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VICMath MethodsQuick questions

Unit 4

Quick questions on Antidifferentiation and indefinite integrals: VCE Math Methods Unit 4

11short Q&A pairs drawn directly from our worked dot-point answer. For full context and worked exam questions, read the parent dot-point page.

What is example 1. Polynomial?
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$\int (5 x^4 - 6 x^2 + 7) \, dx = x^5 - 2 x^3 + 7 x + c$.
What is example 2. Rational and root?
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$\int \left( \frac{1}{x^2} + \sqrt{x} \right) dx$.
What is example 3. Exponential and reciprocal?
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$\int \left( e^{-2x} + \frac{4}{x} \right) dx = -\frac{1}{2} e^{-2x} + 4 \ln\lvert x \rvert + c$.
What is example 4. Circular with non-unit coefficient?
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$\int 3 \cos(4x) \, dx = 3 \cdot \frac{1}{4} \sin(4x) + c = \frac{3}{4} \sin(4x) + c$.
What is example 5. Initial value problem?
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Given $f'(x) = 6 x - \sin(x)$ and $f(0) = 4$.
What is forgetting the $\frac{1}{k}$ factor?
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$\int e^{2x} \, dx = \frac{1}{2} e^{2x} + c$, not $e^{2x} + c$. Same for $\sin(kx)$ and $\cos(kx)$.
What is wrong sign on $\cos$ antiderivative?
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$\int \cos(x) \, dx = \sin(x) + c$ (no negative). $\int \sin(x) \, dx = -\cos(x) + c$ (negative).
What is forgetting $c$?
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An indefinite integral without the constant of integration loses marks even when the antiderivative is otherwise correct.
What is missing the absolute value on $\ln$?
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$\int \frac{1}{x} \, dx = \ln\lvert x \rvert + c$. Without context restricting $x > 0$, the absolute value is required.
What is trying to apply the power rule to $\frac{1}{x}$?
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The power rule for $\int x^n \, dx$ requires $n \neq -1$. The antiderivative of $\frac{1}{x}$ is $\ln\lvert x \rvert$, not $\frac{x^0}{0}$.
What is confusing derivative and antiderivative?
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$\frac{d}{dx}[e^{2x}] = 2 e^{2x}$ (multiply by 2). $\int e^{2x} \, dx = \frac{1}{2} e^{2x} + c$ (divide by 2). The factor goes opposite directions.

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