Unit 2: Molecular interactions and reactions

QLDChemistrySyllabus dot point

Topic 2: Aqueous solutions and acidity

Explain the properties of water as a solvent in terms of its polarity and hydrogen bonding, and describe the dissolution of ionic and polar molecular substances in water

A focused answer to the QCE Chemistry Unit 2 dot point on water as a solvent. Explains why water's bent shape and O-H bonds give it a permanent dipole and extensive hydrogen bonding, then walks through ion-dipole solvation of NaCl, hydrogen-bonding solvation of ethanol, and the "like dissolves like" rule with worked exceptions.

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What this dot point is asking

QCAA wants you to explain why water is such an effective solvent for ionic compounds and polar molecules in terms of its polarity and hydrogen bonding, and describe the mechanism of dissolution at the particle level. This dot point underpins everything in Topic 2 from solubility rules to acid-base behaviour.

The answer

Water dissolves a wide range of ionic and polar molecular substances because its bent molecular shape and two O-H bonds give it a strong permanent dipole and the ability to form extensive hydrogen bonds. These features let water surround and stabilise solute particles through ion-dipole or dipole-dipole interactions that compensate for the energy required to break the solute apart.

The structure of water

Water has the molecular formula H_2O. The O atom is sp3-like with two bond pairs (to H) and two lone pairs. VSEPR predicts a bent shape with H-O-H angle around 104.5 degrees.

The O-H bond is highly polar because oxygen is much more electronegative than hydrogen (3.44 vs 2.20 on Pauling scale). Each O carries a partial negative charge (delta-) and each H a partial positive charge (delta+). Because the molecule is bent, these bond dipoles do not cancel; the molecule has a net dipole moment of 1.85 D pointing from the H-H midpoint toward the O.

Hydrogen bonding in water

H bonded to O (one of N, O, F) can hydrogen bond. Each water molecule has:

  • 2 hydrogen-bond donors (the two O-H bonds).
  • 2 hydrogen-bond acceptors (the two lone pairs on O).

In liquid water, each molecule averages about 3.4 hydrogen bonds with its neighbours at room temperature. In ice the network is fully tetrahedral with exactly 4 bonds per molecule, which is why ice is less dense than liquid water (the open lattice structure).

These extensive hydrogen bonds explain water's anomalously high melting point, boiling point, surface tension, viscosity and specific heat capacity for a molecule of mass 18 g/mol.

Dissolution of ionic compounds (ion-dipole interaction)

When an ionic solid such as NaCl is placed in water:

  1. The polar water molecules orient near ions at the crystal surface. The delta- ends of water (the O) face cations (Na+); the delta+ ends (H) face anions (Cl-).
  2. These ion-dipole attractions pull individual ions away from the lattice. Each freed ion becomes hydrated, surrounded by a shell of oriented water molecules.
  3. Hydrated ions diffuse into the bulk of the solvent.

Energy considerations:

  • Energy required: lattice energy (the work to separate the ions in the crystal).
  • Energy released: hydration enthalpy (the work released by surrounding ions with water dipoles).

If hydration energy is comparable to or greater than lattice energy, the salt is soluble. If lattice energy substantially exceeds hydration energy, the salt is insoluble. For NaCl the two are similar; dissolution is slightly endothermic but entropy-driven.

A typical hydrated ion picture: Na+ surrounded by 6 water molecules with O atoms facing the cation (octahedral). Cl- surrounded by water molecules with H atoms facing the anion.

Dissolution of polar molecular substances

Polar molecules with hydrogen-bond donor or acceptor groups dissolve readily because they can substitute for water-water hydrogen bonds with comparable strength water-solute hydrogen bonds.

Example: ethanol (C_2H_5OH).

  • Ethanol's O-H group hydrogen-bonds with water (donor or acceptor).
  • Ethanol's small carbon chain has only weak dispersion interactions that do not strongly disrupt water-water hydrogen bonding.
  • Ethanol and water are miscible in all proportions.

Example: glucose. Five OH groups on a six-carbon ring. Many hydrogen-bond sites; very high solubility (about 900 g/L at 25 degrees C).

As the carbon chain grows (methanol, ethanol, propanol, butanol, pentanol), water solubility decreases. The non-polar tail becomes too large for the polar head to compensate; eventually the alcohol becomes immiscible with water.

"Like dissolves like" as a heuristic

Polar / hydrogen-bonding substances dissolve in polar / hydrogen-bonding solvents.

Non-polar substances dissolve in non-polar solvents.

The principle is not absolute; many real systems show partial miscibility (ether in water, alcohols of intermediate chain length). But the qualitative rule is reliable for QCE-level predictions when you can name the dominant intermolecular force in both solute and solvent.

Solute Dominant force Soluble in water? Soluble in hexane?
NaCl (s) Ionic lattice Yes (ion-dipole) No
Ethanol Hydrogen bonding Yes Yes (partial; both forces present)
Glucose Hydrogen bonding (many OH) Yes No
Iodine I_2 Dispersion No Yes
Hexane Dispersion No Yes
Oil / fat Dispersion No Yes

Non-polar molecular substances and the hydrophobic effect

Non-polar molecules placed in water disturb water-water hydrogen bonding without offering any replacement attraction. Water responds by forming ordered cages around the solute (a clathrate-like structure), which is entropically unfavourable. This drives non-polar molecules to clump together (or float as a separate phase), the hydrophobic effect. It is the basis of micelle and membrane formation, soap action and protein folding.

QCE Chemistry treats this qualitatively: non-polar molecules are not soluble in water because dissolving them disrupts water structure without forming equivalent attractions.

Common traps

Calling water "neutral" to mean "non-polar". Water is electrically neutral overall but highly polar. Confusing the two terms is a frequent EA mark-loss.

Forgetting the orientation in ion-dipole solvation. Cations attract the delta- O of water; anions attract the delta+ H. Reversing this loses the explanation marks.

Using "ionic bond" for hydration interactions. Ion-dipole interactions are not bonds; they are non-covalent attractions, weaker than ionic bonds but strong enough to overcome lattice energies for soluble salts.

Ignoring entropy. Dissolution can be slightly endothermic and still spontaneous if it increases disorder substantially (NaCl in water is a classic case).

Applying "like dissolves like" without naming the force. The principle is descriptive; the explanation must name the specific intermolecular forces involved (dispersion, dipole-dipole, hydrogen bonding, ion-dipole).

In one sentence

Water's bent shape and two polar O-H bonds give it a permanent dipole and the ability to form four hydrogen bonds per molecule, which lets it dissolve ionic compounds by surrounding cations with delta- O and anions with delta+ H (ion-dipole solvation) and dissolve polar molecules such as alcohols and sugars by hydrogen bonding, following the "like dissolves like" rule with the polar / hydrogen-bonding character of the solute determining aqueous solubility.

Past exam questions, worked

Real questions from past QCAA papers on this dot point, with our answer explainer.

2024 QCAA-style4 marks(a) Explain, using a diagram or annotated description, how solid sodium chloride dissolves in water. (b) Predict, with reasoning, whether iodine (I_2) is soluble in water and whether it is soluble in hexane.
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A 4-mark answer needs the ion-dipole mechanism for NaCl and the like-dissolves-like reasoning for I_2.

(a) Dissolution of NaCl. Water is a polar molecule with delta- on O and delta+ on H. The delta- oxygen ends of water molecules orient toward Na+ cations at the crystal surface; the delta+ hydrogen ends orient toward Cl- anions. These ion-dipole attractions provide enough energy to overcome the ionic lattice energy. Hydrated ions (Na+ surrounded by water with O facing in; Cl- surrounded by water with H facing in) diffuse away from the crystal into solution. Process is endothermic for NaCl overall but entropy-favoured.

(b) Iodine solubility. I_2 is a non-polar molecule (homonuclear diatomic, no dipole). The only intermolecular force it can offer a solvent is dispersion.

Water: dissolving I_2 in water would require breaking water-water hydrogen bonds without forming equivalent water-iodine attractions. Energetically unfavourable; I_2 is poorly soluble in water (about 0.3 g/L).

Hexane: hexane is a non-polar hydrocarbon held together by dispersion forces. Hexane-iodine dispersion attractions are comparable to hexane-hexane and iodine-iodine, so the energy cost of dissolution is small. I_2 dissolves readily in hexane (giving a violet solution).

Markers reward the ion-dipole mechanism (with correct orientation), the like-dissolves-like statement applied to both solvents, and the reference to dispersion forces in non-polar systems.

2022 QCAA-style3 marksGlucose (C_6H_12O_6) is highly soluble in water; cyclohexane (C_6H_12) is essentially insoluble. Both have molar mass 180 and 84 g/mol respectively. Explain the difference using intermolecular force arguments.
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A 3-mark answer needs structural identification and force matching.

Glucose. Has five hydroxyl (-OH) groups around its ring. Each OH can act as both a hydrogen bond donor (O-H) and acceptor (lone pairs on O). Glucose-water interactions are extensive hydrogen bonds, comparable in strength to water-water hydrogen bonds. Dissolution is energetically favourable; glucose dissolves readily.

Cyclohexane. All C-H bonds, no polar functional groups. Only dispersion forces are available. To dissolve cyclohexane in water, water-water hydrogen bonds would have to be replaced by much weaker water-cyclohexane dispersion attractions. Energetically very unfavourable; cyclohexane is essentially insoluble.

Generalisation. Polar / hydrogen-bonding solutes dissolve in polar / hydrogen-bonding solvents (like dissolves like). The number and accessibility of polar groups on the solute, not its molar mass, predicts aqueous solubility for molecular substances.

Markers reward identification of OH groups on glucose, the hydrogen-bond donor-acceptor characterisation, and the explicit force-matching argument.

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