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NSWMaths Extension 1Proof (ME-P1)

Quick questions on Mathematical induction for series identities

10short Q&A pairs drawn directly from our worked dot-point answer. For full context and worked exam questions, read the parent dot-point page.

What is the principle of mathematical induction?
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The principle of mathematical induction lets you prove infinitely many statements at once from two finite checks. Let P(n)P(n) be a statement about a positive integer nn. If
What is the standard four-part structure?
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The four-part structure is the template every series proof must follow, and you should write each part with its own heading or label so the marker can tick them off.
What is common series formulas worth memorising?
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The four standard sum formulas come up constantly, both as the thing you must prove and as a result you can quote elsewhere:
What is the split-off-the-last-term technique?
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The technique that drives the inductive step is always the same: peel off the final term so the rest matches the hypothesis. In symbols,
What is part 1: Base case?
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Verify P(1)P(1) by substituting n=1n = 1 into both sides separately and checking they are equal. Compute the two sides independently; never assume they match.
What is part 2: Inductive hypothesis?
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Assume P(k)P(k) holds for some positive integer kk, and write the assumed identity out in full. This line is the fact you are allowed to use later, so make it explicit.
What is part 3: Inductive step?
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Prove P(k+1)P(k + 1) using the hypothesis. For a series, the move is mechanical: write the (k+1)(k + 1)-term sum as the kk-term sum plus the new last term, replace the kk-term sum by the formula the hypothesis gives, then simplify to the closed form with n=k+1n = k + 1 substituted.
What is part 4: Conclusion?
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State that since the base case holds and P(k)    P(k+1)P(k) \implies P(k + 1), by the principle of mathematical induction P(n)P(n) holds for all positive integers nn.
What is algebra errors in the step?
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Factoring out (k+1)(k + 1) then matching the target form is the reliable route. If the algebra is messy, write the target form for n=k+1n = k + 1 first and aim at it.
What is index confusion?
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i=1n\sum_{i = 1}^{n} runs from i=1i = 1 to i=ni = n. The (k+1)(k + 1)-term sum includes the term at i=k+1i = k + 1, which is exactly the new term you split off in the step.
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