budget is $1440, split as rent $600, food $300, transport $180, savings $240 and other $120. Find the sector-graph angle for rent and for food.
Show worked solution →

Set up the fraction-of-360360^{\circ} rule. Each angle is the category's dollars over the total dollars, times 360360^{\circ}. The total is $1440 (and you can check 600+300+180+240+120=1440600 + 300 + 180 + 240 + 120 = 1440).

Rent.

6001440×360=512×360=150\frac{600}{1440} \times 360 = \frac{5}{12} \times 360 = 150^{\circ}

Food.

3001440×360=524×360=75\frac{300}{1440} \times 360 = \frac{5}{24} \times 360 = 75^{\circ}

so the rent sector is 150150^{\circ} and the food sector is 7575^{\circ}. (Cross-check: rent is $600 of $1440, which is just over 40%40\%, and 150150^{\circ} is just over 40%40\% of 360360^{\circ}, so the size is sensible.)

core4 marksA factory logs 5050 faulty items by cause: scratches 2424, dents 1313, paint 77, loose parts 44, other 22. (a) Sort the causes for a Pareto chart. (b) Find the cumulative percentage after each cause. (c) State how many causes account for at least 80%80\% of the faults.
Show worked solution →

Part (a) sort the causes by frequency, largest first. A Pareto chart always orders the bars from the most common cause down: scratches 2424, dents 1313, paint 77, loose parts 44, other 22. They are already in order here.

Part (b) build the cumulative percentage. Keep a running total of the frequencies, then divide each running total by the grand total 5050 and multiply by 100100.

scratches: 2450×100=48%\text{scratches: } \frac{24}{50} \times 100 = 48\%

+ dents: 24+1350×100=3750×100=74%\text{+ dents: } \frac{24 + 13}{50} \times 100 = \frac{37}{50} \times 100 = 74\%

+ paint: 4450×100=88%\text{+ paint: } \frac{44}{50} \times 100 = 88\%

+ loose parts: 4850×100=96%\text{+ loose parts: } \frac{48}{50} \times 100 = 96\%

+ other: 5050×100=100%\text{+ other: } \frac{50}{50} \times 100 = 100\%

Part (c) read the 80/20 point. The cumulative percentage first reaches at least 80%80\% at the third bar (paint), where it hits 88%88\%. So the top 33 causes (scratches, dents and paint) account for at least 80%80\% of the faults. Fixing those three would remove the great majority of the problems. (Check: 24+13+7=4424 + 13 + 7 = 44 faults out of 5050, and 44/50=88%44/50 = 88\%, which matches the cumulative figure.)

core4 marksA school of 6060 students records how each travels to school: car 2020, bus 1515, walk 1212, train 99, bicycle 44. (a) Find the sector angle for the car group. (b) Find the sector angle for the bicycle group. (c) The school also wants a divided bar graph 300300 mm long. Find the length of the car segment.
Show worked solution →

Part (a) car angle. Use the fraction-of-360360^{\circ} rule with total 6060:

2060×360=13×360=120\frac{20}{60} \times 360 = \frac{1}{3} \times 360 = 120^{\circ}

so the car sector is 120120^{\circ}.

Part (b) bicycle angle.

460×360=115×360=24\frac{4}{60} \times 360 = \frac{1}{15} \times 360 = 24^{\circ}

so the bicycle sector is 2424^{\circ}.

Part (c) car segment on a divided bar. A divided bar graph splits a single bar in the same proportions, so the car segment is the car fraction of the 300300 mm length:

2060×300=13×300=100 mm\frac{20}{60} \times 300 = \frac{1}{3} \times 300 = 100 \text{ mm}

so the car segment is 100100 mm long. (The method is identical to the sector angle: replace the 360360^{\circ} of a full circle with the 300300 mm of the full bar.)

exam6 marksA business records 200200 customer complaints by cause over a month: late delivery 9090, wrong item 5454, damaged goods 3030, billing error 1616, other 1010. (a) Construct the cumulative-percentage column for a Pareto chart. (b) State the two causes that, together, make up more than 70%70\% of complaints. (c) The manager can fix two causes this quarter. Using the 80/20 principle, advise which two and justify with figures. (d) Explain why the bars in a Pareto chart must be sorted from largest to smallest.
Show worked solution →

Part (a) cumulative percentages. The causes are already sorted largest first. Keep a running total of frequencies and convert each to a percentage of the total 200200.

late delivery: 90200×100=45%\text{late delivery: } \frac{90}{200} \times 100 = 45\%

+ wrong item: 90+54200×100=144200×100=72%\text{+ wrong item: } \frac{90 + 54}{200} \times 100 = \frac{144}{200} \times 100 = 72\%

+ damaged: 174200×100=87%\text{+ damaged: } \frac{174}{200} \times 100 = 87\%

+ billing error: 190200×100=95%\text{+ billing error: } \frac{190}{200} \times 100 = 95\%

+ other: 200200×100=100%\text{+ other: } \frac{200}{200} \times 100 = 100\%

Part (b) the two biggest causes. The first two bars, late delivery and wrong item, reach a cumulative 72%72\%, which is more than 70%70\%. So late delivery and wrong item together make up 72%72\% of all complaints.

Part (c) which two to fix. By the 80/20 principle a small number of causes drives most of the problem, so target the two tallest bars: late delivery (9090) and wrong item (5454). Together they are

90+54=144 complaints, 144200×100=72%90 + 54 = 144 \text{ complaints, } \quad \frac{144}{200} \times 100 = 72\%

of all complaints, so fixing these two would address 72%72\% of the month's complaints, far more than tackling any other pair. That is the efficient choice.

Part (d) why the bars are sorted. Sorting the bars from largest to smallest is what makes the chart "Pareto": it puts the most important causes on the left so the cumulative line rises steeply at first and then flattens, letting you read at a glance how few causes account for most of the total (the 80/20 read). If the bars were in any other order the cumulative line would not be increasing in a readable way and the "vital few" would be hidden among the "trivial many". (Check: 45+27=7245 + 27 = 72, matching the cumulative 72%72\%, and the individual percentages 45,27,15,8,545, 27, 15, 8, 5 sum to 100%100\%.)

exam5 marksA council reports recycling collected (in tonnes) on a line graph for five years: 20202020 was 4040, 20212021 was 5252, 20222022 was 5858, 20232023 was 5555, 20242024 was 7070. (a) Find the total increase from 20202020 to 20242024. (b) Find the only year-to-year fall and its size. (c) Find the percentage increase from 20202020 to 20242024, correct to the nearest whole percent. (d) Explain why a line graph, rather than a sector graph, suits this data.
Show worked solution →

Part (a) total increase. Subtract the first value from the last:

7040=30 tonnes70 - 40 = 30 \text{ tonnes}

so recycling rose by 3030 tonnes over the five years.

Part (b) the year-to-year fall. Read the step between consecutive years: 405240 \to 52 (up 1212), 525852 \to 58 (up 66), 585558 \to 55 (down 33), 557055 \to 70 (up 1515). The only fall is from 20222022 to 20232023:

5855=3 tonnes58 - 55 = 3 \text{ tonnes}

a fall of 33 tonnes.

Part (c) percentage increase. Percentage increase is the change over the original, times 100100:

704040×100=3040×100=75%\frac{70 - 40}{40} \times 100 = \frac{30}{40} \times 100 = 75\%

so recycling rose by 75%75\% from 20202020 to 20242024.

Part (d) why a line graph suits the data. The data is a single quantity measured over time, and a line graph is built to show change and trend across time, joining the points so the rise and the one dip are easy to see. A sector graph splits one total into parts of a whole, which is not what this data is, so it could not show the year-on-year movement. (Check: the steps +12,+6,3,+15+12, +6, -3, +15 sum to +30+30, matching the total increase in part (a).)

Related dot points