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NSWChemistrySyllabus dot point

Inquiry Question 1: How are the ions present in the environment identified and measured?

Conduct qualitative investigations to test for the presence in aqueous solutions of cations and anions using flame tests, precipitation reactions and complexation reactions

A focused answer to the HSC Chemistry Module 8 dot point on qualitative ion identification. Flame tests for group 1 and 2 cations, precipitation tests for transition metals and halides, complexation tests for copper, iron and silver, a structured systematic analysis, and worked HSC past exam questions.

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  1. What this dot point is asking
  2. The answer
  3. Examples in context
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What this dot point is asking

NESA wants you to be able to identify a list of named cations (Ba2+,Ca2+,Mg2+,Pb2+,Ag+,Cu2+,Fe2+,Fe3+Ba^{2+}, Ca^{2+}, Mg^{2+}, Pb^{2+}, Ag^+, Cu^{2+}, Fe^{2+}, Fe^{3+}) and anions (chloride, bromide, iodide, hydroxide, acetate, carbonate, sulfate, phosphate) by their colour, flame test, precipitation behaviour with named reagents, and complexation behaviour. You should also be able to sequence tests so that one ion does not interfere with another.

The answer

Flame tests (group 1 and 2 cations mostly)

Heat a clean platinum or nichrome wire in a Bunsen flame until it glows colourless. Dip it in concentrated HCl to clean residual ions, then in the unknown, and observe the flame colour.

Cation Flame colour
Li+Li^+ Carmine red
Na+Na^+ Persistent yellow-orange
K+K^+ Lilac (use cobalt-blue glass to block sodium)
Ca2+Ca^{2+} Brick red
Sr2+Sr^{2+} Crimson
Ba2+Ba^{2+} Apple green
Cu2+Cu^{2+} Blue-green
Pb2+Pb^{2+} Pale blue (variable)

Flame tests are qualitative only. They are excellent for group 1 and group 2 cations because the electron transitions are in the visible range and the colours are characteristic.

Precipitation tests for cations

Add a named reagent and observe the precipitate (colour, texture, solubility in excess).

Reagent Cu2+Cu^{2+} Fe2+Fe^{2+} Fe3+Fe^{3+} Pb2+Pb^{2+} Ag+Ag^+ Mg2+Mg^{2+} Ba2+Ba^{2+}, Ca2+Ca^{2+}
Dilute NaOH Blue gel Dirty green Rust brown White (redissolves in excess) Brown Ag2OAg_2O White No ppt (Ca slow)
Dilute NH3NH_3 Blue, then deep blue with excess (complex) Green, darkens Brown White Brown then dissolves in excess White No ppt
Na2CO3Na_2CO_3 Green-blue Green-white Brown White Pale yellow White White
K2CrO4K_2CrO_4 Brown (Pale) (Brown) Yellow PbCrO4PbCrO_4 Red Ag2CrO4Ag_2CrO_4 (No) Yellow BaCrO4BaCrO_4, faint CaCrO4CaCrO_4

The Fe2+Fe^{2+} green hydroxide darkens on standing as it oxidises in air to Fe3+Fe^{3+} brown. State that change explicitly if you see it in a question.

Precipitation tests for anions

Anion Reagent Observation
ClCl^- AgNO3AgNO_3 in dilute HNO3HNO_3 White ppt of AgClAgCl, dissolves in dilute NH3NH_3
BrBr^- AgNO3AgNO_3 in dilute HNO3HNO_3 Cream ppt of AgBrAgBr, partly dissolves in concentrated NH3NH_3
II^- AgNO3AgNO_3 in dilute HNO3HNO_3 Yellow ppt of AgIAgI, insoluble in NH3NH_3
SO42SO_4^{2-} BaCl2BaCl_2 in dilute HClHCl White ppt of BaSO4BaSO_4, insoluble in acid
CO32CO_3^{2-} Dilute HClHCl Effervescence of CO2CO_2, turns limewater milky
PO43PO_4^{3-} AgNO3AgNO_3 in neutral solution Yellow ppt of Ag3PO4Ag_3PO_4
OHOH^- Universal indicator or pH Blue/purple, pH > 10
CH3COOCH_3COO^- Warm with conc. H2SO4H_2SO_4 and ethanol Fruity smell of ethyl ethanoate (ester)

The order halide colours (white, cream, yellow) and ammonia solubility (yes, partial, no) is the standard halide differentiation.

The acidification step (dilute HNO3HNO_3 for AgNO3AgNO_3, dilute HClHCl for BaCl2BaCl_2) destroys any carbonate, which would otherwise also precipitate and give a false positive.

Complexation tests

Complexation distinguishes ions that give similar precipitates by re-dissolving one in excess reagent through formation of a soluble complex ion.

Silver halides with ammonia is the canonical example. AgClAgCl dissolves in dilute NH3NH_3, AgBrAgBr partly dissolves in concentrated NH3NH_3, AgIAgI does not dissolve:

AgCl(s)+2NH3(aq)[Ag(NH3)2](aq)++Cl(aq)AgCl_{(s)} + 2NH_{3(aq)} \rightarrow [Ag(NH_3)_2]^+_{(aq)} + Cl^-_{(aq)}

Copper with ammonia. Add dilute NH3NH_3 to a Cu2+Cu^{2+} solution; pale blue Cu(OH)2Cu(OH)_2 forms, then with excess ammonia it dissolves to give the deep blue tetraammine complex:

Cu(OH)2(s)+4NH3(aq)[Cu(NH3)4](aq)2++2OH(aq)Cu(OH)_{2(s)} + 4NH_{3(aq)} \rightarrow [Cu(NH_3)_4]^{2+}_{(aq)} + 2OH^-_{(aq)}

Iron(III) with thiocyanate. Add KSCNKSCN to a Fe3+Fe^{3+} solution; a deep blood-red complex forms:

Fe(aq)3++SCN(aq)[FeSCN](aq)2+Fe^{3+}_{(aq)} + SCN^-_{(aq)} \rightarrow [FeSCN]^{2+}_{(aq)}

This test is so sensitive it picks up traces of Fe3+Fe^{3+} at sub-ppm levels.

Iron(III) with hydroxide vs iron(II) with hydroxide. Fe3+Fe^{3+} gives rust-brown Fe(OH)3Fe(OH)_3; Fe2+Fe^{2+} gives dirty green Fe(OH)2Fe(OH)_2 that browns on standing. Adding KSCNKSCN confirms which is present, since only Fe3+Fe^{3+} gives the red colour.

A systematic procedure

When you do not know what is in the sample:

  1. Look. Coloured solution suggests Cu2+Cu^{2+} (blue), Fe3+Fe^{3+} (yellow-brown), Fe2+Fe^{2+} (pale green), CrO42CrO_4^{2-} (yellow), MnO4MnO_4^- (purple).
  2. Flame test on a small portion to screen group 1/2 cations.
  3. Add NaOH to a fresh portion to test for transition metal hydroxides.
  4. Targeted tests for suspected ions on fresh portions: AgNO3AgNO_3 for halides, BaCl2BaCl_2 for sulfate, dilute HCl for carbonate, KSCNKSCN for Fe3+Fe^{3+}.
  5. Always use a fresh portion for each test. Acidify with the appropriate acid to suppress interferences (carbonate is the most common false-positive).

Examples in context

Example 1. Identifying contaminants in groundwater near Botany Bay. Following a 1990s legacy spill of dense non-aqueous phase liquids at the Botany Industrial Park, NSW EPA contractors run a qualitative ion screen on every new groundwater sample before quantitative GC-MS. The test sequence covers: flame test (no yellow Na+Na^+ confirms no halite intrusion), acidified AgNO3AgNO_3 (a white AgClAgCl precipitate indicates chloride), and acidified BaCl2BaCl_2 (a white BaSO4BaSO_4 flag for sulfate from acid mine drainage). A positive reaction triggers escalation to quantitative AAS for the cation profile. The HSC qualitative framework students apply at the bench is the same first-pass screen that scopes the contamination plume.

Example 2. NSW HSC depth study unknown solution identification. A common Stage 6 task gives students six unlabelled solutions and asks them to identify the cation and anion in each using only the qualitative test reagents on the bench. A solution that turns blue with NaOH (forming Cu(OH)2Cu(OH)_2) and then dissolves to deep blue with excess ammonia ([Cu(NH3)4]2+[Cu(NH_3)_4]^{2+}) is copper. The same solution, treated with BaCl2BaCl_2 in acid and giving a white precipitate, contains sulfate. The student writes the two ion identification net ionic equations: Cu2++4NH3[Cu(NH3)4]2+Cu^{2+} + 4NH_3 \rightarrow [Cu(NH_3)_4]^{2+} and Ba2++SO42BaSO4Ba^{2+} + SO_4^{2-} \rightarrow BaSO_4. NESA markers reward both the observation and the equation.

Try this

Q1. State the flame test colour for each of: Li+Li^+, Na+Na^+, K+K^+, Ca2+Ca^{2+}, Cu2+Cu^{2+}. [3 marks]

  • Cue. Li+Li^+ crimson; Na+Na^+ yellow; K+K^+ lilac; Ca2+Ca^{2+} brick red; Cu2+Cu^{2+} blue-green.

Q2. A solution gives a white precipitate with acidified AgNO3AgNO_3 that dissolves in dilute ammonia. Calculate the mass of chloride ion in 50 mL of the solution if 0.072 g of AgClAgCl is recovered. [3 marks]

  • Cue. n(AgCl)=0.072/143.32=5.02×104n(AgCl) = 0.072 / 143.32 = 5.02 \times 10^{-4} mol; n(Cl)=5.02×104n(Cl^-) = 5.02 \times 10^{-4} mol; mass = 5.02×104×35.45=0.01785.02 \times 10^{-4} \times 35.45 = 0.0178 g.

Q3. A solution gives a pale-green precipitate with NaOH that darkens on standing. (a) Identify the cation. (b) Write the net ionic equation. (c) Describe one additional test to confirm. [2+1+2 marks]

  • Cue. (a) Iron(II), Fe2+Fe^{2+}. (b) Fe2++2OHFe(OH)2Fe^{2+} + 2OH^- \rightarrow Fe(OH)_2. (c) Oxidation to brown Fe(OH)3Fe(OH)_3 on air exposure or red colour with SCNSCN^- after oxidation.

Exam-style practice questions

Practice questions written in the style of NESA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

2022 HSC5 marksAn unknown aqueous solution gives a brick-red flame test, a white precipitate with silver nitrate that dissolves in dilute ammonia, and no precipitate with sodium hydroxide. Identify the cation and the anion present. Write balanced ionic equations for the precipitation and the complexation steps.
Show worked answer →

A 5 mark answer needs both ions, both equations, and one sentence of reasoning per step.

Brick-red flame test points to calcium Ca2+Ca^{2+}. (Strontium is crimson, lithium is bright red but more carmine; brick-red is the standard description for calcium.)

No precipitate with NaOH rules out transition metal cations (which form coloured hydroxides) and rules out Mg2+Mg^{2+} (which gives white Mg(OH)2Mg(OH)_2). Ca(OH)2Ca(OH)_2 has Ksp5×106K_{sp} \approx 5 \times 10^{-6} and is moderately soluble, so dilute NaOH does not precipitate calcium. Consistent with Ca2+Ca^{2+}.

White precipitate with silver nitrate that dissolves in dilute ammonia is the classic test for chloride ClCl^-:

Ag(aq)++Cl(aq)AgCl(s)Ag^+_{(aq)} + Cl^-_{(aq)} \rightarrow AgCl_{(s)}

AgCl(s)+2NH3(aq)[Ag(NH3)2](aq)++Cl(aq)AgCl_{(s)} + 2NH_{3(aq)} \rightarrow [Ag(NH_3)_2]^+_{(aq)} + Cl^-_{(aq)}

The first equation is the precipitation; the second is the complexation that distinguishes chloride from bromide (which is cream and only partially dissolves in concentrated ammonia) and iodide (which is yellow and does not dissolve).

Conclusion. The unknown is calcium chloride, CaCl2CaCl_2.

Markers reward (1) calcium from the flame, (2) ruling out other cations using the hydroxide result, (3) chloride from the silver nitrate result, (4) the complexation equation, (5) using both pieces of evidence consistently.

2019 HSC4 marksDescribe a systematic procedure to identify which of the following ions are present in an unknown aqueous solution: Pb2+Pb^{2+}, Cu2+Cu^{2+}, Fe3+Fe^{3+}, ClCl^-, SO42SO_4^{2-}.
Show worked answer →

A 4 mark answer needs a sequence of tests with observations and conclusions for each candidate.

Step 1: Inspect the colour
Cu2+Cu^{2+} is blue, Fe3+Fe^{3+} is yellow-brown. If the solution is colourless, both are absent. If blue, Cu2+Cu^{2+} is likely; if yellow-brown, Fe3+Fe^{3+} is likely.
Step 2: Add dilute NaOH dropwise
A blue gelatinous precipitate confirms Cu(OH)2Cu(OH)_2 (Cu present). A rust-brown precipitate confirms Fe(OH)3Fe(OH)_3 (Fe present). A white precipitate that dissolves in excess NaOH suggests Pb(OH)2Pb(OH)_2, which is amphoteric.
Step 3: Confirm Pb2+Pb^{2+}
To a fresh portion, add dilute KI. A bright yellow precipitate of PbI2PbI_2 confirms lead:

Pb2++2IPbI2(s)Pb^{2+} + 2I^- \rightarrow PbI_{2(s)}

Step 4: Test for chloride. To a fresh portion (acidified with dilute HNO3HNO_3 to suppress carbonate interference), add silver nitrate. A white precipitate that dissolves in ammonia confirms ClCl^-.

Step 5: Test for sulfate. To a fresh portion (acidified with dilute HCl to remove carbonate), add barium chloride. A white precipitate of BaSO4BaSO_4 that does not dissolve in acid confirms SO42SO_4^{2-}.

Always use fresh portions for each test; never add reagents sequentially to one sample because precipitates and complexes interfere with later tests.

Markers reward (1) a logical sequence (inspection then NaOH then specific tests), (2) at least one named precipitate per ion, (3) the acidification step to remove carbonate interference, (4) the principle of using fresh portions.

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