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Inquiry Question 5: How are acids and bases defined and how do they behave in aqueous solution?

Conduct an investigation to perform titrations of strong acid and strong base, weak acid and strong base, and weak base and strong acid, and analyse the data to determine concentration, pH at the equivalence point, and appropriate indicator selection

A focused answer to the HSC Chemistry Module 5 dot point on titrations. The four titration curve shapes, equivalence vs end point, indicator selection rules, calculating unknown concentrations from titration data, and worked HSC past exam questions.

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  1. What this dot point is asking
  2. The answer
  3. Examples in context
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What this dot point is asking

NESA wants you to interpret titration data, distinguish equivalence point from end point, recognise the four canonical titration curve shapes, select an appropriate indicator, and calculate an unknown concentration from titration data. The shape of every curve is set by the acid-base chemistry of the species involved and the pH math you used earlier in the module. Expect a 5-7 mark calculation in Section II that often combines stoichiometry with indicator justification.

The answer

Titration basics

A titration is a volumetric analysis in which a solution of known concentration (the titrant, usually in the burette) is added gradually to a solution of unknown concentration (the analyte, usually in a conical flask) until the reaction is complete.

The equivalence point is reached when stoichiometrically equivalent moles of acid and base have been mixed. The end point is when the indicator changes colour. Good experimental design makes these coincide.

Calculation pattern

For an acid-base titration with 1:1 stoichiometry:

cunknown=ctitrant×VtitrantVunknownc_{\text{unknown}} = \frac{c_{\text{titrant}} \times V_{\text{titrant}}}{V_{\text{unknown}}}

For diprotic acids or bases, include the stoichiometric ratio. For example, H2SO4+2NaOHNa2SO4+2H2OH_2SO_4 + 2NaOH \rightarrow Na_2SO_4 + 2H_2O: moles of NaOH equals 2 times moles of H2SO4H_2SO_4.

Comparing titration curves

The shape of a titration curve depends on the strengths of the acid and base involved. The table below traces pH against the fraction of titrant added (acid being titrated with base), making the differences explicit.

Volume added Strong acid / strong base Weak acid / strong base Weak base / strong acid
0% ~1.0 ~2.9 ~11.1
50% (mid-point) ~1.5 4.74 (= pKapK_a) 9.26 (= 14 - pKbpK_b)
100% (equivalence) 7.0 8.7 5.3
150% ~12.5 ~12.5 ~1.5

Note that the 50% point of a weak acid (or weak base) titration occurs at pH=pKapH = pK_a (or pH=14pKbpH = 14 - pK_b). This is the heart of the buffer region (see buffer systems). After equivalence, all three curves converge toward the pH of the excess titrant.

Titration curves for strong and weak acid against strong base A plot of pH against volume of 0.10 mol per litre sodium hydroxide added to two acids. The strong acid curve starts near pH 1, rises slowly, then jumps sharply through pH 7 at the equivalence point (25 mL) and levels off above pH 12. The weak acid curve starts near pH 2.9, rises more gradually with a buffer plateau around pH equals pKa equals 4.74, and reaches equivalence at pH 8.7 with a less steep transition. pH V (mL NaOH) 14 12 10 7 5 2 0 10 20 25 30 40 50 equivalence phenolphthalein 8.3-10 strong acid weak acid (pKa ≈ 4.74) Equivalence pH 7 for strong/strong, ~8.7 for weak acid/strong base. Buffer plateau at pH = pKa.

The upper line is strong acid / strong base (steep, equivalence pH 7). The lower line is weak acid / strong base (gentler approach, buffer plateau around pKapK_a = 4.74, equivalence pH 8.7).

Why each curve has the equivalence pH it does

Strong acid / strong base (HCl + NaOH). Equivalence pH 7 because the salt (NaCl) does not hydrolyse. The transition is very steep, so several indicators work.

Weak acid / strong base (CH3COOHCH_3COOH + NaOH). Equivalence pH > 7 because the conjugate base (CH3COOCH_3COO^-) hydrolyses water to give OHOH^-. The buffer plateau in the middle of the curve is exploited for buffer preparation.

Weak base / strong acid (NH3NH_3 + HCl). Equivalence pH < 7 because the conjugate acid (NH4+NH_4^+) hydrolyses water to give H3O+H_3O^+.

Weak acid / weak base. No sharp transition. No indicator gives a reliable end point. Not used quantitatively in HSC.

Indicator selection rule

Choose an indicator whose colour change range straddles the equivalence pH. If the equivalence pH is 8.7 (weak acid / strong base), phenolphthalein (8.3-10.0) brackets it; methyl orange (3.1-4.4) would change far too early.

Common HSC indicators

Indicator pH range Use
Methyl orange 3.1 to 4.4 Weak base / strong acid
Methyl red 4.2 to 6.3 Weak base / strong acid
Bromothymol blue 6.0 to 7.6 Strong acid / strong base
Phenolphthalein 8.3 to 10.0 Weak acid / strong base, also strong/strong

Examples in context

Example 1. Quality control of NSW commercial vinegars. Food chemists at the NSW DPI laboratory in Cobbitty test commercial vinegars against the food standards code, which requires ethanoic acid concentrations between 4 and 8 percent by mass. A pipetted 25 mL sample is titrated against standardised 0.100 mol L1^{-1} NaOH with phenolphthalein as indicator. The titre is multiplied by the molar mass of ethanoic acid and divided by sample volume to give the percentage. The curve is a weak acid / strong base shape with equivalence pH near 8.7, so phenolphthalein straddles the colour change. Methyl orange would mark an end point well before equivalence and falsely understate the acid content.

Example 2. NSW HSC depth study titration of aspirin tablets. A common Stage 6 depth study involves crushing a 300 mg aspirin tablet, dissolving in ethanol, and back-titrating against 0.0500 mol L1^{-1} NaOH. Aspirin (acetylsalicylic acid) behaves as a weak acid with pKapK_a around 3.5. The chosen indicator is phenolphthalein because the equivalence pH sits well above 7 after the conjugate base hydrolyses. Students who use methyl orange typically report a "tablet content" of only 60 percent of the stated 300 mg, falling foul of the marker. The depth study lets candidates see firsthand why indicator range and equivalence pH must align.

Try this

Q1. Define the equivalence point and the end point of a titration, and state the criterion for choosing an indicator that makes them coincide. [3 marks]

  • Cue. Equivalence is stoichiometric mole balance; end point is when indicator changes colour; choose an indicator whose pH range straddles the equivalence pH.

Q2. A 25.0 mL sample of H2SO4H_2SO_4 is titrated to equivalence with 32.50 mL of 0.150 mol L1^{-1} NaOH. Calculate the concentration of the sulfuric acid. [3 marks]

  • Cue. Apply n(NaOH)=cVn(NaOH) = cV then divide by 2 for the 1:2 stoichiometry H2SO4+2NaOHH_2SO_4 + 2NaOH; divide by the acid volume in litres.

Q3. A weak acid HA of unknown concentration is titrated with 0.100 mol L1^{-1} NaOH. The pH at the half-equivalence point is 4.74 and the equivalence point pH is 8.72. (a) State the pKapK_a of HA. (b) Name a suitable indicator and justify the choice. (c) Sketch how the curve would change if a strong acid were used instead. [1+2+2 marks]

  • Cue. (a) pKa=4.74pK_a = 4.74. (b) Phenolphthalein (8.3 to 10.0) straddles equivalence pH 8.72. (c) Strong acid / strong base curve is steeper, equivalence pH 7, no buffer plateau.

Exam-style practice questions

Practice questions written in the style of NESA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

2021 HSC5 marksA 25.0 mL sample of vinegar (containing ethanoic acid, CH₃COOH) was titrated against 0.100 mol/L NaOH. The mean titre was 22.40 mL. Calculate the concentration of ethanoic acid in the vinegar and identify a suitable indicator for the titration. Justify your indicator choice.
Show worked answer →

A 5 mark answer needs the stoichiometry, the concentration calculation, the indicator name, and a justification linked to the equivalence pH.

Equation.

CH3COOH+NaOHCH3COONa+H2OCH_3COOH + NaOH \rightarrow CH_3COONa + H_2O

One mole of acid reacts with one mole of base.

Moles of NaOH used.

n(NaOH)=0.100×0.02240=2.24×103 moln(NaOH) = 0.100 \times 0.02240 = 2.24 \times 10^{-3} \text{ mol}

Moles of acid in the 25.0 mL sample. From 1:1 stoichiometry, n(CH3COOH)=2.24×103n(CH_3COOH) = 2.24 \times 10^{-3} mol.

Concentration of ethanoic acid.

c(CH3COOH)=2.24×1030.0250=0.0896 mol/Lc(CH_3COOH) = \frac{2.24 \times 10^{-3}}{0.0250} = 0.0896 \text{ mol/L}

Indicator. This is a weak acid / strong base titration, so the equivalence pH is above 7 (the conjugate base CH3COOCH_3COO^- is basic). The salt CH3COONaCH_3COONa hydrolyses, giving an equivalence pH around 8.7.

Phenolphthalein (colour change pH 8.3 to 10.0) is appropriate because its colour change range straddles the equivalence pH. Methyl orange (pH 3.1 to 4.4) would change colour too early and give a falsely low titre.

Markers reward (1) the balanced equation, (2) correct stoichiometric calculation to 3 sig figs, (3) identifying the curve type, (4) naming an indicator with its pH range, (5) explicit justification linking range to equivalence pH.

2018 HSC3 marksDistinguish between the terms equivalence point and end point in an acid-base titration.
Show worked answer →

The equivalence point is the point in a titration at which stoichiometrically equivalent amounts of acid and base have been added. For a 1:1 reaction, moles of acid added equals moles of base. The equivalence point is a property of the chemistry of the titration.

The end point is the point at which the indicator changes colour. It depends on the indicator chosen, not on the chemistry alone.

A well-chosen indicator has its colour change range straddling the equivalence pH, so the end point coincides closely with the equivalence point. A poorly chosen indicator can make the end point occur before or after the equivalence point, giving an inaccurate titre.

Markers reward (1) a clear definition of each, (2) the contrast that equivalence is stoichiometric and end point is indicator-dependent, (3) the connection (a good indicator makes them approximately coincide).

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