How do we differentiate and integrate trigonometric functions and use them to model periodic phenomena?
Find derivatives and integrals of , and (with linear inside arguments) and apply them to model simple harmonic and periodic motion
A focused answer to the HSC Maths Advanced dot point on trigonometric calculus. Derivatives and integrals of sin, cos and tan, plus modelling periodic motion such as tides and oscillations.
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What this dot point is asking
NESA wants you to differentiate and integrate the three standard trigonometric functions, including with linear inside arguments such as , and apply this calculus to model periodic phenomena (tides, oscillating springs, biological cycles).
The answer
Derivatives
The angle is always measured in radians. The derivatives are:
With a linear inside argument, apply the chain rule:
Integrals
With a linear inside argument, divide by the inside coefficient:
Modelling periodic motion
A function of the form
describes simple harmonic motion (or any sinusoidal cycle). The parameters are:
- is the amplitude (half the peak-to-trough range).
- is the angular frequency in radians per unit time. The period is .
- is the phase shift.
- is the vertical shift (the centre of oscillation).
Differentiating gives the velocity, , and differentiating again gives the acceleration, . The acceleration is proportional to the displacement from the centre and points back towards it.
Why radians are compulsory
The derivative rules and only hold when is measured in radians, because they rest on the limit , which is true only in radian measure. If your calculator is in degree mode the geometry of the limit changes and every derivative is off by a factor of . Always set angles in radians for any calculus involving trigonometric functions, and convert any degree information in the question to radians before differentiating or integrating.
Why the derivative of is
The rule is worth seeing, not just memorising. The derivative of a function is its gradient at each point, so if we read the gradient of off the graph and plot those gradient values, we should recover . We do.
Stage 1, plot . Draw one full cycle of from to : up to a peak at , back through zero at , down to a trough at , and back to zero at .
Stage 2, measure the gradient at sample points. Draw the tangent at a few key points and read its gradient. At the curve rises steeply, gradient ; at the peak the tangent is flat, gradient ; at the curve falls steeply, gradient ; at the trough it is flat again; at it is rising, gradient .
Stage 3, plot each gradient against . Take those gradient values, , and plot them at the same -positions. The points sit exactly where would: , , , and so on.
Stage 4, the gradient function is . Join the gradient points and the curve appears. The gradient of at every point is , which is exactly what says. The same picture, shifted, shows .
Useful identities for integration
Some trigonometric integrals have no direct antiderivative until you rewrite them with an identity. The most useful in Maths Advanced are the double-angle forms and . These convert a squared trig function (which you cannot integrate directly) into a constant plus a cosine of a double angle (which you can). For example, . Recognising when to deploy an identity is a key marker of fluency.
How exam questions ask about trigonometric calculus
- "Differentiate" a trig expression. Apply the standard derivative and the chain-rule factor for a linear inside argument; watch the minus sign on .
- "Find " or "evaluate ". Use the standard integral, divide by the inside coefficient, add for an indefinite integral, and substitute the limits for a definite one.
- "Find the rate at which ... is changing." A modelling question: differentiate the given function and substitute the value, exact then with units.
- "Find the maximum / minimum value" or "the period / amplitude." Read the parameters of : amplitude , period , centre ; the extreme values are .
- "Show that the motion is simple harmonic." Differentiate twice and show : acceleration proportional to displacement and directed back to the centre.
- An integral of or . Rewrite with the double-angle identity first; the squared form has no direct antiderivative.
Exam-style practice questions
Practice questions written in the style of NESA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
2022 HSC Q143 marksFind .Show worked answer →
Use with .
.
Markers reward the correct antiderivative, the bracket notation, and an evaluated answer (here exactly zero, since the integrand is symmetric about ).
2021 HSC Q123 marksThe height of water in a harbour is modelled by metres, where is in hours after midnight. Find the rate at which the height is changing at hours.Show worked answer →
Differentiate using the chain rule.
.
At : m/hr.
The water is rising at about metres per hour at hours.
Markers expect the chain rule applied correctly, the standard angle evaluated exactly, and units in the final answer.
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