Year 12: Algebra

NSWMaths Standard 2Syllabus dot point

How are reciprocal functions used to model inverse variation, and what does the graph look like?

Model practical problems involving reciprocal functions and inverse variation of the form y=kxy = \frac{k}{x}

A focused answer to the HSC Maths Standard 2 dot point on reciprocal functions and inverse variation. Finding the constant of proportionality, graphing y=k/xy = k/x, identifying asymptotes, and applying to speed-time, pressure-volume and household budget problems with worked examples.

Generated by Claude OpusReviewed by Better Tuition Academy7 min answer

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What this dot point is asking

NESA wants you to recognise inverse variation in worded problems (speed-time at fixed distance, pressure-volume at fixed temperature, workers-hours for a fixed job), set up the reciprocal model y=kxy = \frac{k}{x}, find the constant of proportionality, and use the model to predict.

The answer

Direct vs inverse variation

  • Direct. yy doubles when xx doubles. Equation: y=kxy = k x.
  • Inverse. yy halves when xx doubles. Equation: y=kxy = \frac{k}{x}.

In inverse variation, the product xy=kx y = k is constant.

The reciprocal function

Reciprocal function y equals k over x with two branches A rectangular hyperbola with one branch in the first quadrant and a mirror branch in the third quadrant. Both axes are asymptotes; the curve approaches them but never touches. x y 0 y = k/x, k > 0 third quadrant branch first quadrant branch

y=kxy = \frac{k}{x}

  • For k>0k > 0: branches in the first and third quadrants.
  • For k<0k < 0: branches in the second and fourth quadrants.
  • Two asymptotes: the xx-axis (y=0y = 0) and the yy-axis (x=0x = 0).
  • The graph is a rectangular hyperbola.

Finding IMATH_19

Given one (x,y)(x, y) pair from the problem, compute

k=xy.k = x y.

Then write the full model and use it for other values.

Domain considerations

In a real-world problem, the variables are usually positive (speed cannot be negative, pressure cannot be zero), so you only use the first-quadrant branch. Always state the practical domain when the question asks for a graph.

Practical applications

  • Speed and time at fixed distance. t=dst = \frac{d}{s}. The constant is the trip distance.
  • Pressure and volume of a gas at fixed temperature (Boyle's Law). PV=kP V = k.
  • Workers and time for a fixed job. T=WnT = \frac{W}{n} where WW is total worker-hours and nn is number of workers.
  • Per-unit cost and number of units when total cost is fixed. Cost per pizza when splitting a \50order order nwaysis ways is \frac{50}{n}$.

Past exam questions, worked

Real questions from past NESA papers on this dot point, with our answer explainer.

2023 HSC Q233 marksThe time tt (in hours) for a car to travel 480480 km varies inversely as its speed ss (in km/h). Write the relationship and find the speed needed to complete the trip in 66 hours.
Show worked answer →

Inverse variation: t=kst = \frac{k}{s}.

The constant kk is total distance: k=ts=480k = t \cdot s = 480.

So t=480st = \frac{480}{s}.

For t=6t = 6: 6=480s6 = \frac{480}{s}, giving s=4806=80s = \frac{480}{6} = 80 km/h.

Markers reward the inverse variation form, the constant identified as 480480 km, and the speed.

2021 HSC Q233 marksThe pressure PP of a gas varies inversely as its volume VV. When V=5V = 5 litres, P=200P = 200 kPa. Find PP when V=8V = 8 litres.
Show worked answer →

Inverse variation: P=kVP = \frac{k}{V}.

Find kk from the given pair: 200=k5200 = \frac{k}{5}, so k=1000k = 1000.

Then P=1000VP = \frac{1000}{V}.

At V=8V = 8: P=10008=125P = \frac{1000}{8} = 125 kPa.

Markers reward identification of the inverse relationship, calculation of the constant kk, and the final pressure with units.

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