Inquiry Question 1: How does mutation introduce new alleles into a population?
Investigate the causes of genetic variation relating to the changes and conservation of the DNA sequence including: the use of pedigree analysis to identify patterns of inheritance and mutation
A focused answer to the HSC Biology Module 6 dot point on pedigree analysis. How to identify autosomal recessive, autosomal dominant, X-linked recessive and X-linked dominant inheritance patterns from pedigree charts, with a worked haemophilia example and rules for spotting new mutations.
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What this dot point is asking
NESA wants you to read a pedigree chart, identify the inheritance pattern (autosomal recessive, autosomal dominant, X-linked recessive, X-linked dominant) and link the pattern to where the mutation occurred. New mutations and de novo events are a common twist.
The answer
Pedigree symbols
| Symbol | Meaning |
|---|---|
| Square | Male |
| Circle | Female |
| Filled | Affected |
| Half-filled | Carrier (sometimes shown) |
| Horizontal line between two shapes | Mating |
| Vertical line | Offspring |
| Diamond | Sex unknown |
Generations are labelled with Roman numerals (I, II, III), individuals within a generation with Arabic numerals (1, 2, 3).
Inheritance patterns
Autosomal dominant.
- Trait appears in every generation (no skipping).
- About 50 percent of offspring of an affected parent are affected.
- Both sexes affected equally.
- Affected father can pass to son (rules out X-linked).
- Example: Huntington disease, achondroplasia.
Autosomal recessive.
- Trait often skips generations (carriers are unaffected).
- Two unaffected carrier parents have 25 percent affected children.
- Both sexes affected equally.
- Often appears in offspring of consanguineous (related) parents.
- Example: cystic fibrosis, phenylketonuria, sickle cell anaemia.
X-linked recessive.
- Affects males more than females (males are hemizygous; one allele is enough).
- Affected father cannot pass the condition to sons (he passes Y), but all his daughters are carriers.
- Affected sons usually have a carrier mother.
- Can skip generations through unaffected carrier mothers.
- Example: haemophilia A and B, Duchenne muscular dystrophy, red-green colour blindness.
X-linked dominant.
- Affects both sexes but more females (they have two X chromosomes).
- Affected father transmits the trait to all daughters and no sons.
- No generational skipping.
- Example: fragile X syndrome (partly), incontinentia pigmenti.
Y-linked.
- Passed strictly father to son. Females never affected.
- Rare in syllabus questions but worth recognising.
Reading a pedigree: the decision tree
- Is the trait in every generation?
- Yes β likely dominant.
- No β likely recessive.
- Are males and females affected equally?
- Yes β likely autosomal.
- More males affected β likely X-linked recessive.
- All daughters of affected father affected β X-linked dominant.
- Does an affected father pass to a son?
- Yes β autosomal (rules out X-linked).
- No, with the rule "all daughters but no sons" β X-linked dominant.
- Consanguinity present? Increases the chance of autosomal recessive.
Worked example: haemophilia in the British royal family
Queen Victoria was a carrier (). Her son Leopold was affected (). Her daughters Alice and Beatrice were carriers and married into European royal houses, introducing haemophilia into the Spanish, Russian and Prussian royal families. The Russian Tsarevich Alexei was famously affected, contributing to the political instability that preceded the 1917 revolution.
The pedigree shows the classic X-linked recessive pattern: affected males, carrier females, no female-to-female transmission, and skipping through unaffected carriers.
Mutations on pedigrees
A trait may appear in a pedigree with no prior family history because of a de novo (new) mutation in a parental gamete or early in the embryo. Clues that suggest a de novo mutation:
- A single affected individual with no other family history and no consanguinity.
- A high-penetrance dominant condition that should be visible in the parents (e.g. achondroplasia, where roughly 80 percent of cases are de novo).
- An X-linked recessive condition (e.g. haemophilia) in a boy whose mother is not a known carrier.
Mosaicism is another explanation: a parent carries the mutation in only some of their gametes, so the mutation appears in only some of their children.
Examples in context
Example 1. Huntington's disease in a NSW family. Huntington's disease is an autosomal dominant disorder caused by an expansion of CAG repeats in the HTT gene on chromosome 4. A pedigree from a typical Hunter Valley family at the Royal North Shore neurogenetics clinic shows the disease appearing in every generation, affecting roughly half of offspring of each affected parent, and males and females equally. This pattern - vertical transmission, no skipping, no sex bias - is the classic signature of autosomal dominant inheritance. Genetic counsellors use the pedigree to estimate a 50 percent risk for each child of an affected parent and offer predictive genetic testing once the child is of legal age and capable of informed consent.
Example 2. Cystic fibrosis and the carrier-parent pedigree. Cystic fibrosis is autosomal recessive. In a typical pedigree presented at the Sydney Children's Hospital genetics clinic, two unaffected parents have an affected child, then have unaffected and affected siblings in roughly the 3:1 Mendelian ratio. The trait skips generations because carriers (heterozygotes) are phenotypically normal. Both parents must contribute the recessive allele, so both are obligate Aa carriers. The pedigree pattern - parents unaffected, child affected, no sex bias, often appearing in collateral relatives - confirms autosomal recessive inheritance, and counselling can offer prenatal testing for future pregnancies.
Try this
Q1. A pedigree shows a trait that affects only males, appears in every generation, and is passed from affected grandfathers to half of their grandsons through carrier daughters. Identify the inheritance pattern and justify your answer. [3 marks]
- Cue. X-linked recessive: only males affected, no male-to-male transmission, daughters are unaffected carriers.
Q2. In a pedigree of an autosomal recessive disorder, both parents are heterozygous carriers. They have four children. Calculate the probability that (a) exactly two children are affected, and (b) at least one child is affected. [2+2 marks]
- Cue. (a) Binomial: C(4,2) by (1/4) squared by (3/4) squared = 27/128. (b) 1 minus (3/4) to the fourth = 175/256.
Q3. A pedigree shows an unaffected mother and an unaffected father with an affected daughter. No relatives on either side have the disorder. (a) State why this is consistent with a new (de novo) autosomal dominant mutation. (b) Suggest two other inheritance patterns to consider before concluding it is de novo. (c) Describe a molecular test that could confirm a new mutation. [2+2+2 marks]
- Cue. (a) Trait appears with no carrier family history; both parents unaffected but child affected with dominant phenotype. (b) Autosomal recessive with both parents carriers; non-paternity. (c) Sequence the daughter and both parents - mutation present only in daughter confirms de novo.
Exam-style practice questions
Practice questions written in the style of NESA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
2025 HSC3 marksA pedigree shows the inheritance of CAMT, a rare inherited disorder, across a family. What type of inheritance is shown in the pedigree? Justify your answer.Show worked answer β
Name the precise inheritance pattern and justify with specific individuals/genotypes. Sample answer: Type of inheritance: autosomal recessive. Using B (unaffected) and b (affected): BB and Bb are unaffected, bb is affected. Individuals 8 and 9 are unaffected but have an affected child (17), so the allele must be recessive and inherited from both parents, making it autosomal. (If it were sex-linked, individual 15 would be expected to be affected.) For affected individual 10, both parents (3 heterozygous Bb, 4 homozygous recessive) must carry the recessive allele. Marks: 3 = identifies the type AND provides an appropriate justification; 2 = some understanding of the type; 1 = relevant information. Common error: writing 'recessive' rather than the full 'autosomal recessive', and using incorrect alleles/Punnett squares.
2023 HSC3 marksHuntington's disease is an autosomal dominant genetic disease. Using the pedigree, justify the genotype of individual 'H'. In your answer, refer to the letters on the pedigree to identify individuals.Show worked answer β
Deduce the genotype from the affected/unaffected status of H's children. Sample answer: Individual H must be heterozygous for the Huntington's gene (genotype Hh). This is because she has children who do not have Huntington's disease (J and L) and children who do (I and K). Since Huntington's is autosomal dominant, an affected person showing the trait must carry at least one H allele, but producing unaffected children means she must also carry the normal allele h - therefore Hh. Marks: 3 = justifies the correct genotype with reference to H's offspring; 2 = identifies possible genotypes for autosomal dominant inheritance; 1 = relevant information. Punnett squares were accepted as part of the justification. Common error: not identifying all possible genotypes and confusing dominant/recessive patterns.
2023 HSC3 marksDiagram 1 shows a pedigree of a family affected by Huntington's disease; Diagram 2 shows gel electrophoresis of chromosome-4 DNA fragments with the number of CAG repeats for each individual (P-V). Predict whether individuals S and U will be affected by Huntington's disease, and if so, at what age. Use data from the diagrams to justify your answer.Show worked answer β
Match each individual's CAG-repeat band to an affected/unaffected relative to predict outcome and onset. Sample answer: Individual S is not predicted to be affected. The gel shows S has a band at approximately 15 repeats, the same as his father P, who does not have the disease (normal range). Individual U will most likely develop Huntington's at around age 45. U has the same number of repeats (~38) as her mother Q, who has an age of onset of 45. (More CAG repeats - earlier onset; ~15 repeats is in the normal 10-26 range, while ~38 is in the disease 37-80 range.) Marks: 3 = predicts the outcome for BOTH S and U including age of onset, with justification from the data; 2 = predicts one individual with age of onset OR interprets the data; 1 = relevant information. Common error: not linking individuals' shared CAG repeats to predict age of onset.
Related dot points
- Assess the significance of 'coding' and 'non-coding' DNA segments in the process of mutation and investigate the effects of different mutations on a protein's amino acid sequence
A focused answer to the HSC Biology Module 6 dot point on how mutations alter protein products. Coding versus non-coding regions, silent missense and nonsense substitutions, frameshift consequences, splice-site mutations, and a worked sickle cell example.
- Explain how a range of mutagens operate, including but not limited to: electromagnetic radiation sources, chemicals, naturally occurring mutagens; and classify different types of mutation including point, silent, frameshift and chromosomal mutations
A focused answer to the HSC Biology Module 6 dot point on classifying mutations. Covers point mutations (substitution, insertion, deletion), silent vs missense vs nonsense, frameshift effects on reading frame, and chromosomal mutations (deletion, duplication, inversion, translocation, non-disjunction).