Skip to main content
QLDPhysicsSyllabus dot point

What is nuclear physics, and how do nuclei decay and produce energy?

Atomic nucleus, isotopes, types of radioactive decay (alpha, beta, gamma), half-life, fission and fusion

A focused answer to the QCE Physics Unit 1 subject-matter point on nuclear physics. Atomic structure, isotopes, alpha/beta/gamma decay, half-life formula N=N0(1/2)t/T1/2N = N_0(1/2)^{t/T_{1/2}}, fission and fusion.

Generated by Claude Opus 4.810 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

Have a quick question? Jump to the Q&A page

Jump to a section
  1. What this dot point is asking
  2. Atomic structure
  3. Radioactive decay
  4. Nuclear equations
  5. Half-life
  6. Fission
  7. Fusion
  8. Examples in context
  9. Try this

What this dot point is asking

QCAA wants Year 11 students to describe atomic structure, recognise radioactive decay types, and apply the half-life formula.

Atomic structure

Nucleus: protons (+e, 1.67×10271.67 \times 10^{-27} kg) and neutrons (0 charge, similar mass).

Notation ZAX^A_Z X: ZZ atomic number (protons), AA mass number (protons + neutrons), N=AZN = A - Z neutrons.

Isotopes. Same ZZ, different NN. E.g., 12^{12}C, 13^{13}C, 14^{14}C.

Radioactive decay

Alpha
Emit helium nucleus 24^4_2He. Mass number drops 4, atomic number drops 2. Range: cm in air; stopped by paper.
Beta-minus
Neutron \to proton + electron + antineutrino. Atomic number increases by 1; mass number unchanged. Range: metres in air; stopped by aluminium.
Gamma
High-energy photon from excited nucleus. Mass and atomic numbers unchanged. Highly penetrating; lead/concrete shielding.

Nuclear equations

Conservation: mass number and charge conserved on both sides.

Examples:

92238U90234Th+24He^{238}_{92} \text{U} \to ^{234}_{90} \text{Th} + ^4_2 \text{He} (alpha).

614C714N+10e+νˉe^{14}_6 \text{C} \to ^{14}_7 \text{N} + ^0_{-1} e + \bar{\nu}_e (beta-minus).

Half-life

N=N0(12)t/T1/2N = N_0 \left(\frac{1}{2}\right)^{t/T_{1/2}}

Half-life is statistical; random for individual atom.

Common: C-14 (5,730 yr, carbon dating), I-131 (8 days, medical), U-238 (4.5 Gyr).

Fission

Heavy nucleus splits: 235U+n141Ba+92Kr+3n^{235}\text{U} + n \to ^{141}\text{Ba} + ^{92}\text{Kr} + 3n, releasing 200\sim 200 MeV.

Chain reaction possible (more than one neutron per fission triggers next).

Fusion

Light nuclei combine: 2H+3H4He+n^2\text{H} + ^3\text{H} \to ^4\text{He} + n, 17.6\sim 17.6 MeV.

Powers the sun. Controlled fusion remains research goal.

Examples in context

Example 1. ANSTO Mt Cotton's archived monazite samples include thorium-232232 (half-life 1.4×1010 years1.4 \times 10^{10} \text{ years}), which decays in a long chain ending at lead-208208. Each alpha step lowers nucleon number by 44 and proton number by 22; each beta-minus step leaves nucleon number unchanged and raises proton number by 11. Geologists use the parent-to-daughter ratio to date Queensland sapphire-bearing basalt fields north of Anakie, applying N=N0(1/2)t/T1/2N = N_0 (1/2)^{t/T_{1/2}}. The QCAA Unit 1 nuclear summary expects students to balance such decay equations.

Example 2. Royal Brisbane Hospital cyclotron production of fluorine-1818 (T1/2=110 minT_{1/2} = 110 \text{ min}) supplies PET scanners. A batch leaving the cyclotron with 20 GBq20 \text{ GBq} at 07000700 has fallen to 20×(1/2)2.18=4.4 GBq20 \times (1/2)^{2.18} = 4.4 \text{ GBq} by the patient injection at 11001100. The isotope decays by positron (β+\beta^+) emission, the positrons annihilate with electrons and produce paired 511 keV511 \text{ keV} gammas detected coincidentally to localise tumours. The same dot-point isotope concept (same Z, different N) is the basis of all medical radio-tracers.

Try this

Q1. Define isotope and identify the decay particle that does not change the mass number. [2 marks]

  • Cue. Isotope: same Z, different N; beta decay and gamma decay leave A unchanged.

Q2. Complete the alpha decay equation 88226Ra?Rn+α^{226}_{88}\text{Ra} \rightarrow ?\text{Rn} + \alpha. State the mass and charge of the alpha particle. [3 marks]

  • Cue. 86222Rn^{222}_{86}\text{Rn}; alpha =24He= ^{4}_{2}\text{He}, mass 4.00 u\approx 4.00 \text{ u}, charge +2e+2e.

Q3. A 40 MBq40 \text{ MBq} source of cobalt-6060 (T1/2=5.3 yearsT_{1/2} = 5.3 \text{ years}) is purchased for radiotherapy. (a) Calculate the activity remaining after 15.9 years15.9 \text{ years}. (b) Cobalt-6060 decays by beta-minus then gamma. Write the daughter nuclide and explain how the gamma originates. (c) Discuss one regulatory implication in Queensland of selecting an isotope with this half-life. [3+3+2 marks; ISMG: Knowledge and conceptual understanding, Evaluation]

  • Cue. (a) Three half-lives, 5.0 MBq5.0 \text{ MBq}; (b) 60Ni^{60}\text{Ni} excited state emits gammas; (c) ARPANSA storage requirements.

Exam-style practice questions

Practice questions written in the style of QCAA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Year 11 SAC4 marksCarbon-14 has half-life 5,7305,730 years. (a) Atoms remaining after 11,46011,460 years from 101010^{10} initial? (b) Write the beta-minus decay equation.
Show worked answer →

(a) 11460/5730=211460/5730 = 2 half-lives. N=1010(1/2)2=2.5×109N = 10^{10} (1/2)^2 = 2.5 \times 10^9 atoms.

(b) 614C714N+10e+νˉe^{14}_6 \text{C} \to ^{14}_7 \text{N} + ^0_{-1} e + \bar{\nu}_e.

Charge: 6 = 7 + (-1). Mass: 14 = 14 + 0. Conserved.

Markers reward half-life calculation and conservation in nuclear equation.

Related dot points