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NSWChemistryQuick questions

Module 5: Equilibrium and Acid Reactions

Quick questions on Equilibrium constant Keq explained: HSC Chemistry Module 5

5short Q&A pairs drawn directly from our worked dot-point answer. For full context and worked exam questions, read the parent dot-point page.

What is the reaction quotient Q?
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For a system not yet at equilibrium, the same expression is evaluated using the current concentrations and is called the reaction quotient Q.
What is wrong direction of Keq when reaction is reversed?
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Kreverse=1/KforwardK_{reverse} = 1 / K_{forward}. If a question gives Keq for one direction, you must invert it for the reverse.
What is q1?
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Define the equilibrium constant KeqK_{eq} and state two factors that do not change its value at constant temperature. [2 marks]
What is q2?
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At 500 K, 2.00 mol2.00 \text{ mol} of PCl5PCl_5 is placed in a 2.00 L2.00 \text{ L} vessel and decomposes via PCl5(g)PCl3(g)+Cl2(g)PCl_{5(g)} \rightleftharpoons PCl_{3(g)} + Cl_{2(g)}. At equilibrium [Cl2]=0.30 mol L1[Cl_2] = 0.30 \text{ mol L}^{-1}. Calculate KeqK_{eq}.
What is q3?
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For 2NO2(g)N2O4(g)2NO_{2(g)} \rightleftharpoons N_2O_{4(g)}, Keq=4.0K_{eq} = 4.0 at 298 K. A mixture has [NO2]=0.50 mol L1[NO_2] = 0.50 \text{ mol L}^{-1} and [N2O4]=0.50 mol L1[N_2O_4] = 0.50 \text{ mol L}^{-1}. (a) Calculate QQ.

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