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How is credit card interest calculated, and how do the interest-free period and daily compounding affect the cost of using a credit card?

Calculate credit card interest using daily compounding, identify the interest-free period and the minimum monthly repayment

A focused answer to the HSC Maths Standard 2 dot point on credit card interest. Daily compounding from purchase date, the interest-free period if the balance is paid in full, the back-dating rule, the minimum-repayment trap, and worked Australian examples using typical RBA-published credit card interest rates.

Reviewed by: AI editorial process; not yet individually human-reviewed

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What this dot point is asking

NESA wants you to do four things. Work out credit card interest using daily compounding (interest added once a day). Explain the interest-free period. Apply the back-dating rule. And explain why paying only the minimum keeps a balance alive for years. Australian credit card rates sit around 1515-22%22\% per annum (per RBA statistics). That is far above home-loan rates, which is what makes carrying a balance so expensive.

The answer

How credit card interest works

A credit card charges a high annual interest rate (typically 1313-22%22\% in Australia, per RBA statistics). That rate is compounded daily (added to the balance each day) on any balance carried past the due date. Two features make a credit card behave differently from a normal loan: an interest-free period, and a back-dating rule that switches it off.

If you pay the full closing balance by the due date, you are charged no interest on purchases made in that statement period. This is the interest-free period. On most Australian cards it can be up to 4444 to 5555 days. That is because it runs from the purchase date all the way to the due date of the statement the purchase lands in. The timeline below shows how it works.

The interest-free period on a credit card A timeline from a purchase on 1 June, through the statement closing on 30 June, to the due date on 25 July. The stretch from purchase to due date is the interest-free period, up to 55 days. If the balance is paid in full by the due date, no interest is charged. If any amount is left unpaid, interest is back-dated to the original purchase date on the whole balance. 1 2 3 interest-free period: up to 55 days time 1 Jun purchase 30 Jun statement closes 25 Jul due date Paid in full by 25 Jul $0 interest on purchases in this statement period. Any amount left unpaid interest back-dated to 1 Jun, on the whole balance.

If even $1 is left unpaid, most cards charge interest from the original purchase date on the entire balance, not just the unpaid part. This is the back-dating rule, and it is the major trap. The interest-free period is a reward for paying in full, and it vanishes entirely the moment you do not.

Daily rate

Annual rate divided by 365365:

rday=R365.r_{\text{day}} = \frac{R}{365}.

A nominal 19.99%19.99\% per annum is a daily rate of 0.19993650.0005477\frac{0.1999}{365} \approx 0.0005477, or about 0.055%0.055\% per day.

Balance after nn days

Using compound interest with daily compounding:

A=P(1+rday)n.A = P(1 + r_{\text{day}})^n.

Interest charged is APA - P. Here nn is a count of actual calendar days, so read the dates carefully: from 11 June to 55 August is 6565 days, not "two months".

For short periods the result is close to simple interest I=PrdaynI = P r_{\text{day}} n. This is because over a few weeks the interest-on-interest (interest charged on interest already added) is tiny. But the compound formula is what NESA expects, unless the question clearly says "simple interest". A question that says "calculated daily" is a signal to use daily compounding.

Effective annual rate

A daily-compounded rate has a slightly higher effective annual rate than the nominal rate, because the interest itself earns interest through the year:

reff=(1+rday)3651.r_{\text{eff}} = (1 + r_{\text{day}})^{365} - 1.

A nominal 20%20\% gives an effective annual rate of (1+0.20/365)365122.1%(1 + 0.20/365)^{365} - 1 \approx 22.1\%. The headline rate understates the true annual cost.

Minimum monthly repayment

Cards usually require a minimum monthly repayment of about 22-3%3\% of the closing balance (or a small fixed amount such as $25, whichever is greater). The trap is just arithmetic. The monthly interest on a typical card is itself close to that same percentage. So the minimum payment barely clears more than the interest, and the balance falls at a crawl.

The chart below tracks a $5000 balance at 19%19\% per annum. Paying only the minimum, the balance is still about $3000 after ten years. Paying a fixed $200 a month instead clears the whole debt in under three years.

Paying only the minimum versus a fixed repayment on a credit card A line chart of a 5000 dollar credit card balance at 19 percent per annum over 10 years. The accent curve, paying only the 2 percent minimum each month, barely falls and is still around 3000 dollars after 10 years. The muted curve, paying a fixed 200 dollars a month, drops steeply and clears the debt in under 3 years. $1k $2k $3k $4k $5k 0 2 4 6 8 10 minimum only $200/month still ~$3,000 years balance owing ($) $5,000 at 19% p.a.: paying only the minimum, the balance is still ~$3,000 after 10 years.

Paying only the minimum means the balance reduces extremely slowly while interest keeps compounding, so the debt can persist for decades. Cards now legally have to print a minimum-repayment warning on every statement for exactly this reason.

Statement period

A typical statement period is one month. Interest is worked out daily on the balance and added to the account at the end of the statement period. That added interest then earns interest itself the next period. This is what makes it compounding rather than simple.

How exam questions ask about credit card interest

Each wording maps to one method:

  • "Calculate the interest charged on a balance of $X outstanding for nn days." Daily compounding: I=P((1+R/365)n1)I = P\left((1 + R/365)^n - 1\right).
  • "Find the new balance after nn days." A=P(1+R/365)nA = P(1 + R/365)^n; quote both AA and the interest APA - P if asked.
  • "A purchase is made on (date) and paid on (date)." Count the calendar days between the two dates for nn, and apply the back-dating rule if the balance was not paid in full by the due date.
  • "Identify / explain the interest-free period." From purchase date to the statement due date (up to about 5555 days), provided the closing balance is paid in full; no interest on those purchases.
  • "Find the minimum monthly repayment." A percentage (usually 22-3%3\%) of the closing balance, or a fixed floor, whichever is greater.
  • "Explain why paying only the minimum is expensive" or "how long to repay?" Compare the monthly interest with the minimum payment; most of the payment is interest, so the balance barely falls.
  • "What is the effective annual rate?" (1+R/365)3651(1 + R/365)^{365} - 1, slightly above the nominal rate.

Edge case: interest-free period versus a carried balance, side by side

Take the same $800 purchase from Part A, but suppose the cardholder pays the full closing balance by the 2525 July due date. Then the interest-free period applies and the interest charged is exactly $0, even though the money was effectively borrowed for over a month. But pay $799 and leave just $1 unpaid, and the back-dating rule kicks in. Interest is charged from 11 June on the whole $800, not on the $1 shortfall. So leaving a single dollar unpaid can change the interest from $0 to tens of dollars. This all-or-nothing feature is the single most important thing to understand about credit cards, and a favourite exam "explain why" prompt.

Exam-style practice questions

Practice questions written in the style of NESA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

2023 HSC-style3 marksA credit card charges 19.99%19.99\% per annum interest, calculated daily and added monthly. Find the interest charged on a balance of $1500 outstanding for the full 3030 days of a statement period.
Show worked answer →

Daily rate: r=0.19993650.0005477r = \frac{0.1999}{365} \approx 0.0005477.

Interest over 3030 days using daily compounding:

I=1500((1.0005477)301)1500(1.016561)1500×0.0165624.84I = 1500((1.0005477)^{30} - 1) \approx 1500(1.01656 - 1) \approx 1500 \times 0.01656 \approx 24.84, i.e. $24.84.

Markers reward the per-day rate, the compound formula (not simple interest), and the answer to cents. Half marks if simple interest is used, since the question says "calculated daily".

2021 HSC-style4 marksA credit card has an annual interest rate of 21.5%21.5\% compounded daily. On 1 May, the opening balance is $2400. No payments are made for 4040 days. Find the new balance and the interest charged.
Show worked answer →

Daily rate: r=0.2153650.0005890r = \frac{0.215}{365} \approx 0.0005890.

Balance after 4040 days: A=2400(1.0005890)40A = 2400(1.0005890)^{40}.

(1.0005890)401.02383(1.0005890)^{40} \approx 1.02383.

A2400×1.023832457.20A \approx 2400 \times 1.02383 \approx 2457.20, i.e. $2457.20.

Interest: 2457.202400=57.202457.20 - 2400 = 57.20, i.e. $57.20.

Markers reward the daily rate, the compound formula over the right number of days, and both the new balance and the interest as a separate figure.

Practice questions

Original practice questions graded from foundation to exam level, each with a full worked solution. Try them before revealing the solution.

foundation2 marksA credit card charges 22%22\% per annum, calculated daily and added monthly. A balance of $1200 is carried for the full 2828 days of a statement period. (a) Find the daily interest rate as a decimal, to 77 decimal places. (b) Find the interest charged over the 2828 days.
Show worked solution →

Find the daily rate. Credit card interest accrues daily, so divide the annual rate by 365365:

rday=0.223650.0006027.r_{\text{day}} = \frac{0.22}{365} \approx 0.0006027.

Apply daily compounding for 2828 days. Use A=P(1+rday)nA = P(1 + r_{\text{day}})^n with P=1200P = 1200 and n=28n = 28:

A=1200×(1.0006027)281200×1.017011220.42.A = 1200 \times (1.0006027)^{28} \approx 1200 \times 1.01701 \approx 1220.42.

The interest is AP=1220.421200=20.42A - P = 1220.42 - 1200 = 20.42, i.e. $20.42.

Check. Over only 2828 days the simple-interest estimate 1200×0.0006027×2820.251200 \times 0.0006027 \times 28 \approx 20.25 is very close, confirming the figure of about $20.42 is the right size.

foundation2 marksMia buys a $540 textbook bundle on her credit card on 88 March. The statement closes on 3131 March and the due date is 2525 April. The card has an annual rate of 19.99%19.99\%. Mia pays the full closing balance on 2525 April and makes no other purchases. (a) How many days pass between the purchase and the due date? (b) How much interest is she charged on the purchase, and why?
Show worked solution →

Count the days from purchase to due date. From 88 March to 3131 March is 2323 days, then a further 2525 days to 2525 April:

23+25=48 days.23 + 25 = 48 \text{ days}.

So the purchase sits on the card for 4848 days.

Apply the interest-free rule. Because Mia pays the full closing balance by the due date, the interest-free period applies to purchases in that statement period. No interest is charged, even though the $540 was effectively borrowed for 4848 days.

Interest charged=0.\text{Interest charged} = 0.

Check. The interest-free period runs from the purchase date to the due date, here 4848 days, which is within the usual 4444 to 5555 day window, so paying in full means $0 interest.

foundation2 marksA credit card has an annual interest rate of 18.49%18.49\%, calculated daily. A balance of $980980 is left unpaid and carried for 1414 days. Find the interest charged over those 1414 days.
Show worked solution →

Find the daily rate. Credit card interest accrues daily, so divide the annual rate by 365365:

rday=0.18493650.0005066.r_{\text{day}} = \frac{0.1849}{365} \approx 0.0005066.

Apply daily compounding for 1414 days. Use A=P(1+rday)nA = P(1 + r_{\text{day}})^n with P=980P = 980 and n=14n = 14:

A=980×(1.0005066)14980×1.00712986.97.A = 980 \times (1.0005066)^{14} \approx 980 \times 1.00712 \approx 986.97.

The interest is AP=986.97980=6.97A - P = 986.97 - 980 = 6.97, i.e. $6.97.

Check. Over just 1414 days the simple-interest estimate 980×0.0005066×146.95980 \times 0.0005066 \times 14 \approx 6.95 is very close, confirming about $6.97 is the right size.

Answer: The interest charged is approximately $6.97.

foundation2 marksA store credit card charges 23.99%23.99\% per annum, calculated daily. A balance of $760760 is carried for the full 3030 days of a statement period with no repayment. (a) Find the daily interest rate as a percentage, to 22 decimal places. (b) Find the interest charged over the 3030 days.
Show worked solution →

Find the daily rate. Divide the annual rate by 365365:

rday=0.23993650.0006573.r_{\text{day}} = \frac{0.2399}{365} \approx 0.0006573.

As a percentage this is about 0.07%0.07\% per day.

Apply daily compounding for 3030 days. Use A=P(1+rday)nA = P(1 + r_{\text{day}})^n with P=760P = 760 and n=30n = 30:

A=760×(1.0006573)30760×1.01991775.13.A = 760 \times (1.0006573)^{30} \approx 760 \times 1.01991 \approx 775.13.

The interest is AP=775.13760=15.13A - P = 775.13 - 760 = 15.13, i.e. $15.13.

Check. The simple-interest estimate 760×0.0006573×3014.99760 \times 0.0006573 \times 30 \approx 14.99 is close to $15.13, so the figure is the right size. Store cards charge a high rate, so a small balance still costs over $1515 in a month.

Answer: The daily rate is about 0.07%0.07\% and the interest charged is approximately $15.13.

core3 marksA $1450 purchase is made on a credit card on 33 February 2026. The due date is 2828 March and the cardholder does not pay until 1212 April 2026, having paid nothing by the due date. The annual rate is 19.49%19.49\% compounded daily. (20262026 is not a leap year.) Find the interest charged and the amount finally owing.
Show worked solution →

Apply the back-dating rule to find the number of days. Because nothing was paid by the due date, interest runs from the original purchase date of 33 February. Counting calendar days, 33 to 2828 February is 2525 days (February has 2828 days in 20262026), plus 3131 days in March, plus 1212 days in April:

25+31+12=68 days.25 + 31 + 12 = 68 \text{ days}.

Convert the annual rate to a daily rate.

rday=0.19493650.0005340.r_{\text{day}} = \frac{0.1949}{365} \approx 0.0005340.

Compound the balance over 6868 days. Use A=P(1+rday)nA = P(1 + r_{\text{day}})^n:

A=1450×(1.0005340)681450×1.036971503.60.A = 1450 \times (1.0005340)^{68} \approx 1450 \times 1.03697 \approx 1503.60.

The interest is 1503.601450=53.601503.60 - 1450 = 53.60, i.e. $53.60.

Check. February has 2828 days in 20262026 (not 3030), so the day count is 6868; the amount owing is about $1503.60 with $53.60 of interest.

core3 marksA cardholder carries a balance of $2750 at 20.99%20.99\% per annum compounded daily. No purchases and no repayments are made for 3131 days. Find the new balance and state the interest charged as a separate figure.
Show worked solution →

Convert the annual rate to a daily rate.

rday=0.20993650.0005751.r_{\text{day}} = \frac{0.2099}{365} \approx 0.0005751.

Compound the balance over 3131 days. Use A=P(1+rday)nA = P(1 + r_{\text{day}})^n with P=2750P = 2750 and n=31n = 31:

A=2750×(1.0005751)312750×1.017982799.45.A = 2750 \times (1.0005751)^{31} \approx 2750 \times 1.01798 \approx 2799.45.

State both figures. The new balance is approximately $2799.45, and the interest charged is 2799.452750=49.452799.45 - 2750 = 49.45, i.e. $49.45.

Check. A simple-interest estimate 2750×0.0005751×3149.042750 \times 0.0005751 \times 31 \approx 49.04 is close to $49.45, confirming the new balance of about $2799.45 is right.

core3 marksA credit card advertises a nominal annual rate of 17.99%17.99\% compounded daily. (a) Explain why the effective annual rate is higher than the nominal rate. (b) Find the effective annual rate, correct to two decimal places.
Show worked solution →

Explain the difference. With daily compounding the interest charged each day is itself added to the balance, so it earns interest for the rest of the year. This interest-on-interest means the true yearly cost, the effective annual rate, is a little above the headline nominal rate.

Write the daily rate.

rday=0.17993650.0004929.r_{\text{day}} = \frac{0.1799}{365} \approx 0.0004929.

Apply the effective-rate formula over a full year. Use reff=(1+rday)3651r_{\text{eff}} = (1 + r_{\text{day}})^{365} - 1:

reff=(1.0004929)36511.19701=0.1970.r_{\text{eff}} = (1.0004929)^{365} - 1 \approx 1.1970 - 1 = 0.1970.

As a percentage this is about 19.70%19.70\%.

Check. The effective rate 19.70%19.70\% is slightly above the nominal 17.99%17.99\%, as expected for daily compounding, so the headline rate understates the real annual cost.

core3 marksA cardholder carries a balance of $31803180 at 19.74%19.74\% per annum compounded daily and makes no payments for 4545 days. (a) Find the new balance and the interest charged. (b) What percentage of the new balance is interest, to one decimal place?
Show worked solution →

Convert the annual rate to a daily rate.

rday=0.19743650.0005408.r_{\text{day}} = \frac{0.1974}{365} \approx 0.0005408.

Compound the balance over 4545 days. Use A=P(1+rday)nA = P(1 + r_{\text{day}})^n with P=3180P = 3180 and n=45n = 45:

A=3180×(1.0005408)453180×1.024633258.32.A = 3180 \times (1.0005408)^{45} \approx 3180 \times 1.02463 \approx 3258.32.

The interest is 3258.323180=78.323258.32 - 3180 = 78.32, i.e. $78.32.

Find the interest as a percentage of the new balance. Divide the interest by the new balance:

78.323258.32×1002.4%.\frac{78.32}{3258.32} \times 100 \approx 2.4\%.

Check. The simple-interest estimate 3180×0.0005408×4577.393180 \times 0.0005408 \times 45 \approx 77.39 is close to $78.32, confirming the new balance of about $3258.32.

Answer: The new balance is approximately $3258.32 with $78.32 of interest, about 2.4%2.4\% of the balance.

exam5 marksSam spends $2200 on a credit card on 11 May 2026. The statement closes on 3131 May and the due date is 2525 June. The annual rate is 20.74%20.74\% compounded daily. (a) Find the interest if Sam pays the full closing balance by 2525 June. (b) Find the interest if Sam instead pays nothing by the due date, assuming interest is back-dated to the purchase date and charged up to 2525 June. (c) Use the two answers to explain the back-dating trap.
Show worked solution →

Part (a): apply the interest-free rule. Paying the full closing balance by the due date triggers the interest-free period on purchases in that statement period, so

Interest=0.\text{Interest} = 0.

Part (b): count the days from the purchase date. With nothing paid by the due date, interest is back-dated to 11 May. From 11 May to 3131 May is 3030 days, plus 2525 days to 2525 June:

30+25=55 days.30 + 25 = 55 \text{ days}.

Convert the annual rate to a daily rate.

rday=0.20743650.0005682.r_{\text{day}} = \frac{0.2074}{365} \approx 0.0005682.

Compound the full balance over 5555 days. The back-dating rule charges interest on the whole $2200:

A=2200×(1.0005682)552200×1.031742269.82.A = 2200 \times (1.0005682)^{55} \approx 2200 \times 1.03174 \approx 2269.82.

The interest is 2269.822200=69.822269.82 - 2200 = 69.82, i.e. $69.82.

Part (c): explain the trap. Paying in full costs $0, but missing the due date costs about $69.82 because interest is charged from the purchase date on the entire balance, not just on any unpaid part. The interest-free period is all-or-nothing: it is a reward for paying in full and vanishes the moment any amount is left unpaid.

Check. The day count 5555 lies in the usual 4444 to 5555 day window, and the difference between the two scenarios is the full $69.82, which is the whole interest charge.

exam5 marksA $4200 credit card balance has an annual rate of 21.99%21.99\%. Interest is charged monthly at R12\frac{R}{12} and the minimum repayment is the greater of 2.5%2.5\% of the opening balance or $30. No further purchases are made and only the minimum is paid each month. Each month, add the interest then subtract the payment. Find the closing balance after 33 months and comment on what this shows.
Show worked solution →

Find the monthly interest rate. Divide the annual rate by 1212:

0.2199120.018325.\frac{0.2199}{12} \approx 0.018325.

Work through month 11. Interest is 4200×0.01832576.974200 \times 0.018325 \approx 76.97. The minimum is 2.5%2.5\% of $4200, i.e. 0.025×4200=105.000.025 \times 4200 = 105.00, which is more than $30, so the payment is $105.00.

Closing1=4200+76.97105.00=4171.97.\text{Closing}_1 = 4200 + 76.97 - 105.00 = 4171.97.

Work through month 22. Interest is 4171.97×0.01832576.454171.97 \times 0.018325 \approx 76.45. The minimum is 0.025×4171.97104.300.025 \times 4171.97 \approx 104.30.

Closing2=4171.97+76.45104.30=4144.12.\text{Closing}_2 = 4171.97 + 76.45 - 104.30 = 4144.12.

Work through month 33. Interest is 4144.12×0.01832575.944144.12 \times 0.018325 \approx 75.94. The minimum is 0.025×4144.12103.600.025 \times 4144.12 \approx 103.60.

Closing3=4144.12+75.94103.60=4116.46.\text{Closing}_3 = 4144.12 + 75.94 - 103.60 = 4116.46.

Comment. After three months the balance has fallen from $4200 to only about $4116.46, a drop of roughly $84, because most of each payment is swallowed by interest. Paying only the minimum keeps the debt alive for years.

Check. The month 11 net reduction is 105.0076.97=28.03105.00 - 76.97 = 28.03, so $28.03; three roughly equal monthly reductions of about $28 give a total near $84, matching the closing balance of about $4116.46.

exam5 marksPriya buys a $17501750 laptop on her credit card on 1212 August 2026. The statement closes on 3131 August and the due date is 2525 September. The annual rate is 22.49%22.49\% compounded daily. (a) State the interest charged if Priya pays the full closing balance by 2525 September, and give the length of the interest-free period in days. (b) Instead, Priya pays nothing by the due date and clears the card on 1010 October, so interest is back-dated to the purchase date. Find the interest charged. (c) Explain what part (b) shows about leaving any balance unpaid.
Show worked solution →

Part (a): apply the interest-free rule. Paying the full closing balance by the due date triggers the interest-free period on purchases in that statement period, so

Interest=0.\text{Interest} = 0.

The interest-free period runs from the purchase date to the due date. From 1212 August to 3131 August is 1919 days, plus 2525 days to 2525 September:

19+25=44 days.19 + 25 = 44 \text{ days}.

Part (b): count the days from the purchase date. With nothing paid by the due date, interest is back-dated to 1212 August. From 1212 August to 3131 August is 1919 days, plus 3030 days in September, plus 1010 days in October:

19+30+10=59 days.19 + 30 + 10 = 59 \text{ days}.

Convert the annual rate to a daily rate.

rday=0.22493650.0006162.r_{\text{day}} = \frac{0.2249}{365} \approx 0.0006162.

Compound the full balance over 5959 days. The back-dating rule charges interest on the whole $17501750:

A=1750×(1.0006162)591750×1.037011814.77.A = 1750 \times (1.0006162)^{59} \approx 1750 \times 1.03701 \approx 1814.77.

The interest is 1814.771750=64.771814.77 - 1750 = 64.77, i.e. $64.77.

Part (c): explain the trap
Paying in full costs $0, but missing the due date costs about $64.77 because interest is charged from the purchase date on the entire balance, not just on any unpaid part. The interest-free period is a reward for paying in full and disappears the moment any amount is carried.
Check
The interest-free window of 4444 days lies inside the usual 4444 to 5555 day range, and the $64.77 charge is the whole cost of losing it.
Answer
(a) $0 interest, with a 4444 day interest-free period. (b) about $64.77. (c) leaving any balance unpaid back-dates interest to the purchase date on the full amount.
exam5 marksA $36003600 credit card balance has an annual rate of 20.49%20.49\%. Interest is charged monthly at R12\frac{R}{12} and the minimum repayment is the greater of 2%2\% of the opening balance or $2525. No further purchases are made and only the minimum is paid each month. Each month, add the interest then subtract the payment. (a) Find the closing balance after 22 months. (b) Find the net reduction in the balance in each month and explain why the balance falls so slowly.
Show worked solution →

Find the monthly interest rate. Divide the annual rate by 1212:

0.2049120.017075.\frac{0.2049}{12} \approx 0.017075.

Work through month 11. Interest is 3600×0.01707561.473600 \times 0.017075 \approx 61.47. The minimum is 2%2\% of $36003600, i.e. 0.02×3600=72.000.02 \times 3600 = 72.00, which is more than $2525, so the payment is $72.00.

Closing1=3600+61.4772.00=3589.47.\text{Closing}_1 = 3600 + 61.47 - 72.00 = 3589.47.

Work through month 22. Interest is 3589.47×0.01707561.293589.47 \times 0.017075 \approx 61.29. The minimum is 0.02×3589.4771.790.02 \times 3589.47 \approx 71.79.

Closing2=3589.47+61.2971.79=3578.97.\text{Closing}_2 = 3589.47 + 61.29 - 71.79 = 3578.97.

Part (b): find each net reduction. Subtract the interest from the payment each month:

Month 1:72.0061.47=10.53,Month 2:71.7961.29=10.50.\text{Month } 1: 72.00 - 61.47 = 10.53, \qquad \text{Month } 2: 71.79 - 61.29 = 10.50.

So the balance falls by only about $10.53 then $10.50, a total near $21 over two months.

Explain
Almost all of each minimum payment is swallowed by interest, leaving barely $1010 to clear the actual debt. Because the balance and the 2%2\% minimum both shrink together, the progress only slows, so paying the minimum keeps the debt alive for years.
Check
Closing after two months is about $3578.97, a drop of 36003578.97=21.033600 - 3578.97 = 21.03, matching the two net reductions of about $10.5010.50 each.
Answer
(a) the closing balance is approximately $3578.97. (b) net reductions of about $10.53 and $10.50, because most of each payment covers interest.
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