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NSWMaths Standard 2Syllabus dot point

How do we decide whether a real situation is best modelled by a linear, quadratic, exponential or reciprocal function?

Compare linear and non-linear models of real-world data and select the most appropriate model

A focused answer to the HSC Maths Standard 2 dot point on selecting an appropriate model. Identifying the shape of data from a table or scatterplot, the difference between constant, proportional, multiplicative and inversely proportional change, and worked Australian examples for choosing the right model.

Generated by Claude OpusReviewed by Better Tuition Academy7 min answer

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What this dot point is asking

NESA wants you to look at a table or graph of data and decide whether the underlying relationship is linear, quadratic, exponential or reciprocal. The diagnostic rules are simple and worth memorising.

The answer

Four standard model shapes

  • Linear y=mx+cy = m x + c. First differences (consecutive yy values subtracted) are constant.
  • Quadratic y=ax2+bx+cy = a x^2 + b x + c. First differences are not constant but second differences are.
  • Exponential y=abxy = a b^x. Ratios of consecutive yy values are constant (equal to bb).
  • Reciprocal y=kxy = \frac{k}{x}. Products xyx y are constant.

Diagnostic checklist

Given a table of (x,y)(x, y) pairs with xx equally spaced:

  1. Compute consecutive differences yi+1βˆ’yiy_{i+1} - y_i. If constant, linear.
  2. Compute consecutive ratios yi+1yi\frac{y_{i+1}}{y_i}. If constant, exponential.
  3. Compute products xyx y. If constant, reciprocal.
  4. If none of the above, try second differences for a quadratic, or try other forms.

Shape clues from a graph

  • Straight line. Linear.
  • Smooth curve through the origin, increasing faster and faster. Quadratic or exponential. Use the diagnostic to decide.
  • Curve rising sharply at first then flattening towards an asymptote on the right. Exponential decay if downward, or possibly a logarithm.
  • Two branches with both axes as asymptotes. Reciprocal.
  • Parabolic shape with one turning point. Quadratic.

Practical clues from context

  • Money charged per unit plus a flat fee: linear.
  • Compound growth or decay (interest, depreciation, population): exponential.
  • A fixed total split among a variable number of parts (fuel cost for a fixed trip, time for a fixed job): reciprocal.
  • Projectile or revenue-maximising problem: quadratic.

When two models could work

Sometimes a small dataset fits multiple models reasonably well. The question will normally guide you (for example, "the growth percentage is constant" tells you exponential). If asked to compare fit, plot residuals: the better model has smaller residuals across the dataset.

Past exam questions, worked

Real questions from past NESA papers on this dot point, with our answer explainer.

2022 HSC Q264 marksA table shows population data over five years. Year 00 has 10001000, year 11 has 11001100, year 22 has 12101210, year 33 has 13311331, year 44 has 14641464. Which model best fits, linear or exponential? Justify your answer and write the model.
Show worked answer β†’

For linear, check first differences: 1100βˆ’1000=1001100 - 1000 = 100, 1210βˆ’1100=1101210 - 1100 = 110, 1331βˆ’1210=1211331 - 1210 = 121, 1464βˆ’1331=1331464 - 1331 = 133. Differences are increasing, not constant, so not linear.

For exponential, check ratios: 11001000=1.10\frac{1100}{1000} = 1.10, 12101100=1.10\frac{1210}{1100} = 1.10, 13311210=1.10\frac{1331}{1210} = 1.10, 14641331β‰ˆ1.10\frac{1464}{1331} \approx 1.10. Ratios are constant at 1.101.10, so the model is exponential.

Model: P=1000(1.10)tP = 1000 (1.10)^t. This is 10%10\% growth per year.

Markers reward both first-difference and ratio checks, the conclusion that ratios are constant, and the model with correct base 1.101.10.

2021 HSC Q223 marksA table shows fuel cost for a trip of fixed length at different speeds. 4040 km/h costs \18,, 60km/hcosts km/h costs \1212, 8080 km/h costs \9,, 120km/hcosts km/h costs \66. What type of model fits this data?
Show worked answer β†’

Check the product of speed and cost: 40Γ—18=72040 \times 18 = 720, 60Γ—12=72060 \times 12 = 720, 80Γ—9=72080 \times 9 = 720, 120Γ—6=720120 \times 6 = 720.

The product is constant at 720720, so the relationship is inverse: cost Γ—\times speed =720= 720, that is C=720sC = \frac{720}{s}.

Markers reward checking the product, identifying it as constant, and writing the reciprocal model with the constant explicitly.

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